X + 27 + 7 x X = 187
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Giải:
Ta có:
\(\frac{x+1}{15}+\frac{x+2}{7}+\frac{x+4}{4}+6=0\)
\(\Leftrightarrow\frac{x}{15}+\frac{1}{15}+\frac{x}{7}+\frac{2}{7}+\frac{x}{4}+\frac{4}{4}+6=0\)
\(\Leftrightarrow\frac{x}{15}+\frac{x}{7}+\frac{x}{4}=-\frac{772}{105}\)
\(\Leftrightarrow x\left(\frac{1}{15}+\frac{1}{7}+\frac{1}{4}\right)=-\frac{772}{105}\)
\(\Leftrightarrow x=-16\)
Vậy phương trình trên có nghiệm là x = -16.
b. Cách làm tương tự.
Chúc bạn học tốt@@
\(\left(\frac{x+14}{200}+1\right)+\left(\frac{x+27}{187}+1\right)+\left(\frac{x+105}{109}+1\right)=\left(\frac{x+200}{14}+1\right)\)
\(+\left(\frac{x+187}{27}+1\right)+\left(\frac{x+109}{105}+1\right)\)
\(\Rightarrow\frac{x+214}{200}+\frac{x+214}{187}+\frac{x+214}{109}-\frac{x+214}{14}-\frac{x+214}{27}-\frac{x+214}{105}=0\)
\(\Rightarrow\left(x+214\right)\left(\frac{1}{200}+\frac{1}{187}+\frac{1}{109}-\frac{1}{14}-\frac{1}{27}-\frac{1}{105}\right)=0\)
Mà \(\frac{1}{200}+\frac{1}{187}+\frac{1}{109}-\frac{1}{14}-\frac{1}{27}-\frac{1}{105}\ne0\)
\(\Rightarrow x+214=0\)
\(\Rightarrow x=-214\)
Vậy x = -214
\(\Leftrightarrow\frac{x+14}{200}+\frac{x+27}{187}+\frac{x+105}{109}-\frac{x+200}{14}-\frac{x+187}{27}-\frac{x+109}{105}=0\)
\(\Leftrightarrow\left(\frac{x+14}{200}+1\right)+\left(\frac{x+27}{187}+1\right)+\left(\frac{x+105}{109}+1\right)-\left(\frac{x+200}{14}+1\right)-\left(\frac{x+187}{27}+1\right)-\left(\frac{x+109}{105}+1\right)=0\)\(\Leftrightarrow\frac{x+214}{200}+\frac{x+214}{187}+\frac{x+214}{109}-\frac{x+214}{14}-\frac{x+214}{27}-\frac{x+214}{105}=0\)
\(\Leftrightarrow\left(x+214\right)\left(\frac{1}{200}+\frac{1}{187}+\frac{1}{109}-\frac{1}{14}-\frac{1}{27}-\frac{1}{105}\right)=0\)
Mà \(\frac{1}{200}+\frac{1}{187}+\frac{1}{109}< \frac{1}{14}+\frac{1}{27}+\frac{1}{105}\Rightarrow\frac{1}{200}+\frac{1}{187}+\frac{1}{109}-\frac{1}{14}-\frac{1}{27}-\frac{1}{105}\ne0\)
\(\Rightarrow x+214=0\)
\(\Rightarrow x=-214\)
Vậy x=-214
\(\frac{x+14}{200}+\frac{x+27}{187}+\frac{x+105}{109}=\frac{x+200}{14}+\frac{x+187}{27}+\frac{x+109}{105}\\\Leftrightarrow \frac{x+14}{200}+1+\frac{x+27}{187}+1+\frac{x+105}{109}+1=\frac{x+200}{14}+1+\frac{x+187}{27}+1+\frac{x+109}{105}+1\\\Leftrightarrow \frac{x+214}{200}+\frac{x+214}{187}+\frac{x+214}{109}-\frac{x+214}{14}-\frac{x+214}{27}-\frac{x+214}{105}=0\\\Leftrightarrow \left(x+214\right)\left(\frac{1}{200}+\frac{1}{187}+\frac{1}{109}-\frac{1}{14}-\frac{1}{27}-\frac{1}{105}\right)=0\)
\(\Leftrightarrow x+214=0\left(vi\frac{1}{200}+\frac{1}{187}+\frac{1}{109}-\frac{1}{14}-\frac{1}{27}-\frac{1}{105}\ne0\right)\\\Leftrightarrow x=-214 \)
Vậy tập nghiệp của phương trình trên là \(S=\left\{-214\right\}\)
\(a)5-\left(x-6\right)=4\left(3-2x\right)\)
\(\Leftrightarrow5-x+6=12-8x\)
\(\Leftrightarrow-x+8x=12-5-6\)
\(\Leftrightarrow7x=1\Leftrightarrow x=\frac{1}{7}\)
a) 5-(x-6)=4(3-2x)
<=>5-x-6=12-8x
