tim x
\(\frac{25-x}{56}=\frac{6}{16}\)
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25-x/56 = 6/16
=> 2.(25-x)/112=7.6/112
=> 2.(25-x)= 42
=> 50 - 2x = 42
=> -2x = 50 - 42
=> -2x = 8
=> x = 8:(-2)
=> x = 4
\(\frac{25-x}{56}=\frac{6}{16}\)
\(\frac{25-x}{56}=\frac{3}{8}\)
\(\frac{25-x}{56}=\frac{21}{56}\)
\(\Rightarrow25-x=21\)
\(\Rightarrow x=25-21\)
\(\Rightarrow x=4\)
Vậy x=4
=>(25-x)16=6x56=280
25-x=17.5
x=7.5=15/2
vậy x=15/2
Theo đề ta có: \(\frac{25-x}{56}=\frac{6}{16}\)
Ta rút gọn: \(\frac{25-x}{56}=\frac{3}{8}\)
\(\Leftrightarrow\)25 -x . 8 = 56 . 3
\(\Rightarrow\)25 - x . 8 = 168
\(\Rightarrow\)25 - x = 168 : 8
\(\Rightarrow\)25 - x = 21
\(\Rightarrow\) - x = 21 - 25
\(\Rightarrow\) - x = -4
\(\Rightarrow\) x = 4
Vậy x = 4.
\(\frac{25-x}{56}=\frac{6}{16}\)
\(\Rightarrow\frac{25-x}{56}=\frac{3}{8}\)
\(\Rightarrow\left(25-x\right).8=56.3\)
\(\Rightarrow25.8-8x=168\)
\(\Rightarrow200-8x=168\)
\(\Rightarrow8x=200-168\)
\(\Rightarrow8x=32\)
\(\Rightarrow x=32:8\)
\(\Rightarrow x=4\)
Tham khảo nha !!!
Cách này dễ hơn nèk :
\(\frac{25-x}{56}=\frac{6}{16}\)
\(\Leftrightarrow\)\(\frac{25-x}{56}=\frac{3}{8}\)
\(\Leftrightarrow\)\(\frac{25-x}{56}=\frac{21}{56}\)
\(\Leftrightarrow\)\(25-x=21\)
\(\Leftrightarrow\)\(x=25-21\)
\(\Leftrightarrow\)\(x=4\)
Vậy \(x=4\)
Chúc bạn học tốt ~
\(\left(x-2011\right)\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)=\frac{16}{9}\)
\(\left(x-2011\right)\cdot\frac{2}{9}=\frac{16}{9}\)
\(x-2011=8\)
\(x=2019\)
\(\frac{x-2011}{12}+\frac{x-2011}{20}+\frac{x-2011}{30}+\frac{x-2011}{42}+\frac{x-2011}{56}+\frac{x-2011}{72}=\frac{16}{9}\)
\(\left(x-2011\right)\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\right)=\frac{16}{9}\)
\(\left(x-2011\right)\left(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\right)=\frac{16}{9}\)
\(\left(x-2011\right)\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{8}-\frac{1}{9}\right)=\frac{16}{9}\)
\(\left(x-2011\right)\left(\frac{1}{3}-\frac{1}{9}\right)=\frac{16}{9}\)
\(\left(x-2011\right)\frac{2}{9}=\frac{16}{9}\)
\(x-2011=8\Rightarrow x=2019\)
a) \(\left(\frac{1}{16}\right)^x=\left(\frac{1}{2}\right)^{10}\)
\(\left(\frac{1}{2}\right)^{4x}=\left(\frac{1}{2}\right)^{10}\)
\(\Rightarrow4x=10\)
x = 2,5
I x - 1/6 I - 6/16 = 25%
=> I x - 1/6 I- 6/16 = 1/4
=>I x - 1/6 I = 5/8
\(\Rightarrow\orbr{\begin{cases}x-\frac{1}{6}=\frac{5}{8}\\x-\frac{1}{6}=-\frac{5}{8}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{19}{24}\\x=-\frac{11}{24}\end{cases}}\)
vậy x = 19/24 , x = -11/24
\(\left|x-\frac{1}{6}\right|-\frac{6}{16}=25\%\)
\(\left|x-\frac{1}{6}\right|-\frac{3}{8}=\frac{2}{8}\)
\(\left|x-\frac{1}{6}\right|=\frac{2}{8}+\frac{3}{8}\)
\(\left|x-\frac{1}{6}\right|=\frac{5}{8}\)
=> 2 trường hợp:
1 là \(x-\frac{1}{6}=\frac{5}{8}\)
2 là \(x-\frac{1}{6}=\frac{-5}{8}\)
Trường hợp 1:\(x=\frac{5}{8}+\frac{1}{6}=\frac{19}{24}\)
Trường hợp 2:\(x=\frac{-5}{8}+\frac{1}{6}=\frac{-11}{24}\)
Hội con 🐄 chúc bạn học tốt!!!
25 - x / 56 = 6/16
( 25 - x ) : 56 = 6/16
25 - x = 6/16 x 56
25 - x = 21
x = 25 - 21
x = 4
\(\frac{25-x}{56}=\frac{6}{16}\)
\(\frac{x}{56}=25-\frac{6}{16}\)
\(\frac{x}{56}=24\frac{5}{8}\)
\(\frac{x}{56}=24\frac{35}{56}\)
\(\frac{x}{56}=\frac{24\cdot56+35}{56}\)
\(\frac{x}{56}=\frac{1379}{56}\)
Vậy số cần tìm là \(1379\)