Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
=1875*8,1*5/3+13,5*625
=13,5*(1875+625)
=13,5*2500
=33750
`@` `\text {Ans}`
`\downarrow`
`a,`
`(x-1954) \times 5=50`
`x-1954 = 50 \div 5`
`x-1954 = 10`
`x=10 + 1954`
`x= 1964`
`B.`
`48 - 40 \times x=8`
`40 \times x=48-8`
`40 \times x = 40`
` x=40 \div 40`
`x=1`
`C.`
`2+70 \div x = 3`
`70 \div x = 3-2`
`70 \div x = 1`
`x=70 \div 1`
`x=70`
`D. [3 \times (x+2) \div 7] \times 4=120`
`3 \times (x+2) \div 7 = 120 \div 4`
`3 \times (x+2) \div 7 =30`
`3 \times (x+2) = 30 \times 7`
`3 \times (x+2)=210`
`x+2=210 \div 3`
`x+2=70`
`x=70-2`
`x=68`
`E.`
`7,2 \div [ (0,6 \times x+8) \div 20 + 59] = 0,12?` Thiếu ngoặc bạn nhé._.
\(a,\left(x-1954\right)\times5=50\\ x-1954=50:5\\ x-1954=10\\ x=1954+10\\ x=1964\\b.48-40\times x=8\\40\times x=48-8\\40\times x=40\\ x=40:40\\ x=1 \\ c.2+70:X=3\\ 70:x=3-2\\ 70:x=1\\ x=70:1\\ x=70\\ d,\left[3\times\left(x+2\right):7\right]\times4=120\\ 3\times\left(x+2\right):7-120:4\\ 3\times\left(x+2\right):7=30\\ \left(x+2\right):7=30:3\\ \left(x+2\right):7=10\\ x+2=10\times7\\ x+2=70\\ x=70-2\\ x=68\)
\(\left(\frac{4}{3}\right)^{2018}:\left(\frac{16}{9}\right)^{1008}-x=0,6^3:0,2^3\)
\(\Leftrightarrow\left[\left(\frac{4}{3}\right)^2\right]^{1009}:\left(\frac{16}{9}\right)^{1008}-x=27\)
\(\Leftrightarrow\left(\frac{16}{9}\right)^{1009}:\left(\frac{16}{9}\right)^{1008}-x=27\)
\(\Leftrightarrow\frac{16}{9}-x=27\)
\(\Leftrightarrow x=\frac{-227}{9}\)
Vậy x = \(\frac{-227}{9}\)
\(\left(-0,6\cdot x-\frac{1}{2}\right)\cdot\frac{3}{4}-9-\left(-1\right)=\frac{1}{3}\)
\(\left(-0,6\cdot x-\frac{1}{2}\right)\cdot\frac{3}{4}-10=\frac{1}{3}\)
\(\left(-0,6\cdot x-\frac{1}{2}\right)\cdot\frac{3}{4}=\frac{31}{3}\)
\(-0,6\cdot x-\frac{1}{2}=\frac{124}{9}\)
\(-0,6\cdot x=\frac{257}{18}\)
\(x=\frac{1285}{54}\)
\(\left(-0,6.x-\frac{1}{2}\right).\frac{3}{4}-9-\left(-1\right)=\frac{1}{3}\)
\(\frac{-9}{20}x-\frac{3}{8}-\left(9-1\right)=\frac{1}{3}\)
\(\frac{-9}{20}x-\frac{3}{8}-8=\frac{1}{3}\)
\(\frac{-9}{20}x-\left(\frac{3}{8}+8\right)=\frac{1}{3}\)
\(\frac{-9}{20}x-\frac{67}{8}=\frac{1}{3}\)
\(\frac{-9}{20}x=\frac{1}{3}+\frac{67}{8}\)
\(\frac{-9}{20}x=\frac{8}{24}+\frac{201}{24}\)
\(\frac{-9}{20}x=\frac{209}{24}\)
\(x=\frac{209}{24}.\frac{-20}{9}\)
\(x=\frac{-1045}{54}\)
\(0,6.x+40\%.x=9\)
\(0,6.x+0,4.x=9\)
\(\left(0,6+0,4\right).x=9\)
\(1.x=9\)
\(x=9:1\)
\(x=9\)
0,6.X+40%.X=9
=> 0,6.X+0,4.X=9
<=> 0,6X+0,4X=9
<=> 1X=9
<=> X=9