567,34 - 34,97 = ?
321 + 23,56 = ?
54 -23 +65 = ?
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a: \(4\cdot3^3-75:5^2\)
\(=4\cdot27-\dfrac{75}{25}\)
=108-3
=105
b: \(7\cdot2^4-16\cdot3\)
\(=16\cdot7-16\cdot3\)
=16(7-3)
=16*4=64
c: \(2^3\cdot17-2^3\cdot14\)
\(=8\cdot17-8\cdot14\)
=8(17-14)
=8*3
=24
d: \(45+\dfrac{54}{3^2}\)
\(=45+\dfrac{54}{9}\)
=45+6
=51
e: \(17\cdot85+15\cdot17-120\)
\(=17\left(85+15\right)-120\)
=1700-120
=1580
f: \(\dfrac{3^{24}}{3^{21}}+2^2\cdot2^3\)
\(=3^3+2^5\)
=27+32
=59
g: \(92+4^3:8\)
=92+64/8
=92+8
=100
h: \(5\cdot2^3+7^{11}:7^9-1^{2023}\)
\(=5\cdot8+49-1\)
=40+48
=88
Vì tất cả các số hạng khi nhân với 0 đều có kết quả là 0. Vậy kết quả của phép tính trên là 0.
135--65+23-(10+23)
=135+65+23-10-23
=(135+65)+(23-23)-10
=200+0-10
=190
Bài 1:
a, 35 + 28 - 42 - 35 - 28
= (35 - 35) + (28 - 28) - 42
= -42
b, 55 +56 +57 +58 +59 -28 -26 -25 -29 -27
=(55-25)+(56-26)+(57-27)+(58-28)+(59-29)
= 30 + 30 + 30 + 30 + 30
= 150
Bài 2:
a, -1983 - (325 - 1983)
= -1983 - 325 + 1983
= -325
b, -549 + (321 + 549)
= -549 + 321 + 549
= 321
c, 54 - (-65 + 98 - 15)
= 54 + 65 - 98 + 15
= 36
d, (67 + 23) - (56 - 32 + 46)
= 67 + 23 - 56 + 32 - 46
= 20
e, 24 - [ 15 - (42 - 18) ]
= 24 - [ 15 - 42 + 18 ]
= 24 - (-9)
= 33
f, (63 - 21 + 84) - (49 - 36 + 87)
= 63 - 21 + 84 - 49 + 36 - 87
= 26
g, 284 - [ (214 - 168) - (865 - 987) ]
= 284 - [ 214 - 168 - 865 + 987 ]
= 284 - 168
= 116
h, 654 + [ (545 - 726) - (321 - 465) ]
= 654 + [ 545 - 726 - 321 + 465 ]
= 654 + (-37)
= 617
Chúc bạn học tốt !
Lời giải chi tiết:
28 < 31 | 84 < 90 | 54 < 50 + 5 |
65 > 64 | 72 = 72 | 25 = 20 + 5 |
23 < 32 | 48 > 39 | 86 < 80 + 7 |
28 < 31 | 84 < 90 | 54 < 50 + 5 |
65 > 64 | 72 = 72 | 25 = 20 + 5 |
23 < 32 | 48 > 39 | 86 < 80 + 7 |
1. Tính:
a) 23 + 24 - ( 65 x 2 - 4 ) x 4 + 66 + 44 - ( 54 : 9 x 9 : 9 + 45 ) : 1 + 1 - 1 x ( 23 + 23 - 23 x 2 +1 ) = 51
b) 4444444444444444444444444444444444444444444444444444444444444444444 : 1
= 4444444444444444444444444444444444444444444444444444444444444444444
c) 30 = 0
d) 1/1 = 1
e)
a) - 530
b) 44444444444444444444444444444444444444444444444444444444444444444444
c) 0
d) 1
e) Em là em
Bài 1:
1) Ta có: \(\left(-12\right)+6\cdot\left(-3\right)\)
\(=-12-18\)
=-30
2) Ta có: \(\left(36-2020\right)+\left(2019-136\right)-27\)
\(=36-2020+2019-136-27\)
\(=1-100-27\)
\(=-126\)
3) Ta có: \(\left(144-97\right)-\left(244-197\right)\)
