A=15^3.45^4:25^2.9^4
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\(A=5.4^{15}.9^9-4.3^{20}.8^9\\ =5.2^{30}.3^{18}-3^{20}.2^{29}\\ B=5.2^9.6^{19}-7.2^{29}.27^6\\=5.2^{28}.3^{19}-7.2^{^{29}}.3^{18}\\ \Rightarrow A:B=\left(5.2^{30}.3^{18}-3^{20}.2^{29}\right):\left(5.2^{28}.3^{19}-7.2^{^{29}}.3^{18}\right)\\ =\dfrac{2^2-3^2}{3-7}=\dfrac{4-9}{-4}=\dfrac{5}{4}\)
A=\(2^2-9^3+4^{-2}.16-2.5^2\)
\(=4-729+1-50=-774\)
B=\(\left(2^3.2\right).\dfrac{1}{2}+3^{-2}.3^2-7.1+5\)
\(B=2^4.\dfrac{1}{2}+1-7+5=8+1-7+5=7\)
C = 2-3 + (52)3.5-3 + 4-3.16 - 2.32 - 105.(\(\dfrac{24}{51}\))0
C = \(\dfrac{1}{8}\) + 56.5-3 + 4-3.42 - 2.9 - 105.1
C = \(\dfrac{1}{8}\) + 53 + \(\dfrac{1}{4}\) - 18 - 105
C = (\(\dfrac{1}{8}\) + \(\dfrac{1}{4}\)) - (105 - 125 + 18)
C = \(\dfrac{3}{8}\) - (-20 + 18)
C = \(\dfrac{3}{8}\) + 2
C = \(\dfrac{19}{8}\)
\(\frac{2^{13}.3^7}{2^{15}.3^2.9^2}=\frac{2^{13}.3^7}{2^{15}.3^6}=\frac{3}{4}\)
\(\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^{15}.3^8}{3^6.2^{15}}=3^2=9\)
\(x-3,45=\frac{90,5}{15}=\frac{181}{30}\)
=> \(x=\frac{181}{30}+3,45=\frac{569}{60}\)
x - 3 . 45 = 90 . 5 : 15
x - 135 = 450 : 15
x - 135 = 30
x = 30 + 135
x = 165
Vậy x = 165
\(\frac{15^3.45^4}{25^{2.}.9^4}=\frac{3.5.3.5.3.5.5.9.5.9.5.9.5.9}{5.5.5.5.3.3.3.3.3.3.3.3}=\frac{5^{3.}.9.3}{1}=3375\)
A=153.454:252.94
A=153.454:252.(92)2
A=153.454:252.812
A=153.454:(25x81)2
A=153.454:20252
A=153.(452)2:20252
A=153.20252:20252
A=153.1
A=153
Vậy A=153