Giúp em:1+2+3+...+x=105
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a,\(\left(x+1\right)+\left(x+2\right)+...+\left(x+25\right)=925\)
\(< =>25x+325=925< =>x=\frac{600}{25}=24\)
b,\(10-11+12-13+14-...-105+106-107+108\)
\(=\left(-1\right)+\left(-1\right)+...+\left(-1\right)+108\)\(=-49+108=59\)
a (x+1)+(x+2)+...+(x+25)=925
=>25x+(1+2+3+...25)=925
=>25x+(25+1)/2*25=925
=>25x+325=925
=>25x=600
=>x=600/25=24
b 10-11+12-13+14-...-105+106-107+108
=(10-11)+(12-13)+(14-15)+...+(104-105)+(106-107)+108
=(-1)+(-1)+(-1)+...+(-1)+(-1)+108
=108-49=59
\(A=3^x+3^{x+1}+...+3^{x+100}\)
=>\(3A=3^{x+1}+3^{x+2}+...+3^{x+101}\)
=>\(2A=3^{x+101}-3^x\)
=>\(A=\dfrac{3^{x+101}-3^x}{2}\)
=>\(3^{x+101}-3^x=3^{105}-3^4\)
=>x=4
câu a :
\(\left(x-\dfrac{1}{3}\right)^2-\dfrac{1}{2}=1\dfrac{3}{4}\\ \left(x-\dfrac{1}{3}\right)^2-\dfrac{1}{2}=\dfrac{7}{4}\\ \left(x-\dfrac{1}{3}\right)^2=\dfrac{1}{4}+\dfrac{1}{2}\\ \left(x-\dfrac{1}{3}\right)^2=\dfrac{9}{4}\\ x-\dfrac{1}{3}=\sqrt{\dfrac{9}{4}}\\ x-\dfrac{1}{3}=\dfrac{3}{2}\\ x=\dfrac{3}{2}+\dfrac{1}{3}\\ x=\dfrac{11}{6}\)
câu b :
\(\dfrac{x-3}{-2}=\dfrac{-8}{x-3}\\ \Rightarrow\left(x-3\right)\cdot\left(x-3\right)=\left(-2\right)\cdot\left(-8\right)\\ \Rightarrow\left(x-3\right)^2=16\\ x-3=\sqrt{16}\\ x-3=4\\ x=4+3\\ x=7\)
câu c :
\(\dfrac{9}{x}=\dfrac{-35}{105}\\ \Rightarrow\left(-35\right)\cdot x=9\cdot105\\ \left(-35\right)\cdot x=945\\ x=945\div\left(-35\right)\\ x=-27\)
15 - 2x = 11
=> 2x = 15 - 11
=> 2x = 4
=> x = 4 : 2 = 2
3.(x - 9) + 15 = 81
=> 3x - 27 = 81 - 15
=> 3x - 27 = 66
=> 3x = 66 + 27
=> 3x = 93
=> x = 93 : 3 = 31
a) 15 - 2.x = 11
2.x = 4
x = 2
b) 3. (x - 9) + 15 = 81
3. (x - 9) = 66
x - 9 = 22
x = 31
c) (x+1)+(x+2)+...+(x+10)= 105
(x+x+....+x) + (1+2+....+10) = 105
x . 10 + 55 = 105
x . 10 = 50
x = 5
C = 3 - 1 + 4 - 1 + 5 - 1 + .... + 102 - 1 + 103 - 1
= 2 + 3 + 4 + ... + 101 + 102
Số số hạng là : (102 - 2) : 1 + 1 = 100 (số hạng)
Tổng : (102 + 2) . 100 : 2 = 5200
Vậy C = 5200
=>2/x(x+2)+2/(x+2)(x+4)+...+2/(x+6)(x+8)=8/105
=>1/x-1/x+2+1/x+2-1/x+4+...+1/x+6-1/x+8=8/105
=>\(\dfrac{1}{x}-\dfrac{1}{x+8}=\dfrac{8}{105}\)
=>x(x+8)=105
=>x^2+8x-105=0
=>(x+15)(x-7)=0
=>x=7 hoặc x=-15