19,96 +4,19 -24 ,15 :(:1/4-1/4)=23,15
252/x=84/97
x-2/255=114/153
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\(19,96+4,19-24,15:\left(x:\frac{1}{4}-\frac{1}{4}\right)=23,15\)
\(24,15-24,15:\left(x:\frac{1}{4}-\frac{1}{4}\right)=23,15\)
\(24,15:\left(x:\frac{1}{4}-\frac{1}{4}\right)=1\)
\(x:\frac{1}{4}-\frac{1}{4}=24,15\)
\(4x=24,4\)
\(x=6,1\)
\(\text{Bài này cx đơn giản thôi!}\)
\(4.19-24.15:\left(x:\frac{1}{4}-\frac{1}{4}\right)=23.15-19.96\)
\(4.19-24.15:\left(x:\frac{1}{4}-\frac{1}{4}\right)=3.19\)
\(24.15:\left(x:\frac{1}{4}-\frac{1}{4}\right)=4.19-3.19\)
\(24.15:\left(x:\frac{1}{4}-\frac{1}{4}\right)=1\)
\(x:\frac{1}{4}-\frac{1}{4}=24.15:1\)
\(x:\frac{1}{4}-\frac{1}{4}=24.15\)
\(x:\frac{1}{4}=24.15+\frac{1}{4}\)
\(x:\frac{1}{4}=24.4\)
\(x=24.4.\frac{1}{4}\)
\(x=6.1\)
1)\(\frac{252}{x}=\frac{84}{97}\Rightarrow\)\(\frac{84}{97}=\frac{252}{291}\Rightarrow x=291\)
6) \(\frac{y}{15}=\frac{2}{5}\Rightarrow\frac{2}{5}=\frac{6}{15}\Rightarrow x=6\)
1. \(\left(\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+\frac{2}{17.19}+\frac{2}{19.21}\right)\times462-x=19\)
\(\left(\frac{13-11}{11.13}+\frac{15-13}{13.15}+\frac{17-15}{15.17}+\frac{19-17}{17.19}+\frac{21-19}{19.21}\right)\times462-x=19\)
\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+\frac{1}{17}-\frac{1}{19}+\frac{1}{19}-\frac{1}{21}\right)\times462-x=19\)
\(\left(\frac{1}{11}-\frac{1}{21}\right)\times462-x=19\)
\(\frac{10}{231}\times462-x=19\)
\(20-x=19\)
\(x=20-19\)
\(x=1\)
2.b \(187-[[497-(8\times x+11)\div x]\div3-78]=150\)
\(187-[[497-(\frac{8\times x}{x}+\frac{11}{x})]:3-78]=150\)
\(187-[(497-8-\frac{11}{x}):3-78]=150\)
\(187-[(489-\frac{11}{x}):3-78]=150\)
\(187-[\frac{489}{3}-\frac{33}{x}-78]=150\)
\(187-[163-\frac{33}{x}-78]=150\)
\(187-85+\frac{33}{x}=150\)
\(102+\frac{33}{x}=150\)
\(\frac{33}{x}=150-102\)
\(\frac{33}{x}=48\)
\(x=\frac{48}{33}=\frac{16}{11}\)
X=21
nha bạn
~~~~~~~~~~~ai đi ngang qua nhớ để lại k ~~~~~~~~~~~~~
~~~~~~~~~~~~ Chúc bạn sớm kiếm được nhiều điểm hỏi đáp ~~~~~~~~~~~~~~~~~~~
~~~~~~~~~~~ Và chúc các bạn trả lời câu hỏi này kiếm được nhiều k hơn ~~~~~~~~~~~~
a: \(1968\cdot15+1968\cdot84+1968\)
\(=1968\left(15+84+1\right)\)
\(=1968\cdot100=196800\)
b: \(6412+5378+3582+4628\)
\(=\left(6412+4628\right)+\left(5378+3582\right)\)
\(=11040+8960=20000\)
c: \(178\cdot101-178\)
\(=178\cdot101-178\cdot1\)
\(=178\left(101-1\right)=178\cdot100=17800\)
d: \(153\cdot8+153+153\)
\(=153\left(8+1+1\right)\)
\(=153\cdot10=1530\)
Ta có:
\(\frac{x-2}{255}=\frac{114}{153}\)
\(\Rightarrow\left(x-2\right).153=114.255\)
\(\Rightarrow\left(x-2\right).153=29070\)
\(\Rightarrow x-2=29070:153\)
\(\Rightarrow x-2=190\)
\(\Rightarrow x=190+2\)
\(\Rightarrow x=192\)
Vậy x = 192
\(\frac{x-2}{255}=\frac{114}{153}\)
\(\Rightarrow\left(x-2\right).153=255.114\)
\(\Rightarrow\left(x-2\right).153=29070\)
\(\Rightarrow x-2=29070:153\)
\(\Rightarrow x-2=190\)
\(\Rightarrow x=190+2=192\)
Vậy \(x=192\)
k mk nhé
*19,96+4,19-24,15:(1/4-1/4) *252/x=84/97
=19,96+4,19-24,15:0 x=252x97:84
=19,96+4,19-0 x=291
=24,15-0 * x-2/255=114/153
=24,15 x-2/255=38/51
x=38/51+2/255
x=64/85
a ) ko rõ đề
b )\(\frac{252}{x}=\frac{84}{97}\)
=> 252 . 97 = x . 84
=> x . 84 = 24 444
x = 24 444 : 84
x = 291
Vậy x = 291
c ) x - \(\frac{2}{255}=\frac{114}{153}\)
x = 114/153 + 2/255
x = 64/85
Vậy x = 64/85