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a) (x - 78) .26 = 0 => x - 78 = 0 => x = 78
b) 39 (x - 5) = 39 => x - 5 = 1 => x = 6
c) (x - 14) : 2 = 3 => x - 14 = 6 => x = 20
d) (30 - x) . 4 = 92
=> 30 - x = 92 : 4
=> 30 - x = 23
=> x = 30 - 23 = 7
e) 45(91 - x) = 90
=> 91 - x = 90 : 45
=> 91 - x = 2
=> x = 91 - 2 = 89
f) (2x - 6)(3x - 18) = 0
=> \(\orbr{\begin{cases}2x-6=0\\3x-18=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=6\end{cases}}\)
g) 5x + 73.21 = 73.26
=> 5x = 73.26 - 73.21
=> 5x = 73(26 - 21) = 73.5
=> x = \(\frac{73\cdot5}{5}=73\)
h) 2x - 12 - x = 0
=> 2x - x - 12 = 0
=> x - 12 = 0
=> x = 12
1.
a.
11 + x : 5 = 13
x : 5 = 13 - 11
x : 5 = 2
x = 2 . 5
x = 10
Bài 2:
a: \(\Leftrightarrow2x^2-10x-3x-2x^2=26\)
=>-13x=26
hay x=-2
b: \(\Leftrightarrow\left(x-1\right)\left(5x-1\right)=0\)
hay \(x\in\left\{1;\dfrac{1}{5}\right\}\)
c: \(\Leftrightarrow\left(x+5\right)\left(2-x\right)=0\)
hay \(x\in\left\{-5;2\right\}\)
a) (x - 78) . 26 = 40
=>x-78 = 40 : 26 = 20/13
=> x = 78 + 20/13
=> x = 1034/13
b) 39 . (x-5) =39
=>x-5=39:39=1
=>x=1+5=6
c) 30- ( 52 - x) =90
=>30-52+x=90
=>-22+x=90
=>x=90-(-22)
=>x=112
d) (x-12) : 5 =2
=>x-12=2.5=10
=>x=10+12=22
a) \(x-\dfrac{2}{3}=\dfrac{3}{8}\Rightarrow x=\dfrac{3}{8}+\dfrac{2}{3}=\dfrac{25}{24}\)
b) \(x-\dfrac{3}{4}=\dfrac{13}{10}:\dfrac{26}{5}\Rightarrow x-\dfrac{3}{4}=\dfrac{1}{4}\Rightarrow x=\dfrac{1}{4}+\dfrac{3}{4}=1\)
c) \(\dfrac{3}{2}-\left(x+\dfrac{1}{2}\right)=\dfrac{4}{5}\Rightarrow x+\dfrac{1}{2}=\dfrac{3}{2}-\dfrac{4}{5}=\dfrac{7}{10}\)
\(\Rightarrow x=\dfrac{7}{10}-\dfrac{1}{2}=\dfrac{1}{5}\)
d) \(\left|x-2\right|-1=0\Rightarrow\left|x-2\right|=1\)
\(\Rightarrow\left[{}\begin{matrix}x-2=1\\x-2=-1\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)
a: Ta có: \(x-\dfrac{2}{3}=\dfrac{3}{8}\)
\(\Leftrightarrow x=\dfrac{3}{8}+\dfrac{2}{3}=\dfrac{9}{24}+\dfrac{16}{24}=\dfrac{25}{24}\)
b: Ta có: \(x-\dfrac{3}{4}=\dfrac{13}{10}:\dfrac{26}{5}\)
\(\Leftrightarrow x-\dfrac{3}{4}=\dfrac{13}{10}\cdot\dfrac{5}{26}=\dfrac{1}{4}\)
hay x=1
\(a,\Rightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x-5< 0\\x+2>0\end{matrix}\right.\\\left\{{}\begin{matrix}x-5>0\\x+2< 0\end{matrix}\right.\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x< 5\\x>-2\end{matrix}\right.\\\left\{{}\begin{matrix}x>5\\x< -2\end{matrix}\right.\end{matrix}\right.\Rightarrow-2< x< 5\\ \Rightarrow x\in\left\{-1;0;1;2;3;4\right\}\\ b,\Rightarrow5< x^2< 14\\ \Rightarrow x^2=9\Rightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
32.(x-10)=32
=>x-10=32:32
=>x-10=1
=>x=11
(x-78).26=0
=>x-78=0:26
=>x-78=0
=>x=78
(x-14):2=3
=>x-14=3.2
=>x-14=6
=>x=14+6
=>x=20
a) 32.(x-10)=32
x-10=1
x=11
b) (x-78).26=0
x-78=0
x=78
c) (x-14):2=3
x-14=6
x=20
Bài 1:
a: BCNN(10;12)=60
b: BCNN(24;10)=120
c: BCNN(4;14;26)=364
d: BCNN(6;8;10)=120
a) \(\left(x-78\right).26=0\) b) \(39.\left(x-5\right)=39\)
\(\left(x-78\right)=0\) \(x-5=39:39\)
\(x=0+78\) \(x=1+5\)
\(x=78\) \(x=6\)
P/S: Dấu "." là dấu nhân nhé
\(\left(x-14\right):2=3\)
\(x-14=2.3\)
\(x=6+14\)
\(x=20\)
\(\left(30-x\right):4=92\)
\(30-x=92.4\)
\(30-x=368\)
\(x=30-368\)
\(x=-338\)