1 Tinh 89/16+25(9/16÷125/64)÷(-27/8)
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\(\frac{25}{4}+\frac{225}{16}:\frac{-3375}{512}\)
\(\frac{25}{4}+\frac{-32}{15}\)
\(=\frac{247}{60}\)
=\(\frac{89}{15}+25(-\frac{81}{64}):\frac{27}{8}\)
=\(\frac{89}{15}+(-\frac{2025}{64}):\frac{27}{8} \)
=\(\frac{89}{15}+(-\frac{75}{8})\)
=\(-\frac{89}{24}\)
\(\frac{89}{15}\)+ 25 \((\) \(\frac{36}{64}\)\(-\)\(\frac{117}{64}\)\()\). \(\frac{8}{27}\)
= \(\frac{89}{15}\)+ 25 \((\)\(\frac{-81}{64}\)\()\)\(\frac{8}{27}\)
= \(\frac{89}{15}\)+ 25 . \((\)\(\frac{-3}{8}\)\()\)
= \(\frac{89}{15}\)+ \(\frac{-75}{8}\)
= \(\frac{-413}{120}\)
Nếu đúng cho mình xin 1 k nhé
\(4\dfrac{25}{16}+25\left(\dfrac{9}{16}:\dfrac{125}{64}:\dfrac{-27}{8}\right)\)
\(=\dfrac{89}{16}+25\left(\dfrac{36}{125}:\dfrac{-27}{8}\right)\)
\(=\dfrac{89}{16}+25.\dfrac{-32}{375}\)
\(=\dfrac{89}{16}+\dfrac{-32}{15}=\dfrac{823}{240}\)
Chúc bạn học tốt!
\(4\dfrac{25}{16}+25\left(\dfrac{9}{16}:\dfrac{125}{64}:-\dfrac{27}{8}\right)\)
= \(\dfrac{89}{16}+25\left(\dfrac{9}{16}.\dfrac{64}{125}:-\dfrac{27}{8}\right)\)
= \(\dfrac{89}{16}+25\left(\dfrac{36}{125}:-\dfrac{27}{8}\right)\)
= \(\dfrac{89}{16}+25\left(\dfrac{36}{125}.-\dfrac{8}{27}\right)\)
= \(\dfrac{89}{16}+25.-\dfrac{32}{375}\)
\(=\dfrac{89}{16}+-\dfrac{32}{15}\)
= \(\dfrac{823}{240}\)
a, 410. 230=220.230=250
b,925.274.813= 350.312.312=374
Tương tự các câu khác....
a, 410.230 = (22)10.230 = 220.230 = 250
b, 925.274.813 = (32)25.(33)4.(34)3 = 350.312.312 = 374
c, 2550.1255 = (52)50.(53)5 = 5100.515 = 5115
d, 643.48.164 = (26)3.(22)8.(24)4 = 218.216.216 = 250
e, 38 : 36 = 32
210 : 83 = 210 : (23)3 = 210 : 29 = 2
127 : 67 = (12 : 6)7 = 27
@Dương Tuyết Mai
KQ là \(-\frac{61}{16}\)
mk ko bít bạn có cần lời giải ko mk chỉ vít kq hoi
có j nếu cần lời giải ns mk ha
\(4\frac{25}{16_{ }}+25.\left(\frac{9}{16}-\frac{117}{64}\right):\frac{27}{8}\)
=\(\frac{25}{4}+25.\left(\frac{36}{64}-\frac{117}{64}\right):\frac{27}{8}\)
=\(\frac{25}{4}+25.\left(\frac{-81}{64}\right):\frac{28}{7}\)
=\(\frac{25}{4}+\left(\frac{-2025}{64}\right).\frac{7}{28}\)
=\(\frac{25}{4}+\left(\frac{-2025}{256}\right)\)
=\(\frac{1600}{256}-\frac{2025}{256}\)
=\(\frac{-425}{256}\)
bn xem có đúng k nhé!
1, \(81\cdot27^3\cdot243^5=3^4\cdot3^9\cdot3^{25}=3^{38}\)
2,\(25^4\cdot125^3\cdot625^7=5^8\cdot5^9\cdot5^{28}=5^{45}\)
3,
\(16^3\cdot8^9\cdot64^5\cdot1024=2^{12}\cdot2^{27}\cdot2^{30}\cdot2^{10}=2^{79}\)
a) 25x² - 16
= (5x)² - 4²
= (5x - 4)(5x + 4)
b) 16a² - 9b²
= (4a)² - (3b)²
= (4a - 3b)(4a + 3b)
c) 8x³ + 1
= (2x)³ + 1³
= (2x + 1)(4x² - 2x + 1)
d) 125x³ + 27y³
= (5x)³ + (3y)³
= (5x + 3y)(25x² - 15xy + 9y²)
e) 8x³ - 125
= (2x)³ - 5³
= (2x - 5)(4x² + 10x + 25)
g) 27x³ - y³
= (3x)³ - y³
= (3x - y)(9x² + 3xy + y²)
a) \(25x^2-16=\left(5x-4\right)\left(5x+4\right)\)
b) \(16a^2-9b^2=\left(4a-3b\right)\left(4a+3b\right)\)
c) \(8x^3+1=\left(2x+1\right)\left(4x^2-2x+1\right)\)
d) \(125x^3+27y^3=\left(5x+3y\right)\left(25x^2-15xy+9y^2\right)\)
e) \(8x^3-125=\left(2x-5\right)\left(4x^2-10x+25\right)\)
g) \(27x^3-y^3=\left(3x-y\right)\left(9x^2+3xy+y^2\right)\)
1 Tinh
89/16+25(9/16÷125/64)÷(-27/8)
= \(\frac{89}{16}+25\left(\frac{9}{16}:\frac{125}{64}\right):-\frac{27}{8}\)
=\(\frac{89}{16}+\frac{25.36}{125}:-\frac{27}{8}\)
=\(\frac{89}{16}-\frac{32}{15}=\frac{823}{240}\)
\(\frac{89}{16}+25.\left(\frac{9}{16}:\frac{125}{64}\right):\left(\frac{-27}{8}\right)\)
=\(\frac{89}{16}+25.\frac{36}{125}:\left(\frac{-27}{8}\right)\)
=\(\frac{89}{16}+\frac{36}{5}:\left(\frac{-27}{8}\right)\)
=\(\frac{89}{16}+\left(\frac{-32}{15}\right)\)
=\(\frac{823}{240}\)