5x230x318-4x320x227
5x29x219x319-7x229x318
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\(\frac{3}{4}+x\div\frac{3}{8}=1,5\)
\(x\div\frac{3}{8}=1,5-\frac{3}{4}\)
\(x\div\frac{3}{8}=\frac{3}{4}\)
\(x=\frac{3}{4}\times\frac{3}{8}\)
\(x=\frac{9}{32}\)
3/4 + x : 3/8 = 1,5
<=> 3/4 + x : 3/8 = 3/2
x : 3/8 = 3/2 - 3/4
x : 3/8 = 6/4 - 3/4
x : 3/8 = 3/4
x = 3/4 . 3/8
x = 9/32
a: \(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}\)
b: \(\dfrac{45^{10}\cdot5^{20}}{75^{15}}=\dfrac{5^{30}\cdot3^{20}}{3^{15}\cdot5^{30}}=3^5\)
a)\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}=1024\)
b)\(\dfrac{45^{10}\cdot5^{20}}{75^{15}}=\dfrac{9^{10}\cdot5^{30}}{3^{15}\cdot5^{30}}=\dfrac{3^{20}}{3^{15}}=3^5=243\)
3/4×13/21-3/21×7/4+15/4×3/21
= 3/21 x 13/4 - 3/21 x 7/4 + 15/4 x 3/21
= 3/21 x ( 13/4 - 7/4 + 15/4 )
= 3/21 x 21/4
= 3/4
3/4 x 13/21 - 3/21 x 7/4 + 15/4 x 3/21
= 3/21 x 13/4 - 3/21 x 7/4 + 15/4 + 3/21
= 3/21 x ( 13/4 - 7/4 + 15/4 )
= 3/21 x 21/4
= 3/4
\(\left(2x-3\right):\frac{2}{39}=\frac{5}{39}\)
=> \(2x-3=\frac{5}{39}\cdot\frac{2}{39}=\frac{10}{39}\)
=> \(2x=\frac{10}{39}+3\)
=> \(2x=\frac{127}{39}\)
=> \(x=\frac{127}{39}:2=\frac{127}{39\cdot2}=\frac{127}{78}\)
\(\left(2x-3\right):\frac{2}{39}=\frac{5}{39}\)
\(\Leftrightarrow2x-3=\frac{5}{39}.\frac{2}{39}\)
\(\Leftrightarrow2x-3=\frac{10}{1521}\)
\(\Leftrightarrow2x=\frac{4573}{1521}\)
\(\Leftrightarrow x=\frac{4573}{3042}\)
\(\frac{5.2^{30}.3^{18}-4.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{5.2^{28}.2^2.3^{18}-4.3^{18}.3^2.2^{27}}{5.2^{28}.3^{18}.3-7.2^{27}.2^2.3^{18}}\)
\(=\frac{3^{18}.\left(5.2^{28}.4-4.9.2^{27}\right)}{3^{18}.\left(5.3.2^{28}-7.2^{27}.4\right)}\)
\(=\frac{20.2^{28}-9.2.2.2^{27}}{15.2^{28}-14.2.2^{27}}\)
\(=\frac{2^{28}.20-18.2^{28}}{15.2^{28}-14.2^{28}}\)
\(=\frac{2^{28}.\left(20-18\right)}{2^{28}.\left(15-14\right)}\)
\(=\frac{2^{28}.2}{2^{28}1}\)
\(=2\)
=2/1 = 2