[x+2] + [x+4] + [x+6] + [x+8] + x = 120
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(x+2)+(x+4)+(x+6)+(x+8)+x=120
=>(x+x+x+x+x)+(2+8)+(4+6)=120
=>5.x+20=120
=>5.x=100
=>x=100:5
=>x=20
(x+2)+(x+4)+(x+6)+(x+8)+x=120
( x + x + x + x + x ) + ( 2 + 4 + 6 + 8 ) = 120
5x + 20 = 120
5x = 120 - 20
5x = 100
x = 100 : 5
x = 20
(x+2)+(x+4)+(x+6)+(x+8)+x=120
120=5x+(2+4+6+8)
120=5x+20
=>5x=120-20
=>5x=100
=>x=100:5
=>x=20
vậy x=20.
Giải :
0,8 x 120 + 4 x 2 x 6 +8 x 2 +8 x 80
= 8 x 12 + 8 x 6 + 8 x 2 + 8 x 80
= 8 x ( 12 + 6 + 2 + 80 )
= 8 x 100
= 800
= 800 nha bạn
hok tốt
bạn nào trên 10 sp hoặc 10 sp k giúp mình ạ
1. \(x-8+32=68\)
\(x-8=68-32\)
\(x-8=36\)
\(x=36+8\)
\(x=44\)
_____
2. \(x+8+32=68\)
\(x+8=68-32\)
\(x+8=36\)
\(x=36-8\)
\(x=28\)
_____
3. \(98-x+34=43\)
\(98-x=43-34\)
\(98-x=9\)
\(x=98-9\)
\(x=89\)
_____
4. \(98+x-34=43\)
\(98+x=43+34\)
\(98+x=77\)
\(x=77-98\)
\(x=-21\)
_____
5. \(x:5:4=800\)
\(x:5=800.4\)
\(x:5=3200\)
\(x=3200.5\)
\(x=16000\)
_____
6. \(18+x=384:8\)
\(18+x=48\)
\(x=48-18\)
\(x=30\)
_____
7. \(\left(84,6-2\times x\right):3,02=5,1\)
\(84,6-2.x=5,1.3,02\)
\(84,6-2.x=15,402\)
\(2.x=84,6-15,402\)
\(2.x=69,198\)
\(x=69,198:2\)
\(x=34,599\)
_____
8. \(x\times5=120:6\)
\(x.5=20\)
\(x=20:5\)
\(x=4\)
_____
9. \(\left(15\times24-x\right):0,25=100:0,25\)
\(\left(15.24-x\right):0,25=400\)
\(15.24-x=400.0,25\)
\(15.24-x=100\)
\(360-x=100\)
\(x=360-100\)
\(x=260\)
1,x-8+32=68
=>x-8=68-32=36
=>x=36+8=42
2,x+8+32=68
=>x+8=68-32=36
=>x=36-8=28
3,98-x+34=43
=>98-x=43-34=9
=>x=98-9=89
4,98+x-34=43
=>98+x=43+34=77
=>x=77-98=-21
5,x:5:4=800
=>x:20=800
=>x=800x20=16000
6,18+x=384:8=48
=>x=48-18=30
7,(84,6-2x):3,02=5,1
=>84,6-2x=5,1x3,02=15,402
=>2x=84,6-15,402=69,198
=>x=69,198:2=34,599
8,5x=120:6=20
=>x=20:5=4
9,(15x24-x):0,25=100:0,25=400
=>360-x=400x0,25=100
=>x=360-100=260.
\(\left(x+2\right)+\left(x+4\right)+\left(x+6\right)+\left(x+8\right)+x=120\)
\(\left(x+x+x+x+x\right)+\left(2+4+6+8\right)=120\)
\(x\times5+20=120\)
\(x\times5=120-20\)
\(x\times5=100\)
\(x=100:5\)
\(x=20\)
a,(x+1)+(x+2)+(x+3)+....+(x+9)+(x+10)=240
Từ 1 đến 10 có số số hạng là:(10-1):1+1=10
Từ 1 đến 10 có tổng là:(10+1)x10:2=55
Ta có:(Xx10)+55=240
Xx10 =240-55
Xx10 =185
X =185:10
X =18,5
\(\dfrac{10.4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\dfrac{5.2.2^{12}.3^{10}+3^9.2^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\dfrac{5.2^{13}.3^{10}+2^{12}.3^{10}.5}{2^{11}.3^{11}\left(2.3-1\right)}=\dfrac{2^{12}.3^{10}.5\left(2+1\right)}{2^{11}.3^{11}.5}\)
\(=\dfrac{2^{11}.2.3^{10}.5.3}{2^{11}.3^{10}.3.5}=2\)
a) \(\left(x-1\right)^3=8=2^3\)
\(x-1=2\)
\(x=2+1=3\)
b) \(7^{2x-6}=49=7^2\)
\(2x-6=2\)
\(2x=6+2=8\)
\(x=8:2=4\)
c) \(\left(2x-14\right)^7=128=2^7\)
\(2x-14=2\)
\(2x=14+2=16\)
\(x=16:2=8\)
d) \(x^4\cdot x^5=5^3\cdot5^6=5^4\cdot5^5\)
\(x=5\)
e) \(3\cdot\left(x+2\right):7\cdot4=120\)
\(x+2=120:3\cdot7:4\)
\(x+2=70\)
\(x=70-2=68\)
Lời giải:
a. $(x-1)^3=8=2^3$
$\Rightarrow x-1=2$
$\Rightarrow x=3$
b. $7^{2x-6}=49=7^2$
$\Rightarrow 2x-6=2$
$\Rightarrow 2x=8$
$\Rightarrow x=4$
c. $(2x-14)^7=128=2^7$
$\Rightarrow 2x-14=2$
$\Rightarrow 2x=16$
$\Rightarrow x=18$
d.
$x^4.x^5=5^3.5^6$
$x^9=5^9$
$\Rightarrow x=5$
e.
$3(x+2):7=120:4=30$
$3(x+2)=30.7=210$
$x+2=210:3=70$
$x=70-2=68$
(x+2)+(x+4)+(x+6)+(x+8)+x=120
(x+x+x+x+x)+(2+4+6+8)=120
5x+20=120
5x=120-20
5x=100
x=100:5
x=20
Vậy x=20
\(\left(x+2\right)+\left(x+4\right)+\left(x+6\right)+\left(x+8\right)+x=120\)
\(\left(x+x+x+x+x\right)+\left(2+4+6+8\right)=120\)
\(x.5+20=120\)
\(x.5=120-20\)
\(x.5=100\)
\(x=100:5\)
\(x=20\)