\(\frac{213213213-213213+213213213213}{142142142-142142+142142142142}\)
Tính nhanh
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\(\frac{213213213:1001001-213213:1001+213213213213:1001001001}{142142142:1001001-142142:1001+142142142142:1001001001}\)
= \(\frac{213-213+213}{142-142+142}\)
=\(\frac{213}{142}\)
\(\frac{213213213-213213+213213213213}{142142142-142142+142142142142}\)
\(=\frac{213.\left(1001001-1001+1001001001\right)}{142.\left(1001001-1001+1001001001\right)}\)
\(=\frac{213}{142}\)
\(=\frac{3}{2}\)
~ Ủng hộ nhé
Phần A hình như sai đầu bài , mình sửa lại và làm luôn nhé :
A = ( 2 + 4 + 6 + 8 .... + 100 ) x ( 142142 x 143 - 143143 x 142 )
A = ( 2 + 4 + 6 + 8 + ... + 100 ) x ( 142 x 1001 x 143 - 143 x 1001 x 142 )
A = ( 2 + 4 + 6 + 8 + .. + 100 ) x 0
A = 0
B = ( 630 - 315 x 2 ) : ( 1 + 2 + 3 + ... + 1000 )
B = ( 630 - 630 ) : ( 1 + 2 + 3 + ... + 100 )
B = 0 : ( 1 + 2 + 3 + ... + 100 )
B = 0
a) 213213/104104 = 213/104 ; 137137/70070 = 137/70
2 = 208/104 < 213/104 ; 2 = 140/70 > 137/70
=> 213/104 > 137/70 => 213213/104104 > 137137/70070
b) 1 - 21/52 = 31/52 = 310/520
1 - 213/523 = 310/523
Mà 310/520 > 310/523 => 21/52 < 213/523
a, >
b, <
~~ tk mk nha ~~
Ai tk mk mk tk lại ~!~ ^^
kb nha ~ n_n
\(\frac{3232}{1717}=\frac{32}{17}\)
\(\frac{72}{120}=\frac{3}{5}\)
\(\frac{213213}{405405}=\frac{213}{405}\)
TK MÌNH NHÉ
3232/1717=32/17
72/120=3/5
213213/405405=213/405
k nha chúc bn hok tốt !!!
Ta có :
\(A=\frac{3}{1.3}+\frac{3}{3.5}+\frac{3}{5.7}+...+\frac{3}{49.51}\)
\(A=\frac{3}{2}\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{49.51}\right)\)
\(A=\frac{3}{2}\left(\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{49}-\frac{1}{51}\right)\)
\(A=\frac{3}{2}\left(1-\frac{1}{51}\right)\)
\(A=\frac{3}{2}.\frac{50}{51}\)
\(A=\frac{25}{17}\)
Vậy \(A=\frac{25}{17}\)
Chúc bạn học tốt ~
\(A=\frac{3}{1.3}+\frac{3}{3.5}+\frac{3}{5.7}+...+\frac{3}{49.51}\)
\(A=\frac{3}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{49}-\frac{1}{51}\right)\)
\(A=\frac{3}{2}\left(1-\frac{1}{51}\right)\)
\(A=\frac{3}{2}.\frac{50}{51}\)
\(A=\frac{25}{17}\)
\(B=\frac{21}{4}\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{3030}+\frac{3333}{4242}\right)\)
\(B=\frac{21}{4}\left(\frac{33}{12}+\frac{33}{20}+\frac{33}{30}+\frac{33}{42}\right)\)
\(B=\frac{21}{4}\left(\frac{33}{3.4}+\frac{33}{4.5}+\frac{33}{5.6}+\frac{33}{6.7}\right)\)
\(B=\frac{21}{4}.33.\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\right)\)
\(B=\frac{21}{4}.33.\left(\frac{1}{3}-\frac{1}{7}\right)\)
\(B=\frac{21}{4}.33.\frac{4}{21}\)
\(B=\left(\frac{21}{4}.\frac{4}{21}\right).33\)
\(B=33\)
\(C=\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{97.99}\)
\(C=\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{97}-\frac{1}{99}\right)\)
\(C=\frac{1}{2}\left(1-\frac{1}{99}\right)\)
\(C=\frac{1}{2}.\frac{98}{99}\)
\(C=\frac{49}{99}\)
\(\frac{1\times2\times25}{6\times5\times7}\)\(=\frac{1\times2\times5\times5}{2\times3\times5\times7}=\frac{5}{3\times7}=\frac{5}{21}\)
1/6×2/5×25/7=
rut gon:25(tử)÷5 (mâu), 6 (tử)÷2 (mau)
được
1/3×1/1×5/7=5/21
\(\frac{2}{1\times3}+\frac{2}{3\times5}+\frac{2}{5\times7}+\frac{2}{7\times9}\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}\)
\(=1-\frac{1}{9}=\frac{8}{9}\)
\(\frac{2}{1\times3}+\frac{2}{3\times5}+\frac{2}{5\times7}+\frac{2}{7\times9}\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}\)
\(=1+\left(\frac{1}{3}-\frac{1}{3}\right)+\left(\frac{1}{5}-\frac{1}{5}\right)+\left(\frac{1}{7}-\frac{1}{7}\right)-\frac{1}{9}\)
\(=1-\frac{1}{9}=\frac{8}{9}\)
~ Hok tốt ~
\(\frac{3}{2}\)
chúc bạn hk tốt nhé!!(nhớ k cho tui)
bằng 213/142 = 3/2 nha