<=>-x+8x=2-5-6
<=>7x=1
<=>x=1/7
Pt <=> \(\left(\frac{x+14}{200}+1\right)+\left(\frac{x+27}{187}+1\right)+\left(\frac{x+105}{109}+1\right)=\left(\frac{x+200}{14}+1\right)+\left(\frac{x+187}{27}+1\right)+\left(\frac{x+109}{105}+1\right)\)<=> \(\frac{x+14+200}{200}+\frac{x+27+187}{187}+\frac{x+105+109}{109}=\frac{x+200+14}{14}+\frac{x+187+27}{27}+\frac{x+109+105}{105}\)<=> \(\frac{x+214}{200}+\frac{x+214}{187}+\frac{x+214}{109}=\frac{x+214}{14}+\frac{x+214}{27}+\frac{x+214}{105}\)
<=> \(\frac{x+214}{200}+\frac{x+214}{187}+\frac{x+214}{109}-\frac{x+214}{14}-\frac{x+214}{27}-\frac{x+214}{105}=0\)
<=> \(\left(x+214\right)\left(\frac{1}{200}+\frac{1}{187}+\frac{1}{109}-\frac{1}{14}-\frac{1}{27}-\frac{1}{105}\right)=0\)
Vì \(\left(\frac{1}{200}+\frac{1}{187}+\frac{1}{109}-\frac{1}{14}-\frac{1}{27}-\frac{1}{105}\right)\ne0\)
<=> \(x+214=0\)
<=> \(x=-214\)
Ta có:
\(\frac{x+14}{200}+\frac{x+27}{187}+\frac{x+105}{109}=\frac{x+200}{14}+\frac{x+187}{27}+\frac{x+109}{105}\)
Cộng thêm mỗi phân thức 1 ta được:
\(\frac{x+214}{200}+\frac{x+214}{187}+\frac{x+214}{109}-\frac{x+214}{14}-\frac{x+214}{27}-\frac{x+214}{105}=0\)
\(\Leftrightarrow x+214=0\Rightarrow x=-214\)
(x+1)+(x+4)+(x+7)+.....+(x+31)=187
(x+x+x+...+x)+(1+4+7+....+31)=187
11x+11.32:2=187
11.(x+16)=187
x+16=17
x=11
vậy x=11
( x + 1 ) + ( x + 4 ) + ( x + 7 ) + ... + ( x + 31 ) = 187
x + 1 + x + 4 + x + 7 + ... + x + 31 = 187
( x + x + x + ... + x ) + ( 1 + 4 + 7 + ... + 31 ) = 187
Đặt x + x + x + ... + x = A; 1 + 4 + 7 + ... + 31 = B
Dãy B có số số hạng là:
( 31 - 1 ) : 3 + 1 = 11 ( số hạng )
=> A = 11x
Tổng của dãy B là:
( 31 + 1 ) . 11 : 2 = 176
Ta có:
A + B = 187
=> 11x + 176 = 187
=> 11x = 187 - 176
=> 11x = 11
=> x = 1
Chu vi hình vuông là:
8 x 4 = 32 ( cm )
Chiều dài hình chữ nhật là:
32 : 2 - 12 = 4 ( cm )
Đáp số:.....
a) x = 72
b) x = 15
c) x = 34
d) x = 6
e)
f) x = 2 , x =3
g) x=1,x=-3
h)x=3,x=-2
mik chỉ bt giải thế thôi
CHÚC BẠN HỌC TỐT
Bài làm
a) ( x - 15 ) : 3 = 19
x - 15 = 19 . 3
x - 15 = 57
x = 57 + 15
x = 72
Vậy x = 72.
b) ( 5x - 45 ) . 15 = 450
5x - 45 = 450 : 15
5x - 45 = 30
5x = 75
x = 15
Vậy x = 15.
c) 187 - 3( x + 4 ) = 34
3( x + 4 ) = 187 - 34
3( x + 4 ) = 153
x + 4 = 153 : 3
x + 4 = 51
x = 47
Vậy x = 47.
d) 9x - 45 = 37 : 35
9x - 45 = 32
9x - 45 = 9
9( x - 5 ) = 9
x - 5 = 9 : 9
x - 5 = 1
x = 6
Vậy x = 6.
e ) ( 12x - 43 ) . 83 = 4 . 84
( 12x - 64 ) = 4 . 84 : 83
12x - 64 = 4 . 8
12x - 64 = 32
12x = 96
x = 8
Vậy x = 8.
f ) Đề bài không rõ ràng.
g ) ( x + 1 )2 = 4
=> ( x + 1 )2 = 22
=> x + 1 = 2
=> x = 1
Vậy x = 1.
h ) ( 2x - 1 )2 = 25
=> ( 2x - 1 )2 = 52
=> 2x - 1 = 5
=> 2x = 6
=> x = 3
Vậy x = 3
k ) ( 2x - 1 )5 = 243
=> ( 2x - 1 )5 = 35
=> 2x - 1 = 3
=> 2x = 4
=> x = 2
Vậy x = 2
# Học tốt #
x + 27 + 7.x = 187
x + 7x + 27 = 187
8x = 187 - 27
8x = 160
x = 160 : 8
x = 20
Vậy x = 20
x + 27 +7 + x = 187
2x + 27 + 7 = 187
2x + 34 = 187
2x = 187 - 34
2x = 153
x = 153/2