Hãy điền các số 3,4,5,6,7,8,9,10,11 vào bảng 3 * 3 sao cho bảng đó trở thành một hình vuông kỳ diệu hình vuông có tổng các số điền ở các ô vuông trên mỗi hàng , mỗi cột và các đường chéo đều bằng nhau.
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mình cũng có câu hỏi như thế mình cũng học cô loan mà đúng không bà là cẩm thanh mà bà cũng học cô loan mà
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http://www.olm.vn/hoi-dap/question/95083.html
có người làm rùi mà
Tổng các số ở trong bảng là : 1 + (–1) + 2 + (–2) + 3 + (–3) + 0 + 4 + 5 = 9.
Tổng các số trên mỗi hàng, mỗi cột bằng nhau nên tổng các số ở mỗi hàng, mỗi cột bằng : 9 : 3 = 3.
Do đó: 5 + 0 + (c) = 3, suy ra (c) = 3 – 0 – 5 = –2.
4 + (e) + (c) = 3, suy ra (e) = 3 – 4 – (c) = 3 – 4 – (–2) = 1.
5 + (d) + (e) = 3, suy ra (d) = 3 – 5 – (e) = 3 – 5 – 1 = –3.
4 + (d) + (a) = 3, suy ra (a) = 3 – 4 – (d) = 3 – 4 – (–3) = 2.
4 + (g) + 0 = 3, suy ra (g) = 3 – 4 – 0 = –1.
(a) + (b) + (c) = 3, suy ra (b) = 3 – (a) – (c) = 3 – 2 – (–2) = 3.
Vậy ta có bảng:
2 | 3 | –2 |
–3 | 1 | 5 |
4 | –1 | 0 |
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