Question

[Chubby Lê]

(3/4.x-1/2)² - 1/64 = 0

Dấu "/" là phần nhé :))

Mn giải nhanh hộ mình. Cảm ơn!

Answer 1

[Phùng Minh Quân]

Ta có : 

\(\left(\frac{3}{4}x-\frac{1}{2}\right)^2-\frac{1}{64}=0\)

\(\Leftrightarrow\)\(\left(\frac{3}{4}x-\frac{1}{2}\right)^2=\frac{1}{64}\)

\(\Leftrightarrow\)\(\left(\frac{3}{4}x-\frac{1}{2}\right)^2=\frac{1^2}{8^2}\)

\(\Leftrightarrow\)\(\left(\frac{3}{4}x-\frac{1}{2}\right)^2=\left(\frac{1}{8}\right)^2\)

\(\Leftrightarrow\)\(\frac{3}{4}x-\frac{1}{2}=\frac{1}{8}\)

\(\Leftrightarrow\)\(\frac{3}{4}x=\frac{1}{8}+\frac{1}{2}\)

\(\Leftrightarrow\)\(\frac{3}{4}x=\frac{5}{8}\)

\(\Leftrightarrow\)\(x=\frac{5}{8}:\frac{3}{4}\)

\(\Leftrightarrow\)\(x=\frac{5}{8}.\frac{4}{3}\)

\(\Leftrightarrow\)\(x=\frac{5}{2}.\frac{1}{3}\)

\(\Leftrightarrow\)\(x=\frac{5}{6}\)

Vậy \(x=\frac{5}{6}\)

Chúc bạn học tốt ~ 

Answer 2

[()]

\(\left(\frac{3}{4}.x-\frac{1}{2}\right)^2-\frac{1}{64}=0\)

\(\left(\frac{3}{4}.x-\frac{1}{2}\right)^2=0+\frac{1}{64}=\frac{1}{64}\)

\(\left(\frac{3}{4}.x-\frac{1}{2}\right)^2=\left(\frac{1}{8}\right)^2\)

=>\(\frac{3}{4}.x-\frac{1}{2}=\frac{1}{8}\)

\(\frac{3}{4}.x=\frac{1}{8}+\frac{1}{2}\)

\(\frac{3}{4}.x=\frac{5}{8}\)

\(x=\frac{5}{8}:\frac{3}{4}\)

\(x=\frac{5}{6}\)