x-17=(-8)-17
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`@` `\text {Ans}`
`\downarrow`
`x^3 = 125`
`=> x^3 = 5^3`
`=> x = 5`
Vậy, `x = 5`
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`4^5 \div 4^3`
`=`\(4^{5-3}\)
`= 4^2`
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\(8^{12}\cdot8^3\div8^{15}\)
`=`\(8^{12+3-15}\)
`=`\(8^0=1\)
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\(7^{15}\div7^{13}\)
`=`\(7^{15-13}\)
`=`\(7^2\)
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\(17^{15}\cdot17^{10}\div17^{22}\)
`=`\(17^{15+10-22}\)
`= 17^3`
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\(5^{10}\cdot25\div5^{11}\)
`=`\(5^{10}\cdot5^2\div5^{11}\)
`=`\(5^{10+2-11}\)
`= 5`
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\(15^{10}\cdot225\div15^{11}\)
`=`\(15^{10}\cdot15^2\div15^{11}\)
`=`\(15^{12}\div15^{11}\)
`= 15`
`@` `\text {Kaizuu lv uuu}`
\(x^3=125\)
\(\Rightarrow x^3=5^3\)
\(\Rightarrow x=3\)
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\(4^5:4^3\)
\(=4^{5-3}\)
\(=4^2=16\)
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\(8^{12}.8^3:8^{15}\)
\(=8^{15}:8^{15}\)
\(=1\)
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\(7^{15}:7^{13}\)
\(=7^{15-13}\)
\(=7^2=49\)
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\(17^{15}.17^{10}:17^{22}\)
\(=17^{25}:17^{22}\)
\(=17^3=4913\)
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\(5^{10}.25:5^{11}\)
\(=5^{10}.5^2:5^{11}\)
\(=5^{12}:5^{11}\)
\(=5^1=5\)
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\(15^{10}.225:15^{11}\)
\(=15^{10}.15^2:15^{11}\)
\(=15^{12}:15^{11}\)
\(=15^1=15\)
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* an . am = an+m
an : am = an-m
Chúc bạn học tốt
\(\Leftrightarrow\frac{-2}{17}\le\frac{x}{17}\le\frac{2}{17}\Rightarrow x\in\left(-2;-1;0;1;2\right)\)
\(\Leftrightarrow\frac{-1}{24}\le\frac{x}{24}\le\frac{5}{24}\Rightarrow x\in\left(-1;0;1;2;3;4;5\right)\)
2 câu sau tự làm nha
\(-\frac{5}{17}+\frac{3}{17}\le\frac{x}{17}\le\frac{13}{17}+-\frac{11}{17}\)
\(\frac{-2}{17}\le\frac{x}{17}\le\frac{2}{17}\)
=> \(x\in\left\{-2;-1;0;1;2\right\}\)
`(5+8/17):x+(-4/17):x+(3+1/7):(17+1/3)=4/11`
`(5+8/17)xx1/x-4/17xx1/x+22/7:52/17=4/11`
`(5+4/17)xx1/x+187/182=4/11`
`89/17xx1/x=-1329/2002`
`x=-118281/34034`
Số to quá ;-;
\(\left(5+\dfrac{8}{17}\right):x+\left(\dfrac{-4}{17}\right):x+\left(3+\dfrac{1}{17}\right):\left(17+\dfrac{1}{3}\right)=\dfrac{4}{11}\)
\(\left(\dfrac{93}{17}+\dfrac{-4}{17}\right):x+\dfrac{52}{17}:\dfrac{52}{3}=\dfrac{4}{11}\)
\(\dfrac{89}{17}:x+\dfrac{3}{17}=\dfrac{4}{11}\)
\(\dfrac{89}{17}:x=\dfrac{4}{11}-\dfrac{3}{17}\)
\(\dfrac{89}{17}:x=\dfrac{35}{187}\)
\(x=\dfrac{89}{17}:\dfrac{35}{187}\)
\(x=\dfrac{979}{35}\)
Mk thấy đề bài thế này mới đúng nếu sai thì nhắc mk nha!
\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow x\left(\frac{1}{2}-\frac{2}{3}\right)=\frac{7}{12}\Rightarrow x\cdot\left(\frac{3}{6}-\frac{4}{6}\right)=\frac{7}{12}\)
\(\Rightarrow x\cdot\left(-1\right)=\frac{7}{12}\Rightarrow x=\frac{7}{12}:\left(-1\right)=\frac{7}{-12}\)
\(c,\frac{\left(x-5\right)}{12}\cdot\frac{9}{29}=\frac{-6}{29}\Rightarrow\frac{\left(x-5\right)}{12}=\frac{-6}{29}:\frac{9}{26}\)
\(\frac{\Rightarrow\left(x-5\right)}{12}=\frac{-6}{9}=\frac{-2}{3}\Rightarrow x-5=-\frac{2}{3}\cdot12\)
\(\Rightarrow x-5=\frac{-24}{3}=-8\Rightarrow x=-8+5=-3\)
\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow-\frac{1}{6}x=\frac{7}{12}\)
\(\Rightarrow x=-\frac{7}{2}\)
\(c,\frac{x-5}{12}\cdot\frac{9}{29}=-\frac{6}{29}\)
\(\Rightarrow\frac{x-5}{12}=-\frac{2}{3}\)
\(\Rightarrow x-5=12.\left(-\frac{2}{3}\right)\)
\(\Rightarrow x-5=-8\)
\(\Rightarrow x=-3\)
x-17=(-8)-17
x - 17 = - 25
x = - 25 + 17
x = - 8
Vậy x = -8