Bài 1 ) Tìm x
1) \(16^2-9.\left(x+1\right)^2=0\)
2) \(x^2.\left(x-2000\right)=x-2000\)
3)\(x^2-7x+10=0\)
4) \(x^3-2x^3-4x-4=0\)
5)\(x^3-4x^2+12x-2-3=0\)
6) \(x^3+3x^2-4=0\)
7)\(\left(2x^2+x\right)^2-4.\left(2x^2+x\right)+3=0\)
8) \(2x^3-3x^2+3x-1=0\)
9) \(9.\left(x-2\right)^2-25.\left(x+4\right)^2=0\)
Lần sau đăng thì chia thành nhiều câu hỏi nhé
\(16^2-9.\left(x+1\right)^2=0\)
\(16^2-\text{ }\left[3.\left(x+1\right)\right]^2=0\)
\(\left[16-3.\left(x+1\right)\right].\left[16+3\left(x+1\right)\right]=0\)
\(\left[16-3x-3\right]\left[16+3x+3\right]=0\)
\(\left[13-3x\right].\left[19+3x\right]=0\)
\(\Rightarrow\orbr{\begin{cases}13-3x=0\\19+3x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}3x=13\\3x=-19\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{13}{3}\\x=-\frac{19}{3}\end{cases}}}\)
KL:..............................
Nhiều câu hỏi mà bn ??