\(=144-97-244+197\)
\(=-100+100=0\)
4) Ta có: \(\left(-24\right)\cdot13-24\cdot\left(-3\right)\)
\(=-24\cdot13+24\cdot3\)
\(=24\cdot\left(-13+3\right)\)
\(=24\cdot\left(-10\right)=-240\)
5) Ta có: \(54+55+56+57+58-\left(64+65+66+67+68\right)\)
\(=54+55+56+57+58-64-65-66-67-68\)
\(=\left(54-64\right)+\left(55-65\right)+\left(56-66\right)+\left(57-67\right)+\left(58-68\right)\)
\(=\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)\)
=-50
6) Ta có: \(24\cdot\left(16-5\right)-16\cdot\left(24-5\right)\)
\(=24\cdot16-24\cdot5-16\cdot24+16\cdot5\)
\(=-24\cdot5+16\cdot5\)
\(=5\cdot\left(-24+16\right)\)
\(=-5\cdot8=-40\)
7) Ta có: \(47\cdot\left(23+50\right)-23\cdot\left(47+50\right)\)
\(=47\cdot23+47\cdot50-23\cdot47-23\cdot50\)
\(=47\cdot50-23\cdot50\)
\(=50\cdot\left(47-23\right)\)
\(=50\cdot24=1200\)
8) Ta có: \(\left(-31\right)\cdot47+\left(-31\right)\cdot52+\left(-31\right)\)
\(=-31\cdot\left(47+52+1\right)\)
\(=-31\cdot100=-3100\)
Bài 2:
1) Ta có: \(-17-\left(2x-5\right)=-6\)
\(\Leftrightarrow-17-2x+5+6=0\)
\(\Leftrightarrow-2x-6=0\)
\(\Leftrightarrow-2x=6\)
hay x=-3
Vậy: x=-3
2) Ta có: \(10-2\left(4-3x\right)=-4\)
\(\Leftrightarrow10-8+6x+4=0\)
\(\Leftrightarrow6x+6=0\)
\(\Leftrightarrow6x=-6\)
hay x=-1
Vậy: x=-1
3) Ta có: \(-12+3\left(-x+7\right)=-18\)
\(\Leftrightarrow-12-3x+21+18=0\)
\(\Leftrightarrow-3x+27=0\)
\(\Leftrightarrow-3x=-27\)
hay x=9
Vậy: x=9
4) Ta có: \(-45:\left[5\cdot\left(-3-2x\right)\right]=3\)
\(\Leftrightarrow5\cdot\left(-3-2x\right)=-15\)
\(\Leftrightarrow-2x-3=-3\)
\(\Leftrightarrow-2x=0\)
hay x=0
Vậy: x=0
5) Ta có: x(x+3)=0
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)
Vậy: \(x\in\left\{0;-3\right\}\)
6) Ta có: (x-2)(x+4)=0
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)
Vậy: \(x\in\left\{2;-4\right\}\)
7) Ta có: \(x\left(x+1\right)\left(x-3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\\x=3\end{matrix}\right.\)
Vậy: \(x\in\left\{0;-1;3\right\}\)
Bài 1:
1) Ta có: (−12)+6⋅(−3)(−12)+6⋅(−3)
=−12−18=−12−18
=-30
2) Ta có: (36−2020)+(2019−136)−27(36−2020)+(2019−136)−27
=36−2020+2019−136−27=36−2020+2019−136−27
=1−100−27=1−100−27
=−126
Tớ chcs cậu học thật giỏi nha !
\(\Rightarrow❤️✔️✨♕✨✔️❤️\Leftarrow\)
567,34 - 34,97 = 532,37
321 + 23,56 = 344,56
54 - 23 + 65 = 96
Chúc bạn học tốt !
567,34 - 34,97 = 532,37
321 + 23,56 = 344,56
54 -23 +65 = 96