Bài 1, trang 11 sgk lớp 5
1. Tính :
a. 3/10 × 4/9
6/5 : 3/7
3/4 × 2/5
5/8 : 1/2
b. 4 × 3/8
3 : 1/2
1/2 : 3
-Nêu cách trình bày dùm lun ạ !
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Bài 2 :
a, \(3+\dfrac{2}{5}\)
= \(\dfrac{15}{5}+\dfrac{2}{5}\)
= \(\dfrac{17}{5}\)
b, \(4-\dfrac{5}{7}\)
= \(\dfrac{28}{7}-\dfrac{5}{7}\)
= \(\dfrac{23}{7}\)
c, \(1-\left[\dfrac{2}{5}+\dfrac{1}{3}\right]\)
= \(1-\left[\dfrac{6}{15}+\dfrac{5}{15}\right]\)
= \(\dfrac{15}{15}-\dfrac{11}{15}\)
= \(\dfrac{4}{15}\)
Bài 2
a, 3 + \(\dfrac{2}{5}\) = \(\dfrac{15}{5}\) + \(\dfrac{2}{5}\) = \(\dfrac{17}{5}\)
b, 4 - \(\dfrac{5}{7}\) = \(\dfrac{28}{7}\) - \(\dfrac{5}{7}\) = \(\dfrac{23}{7}\)
c, 1 - ( \(\dfrac{2}{5}\) + \(\dfrac{1}{3}\))
= 1 - (\(\dfrac{6}{15}\) + \(\dfrac{5}{15}\))
= 1 - \(\dfrac{11}{15}\)
= \(\dfrac{15}{15}\) - \(\dfrac{11}{15}\)
= \(\dfrac{4}{15}\)
b, \(\dfrac{3}{5}\) - \(\dfrac{3}{8}\)
= \(\dfrac{24}{40}\) - \(\dfrac{15}{40}\)
= \(\dfrac{9}{40}\)
c, \(\dfrac{1}{4}\) + \(\dfrac{5}{6}\)
= \(\dfrac{6}{24}\) + \(\dfrac{20}{24}\)
= \(\dfrac{26}{24}\)
= \(\dfrac{13}{12}\)
1: \(=\dfrac{1}{3}\cdot\dfrac{3}{7}\cdot\dfrac{1}{2}=\dfrac{1}{7\cdot2}=\dfrac{1}{14}\)
2: =5/12+1/7
=35/84+12/84=47/84
3: =8(8/9-6/9)
=8*2/9=16/9
4: \(=\dfrac{5}{12}\cdot\dfrac{12}{5}=1\)
5: =16/5+6
=16/5+30/5=46/5
6: =10*1/2-10*1/5
=5-2=3
1) 1/3 x 1/2 x 3/7 = 3/42 = 1/14
2) 5/4 x 1/3 +1/7 = 5/12 + 1/7 = 35/84 + 12/84 = 47/84
3) 8 x ( 8/9 - 2/3 ) = 8 x 2/9 = 16/9
4) 5/6 x 48/20 x 1/2 = 240/240 = 1
5) ( 2/5 + 3/4 ) + 8 = 23/20 + 8 = 23//20 + 160/20 = 183/20
6) 10 x ( 1/2 - 1/5 ) = 10 x 3/10 = 10/1 x 3/10 = 30/10 = 3
6)
(19-x)-46=-12
19-x=-12+46
19-x=34
x=19-34
x=-15
7)=>x-2=0
x=0+2
x=2
8)=>5-x=2
x=5-2
x=3
9) đề thiếu
10)=>x+1=9
x=9-4
x=8
A. 5(x-11) + 4(x-3) =10
<=>5x -55 + 4x -12 =10
<=>9x -67 =10
<=>9x =10+67 =77
<=>x =77 : 9 =77/9
B.21 - 5 ( x-7) = 2-3(x-5)
<=>21-5x+35 = 2 - 3x +15
<=>-5x + 56 = -3x + 17
<=>-5x +3x=17-56=-39
<=> -2x =-39
<=> x = -39 : -2 =39/2
C.3(2x-1)-7(x+4)=8-9x
<=>6x -4 -7x-28=-9x+8
<=>-x + 9x = 8+4+28=40
<=> 8x = 40
<=> x = 40:8=5
D. l 4-x l =11
<=>\(\orbr{\begin{cases}4-x=11\\4-x=-11\end{cases}}\)<=> \(\orbr{\begin{cases}x=-7\\x=15\end{cases}}\)
E. 5-3 l x+2 l = -28
<=> 3 l x+2 L = -28 -5 =-33
<=> l x+2 l = -33 :3 =11
<=>\(\orbr{\begin{cases}x+2=11\\x+2=-11\end{cases}}\)<=> \(\orbr{\begin{cases}x=9\\-13\end{cases}}\)
T I C K mk nhé!!!^_^
b)\(4\times\dfrac{3}{8}=\dfrac{12}{8}=\dfrac{3}{2}\)
\(3:\dfrac{1}{2}\)
=\(3\times\dfrac{2}{1}\)
= 6
=\(\dfrac{1}{2}:3\)
= \(\dfrac{1}{2}\times\dfrac{1}{3}\)
= \(\dfrac{1}{6}\)
1a, \(\dfrac{3}{10}\) \(\times\) \(\dfrac{4}{9}\)
= \(\dfrac{3\times2\times2}{2\times5\times3\times3}\)
= \(\dfrac{2}{15}\)
\(\dfrac{6}{5}\): \(\dfrac{3}{7}\)
= \(\dfrac{6}{5}\) \(\times\) \(\dfrac{7}{3}\)
= \(\dfrac{14}{5}\)
\(\dfrac{3}{4}\) \(\times\) \(\dfrac{2}{5}\)
= \(\dfrac{3\times2}{2\times2\times5}\)
= \(\dfrac{3}{10}\)
\(\dfrac{5}{8}\) : \(\dfrac{1}{2}\)
= \(\dfrac{5}{8}\) \(\times\) \(\dfrac{2}{1}\)
= \(\dfrac{5}{4}\)