\(1+1=2\)

1+1=2 nha bạn

anh em copy link này lên youtube xem rồi đăng kí nhe cảm ơn

https://www.youtube.com/shorts/hhpTDItpePY

cảm ơn rất nhiều luôn

thì s?????

hack ak

vl 1025 % WTFFFF

NGUUUUUUUU

Tu " tham " la cach noi giam noi tranh , lam giam noi dau thuong mat mat cua Bac , dong thoi khang dinh bac van con song mai trong trai tim cua moi nguoi

-nói giảm nói tránh"thăm"

tác dụng "giảm bớt nỗi đau thương mất mát,đồng thời bất tử hóa hình tượng bác.

2. a) \(B=\left(\dfrac{\sqrt{x}+2}{x-2\sqrt{x}+1}-\dfrac{\sqrt{x}-2}{x-1}\right)\cdot\dfrac{\left(\sqrt{x}-1\right)^2}{2\sqrt{x}}\)

\(B=\left[\dfrac{\sqrt{x}+2}{\left(\sqrt{x}-1\right)^2}-\dfrac{\sqrt{x}-2}{x-1}\right]\cdot\dfrac{\left(\sqrt{x}-1\right)^2}{2\sqrt{x}}\)

\(B=\left[\dfrac{\left(\sqrt{x}+2\right)\left(x-1\right)}{\left(\sqrt{x}-1\right)^2\left(x-1\right)}-\dfrac{\left(\sqrt{x}-2\right)\left(x-2\sqrt{x}+1\right)}{\left(\sqrt{x}-1\right)^2\left(x-1\right)}\right]\cdot\dfrac{\left(\sqrt{x}-1\right)^2}{2\sqrt{x}}\)

\(B=\left[\dfrac{x\sqrt{x}-\sqrt{x}+2x-2}{\left(\sqrt{x}-1\right)^2\left(x-1\right)}-\dfrac{x\sqrt{x}-4x+5\sqrt{x}-2}{\left(\sqrt{x}-1\right)^2\left(x-1\right)}\right]\cdot\dfrac{\left(\sqrt{x}-1\right)^2}{2\sqrt{x}}\)

\(B=\dfrac{x\sqrt{x}-\sqrt{x}+2x-2-x\sqrt{x}+4x-5\sqrt{x}+2}{\left(\sqrt{x}-1\right)^2\left(x-1\right)}\cdot\dfrac{\left(\sqrt{x}-1\right)^2}{2\sqrt{x}}\)

\(B=\dfrac{6x-6\sqrt{x}}{\left(\sqrt{x}-1\right)^2\left(x-1\right)}\cdot\dfrac{\left(\sqrt{x}-1\right)^2}{2\sqrt{x}}\)

\(B=\dfrac{2\sqrt{x}\left(3\sqrt{x}-3\right)}{\left(\sqrt{x}-1\right)^2\left(x-1\right)}\cdot\dfrac{\left(\sqrt{x}-1\right)^2}{2\sqrt{x}}\)

\(B=\dfrac{3\sqrt{x}-3}{x-1}\)

\(B=\dfrac{3\left(\sqrt{x}-1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

\(B=\dfrac{3}{\sqrt{x}+1}\)

b) \(B=1\Leftrightarrow\dfrac{3}{\sqrt{x}+1}=1\)

\(\Leftrightarrow\sqrt{x}+1=3\)

\(\Leftrightarrow\sqrt{x}=2\)

\(\Leftrightarrow x=4\)

\(n_{C_2H_4}=\frac{V}{22,4}=\frac{6,72}{22,4}=0,3\)(mol)

PTHH : C₂H₄ + Br₂ ----> C₂H₄Br₂ 

               1        :   1        :      1

         0,3 (mol)                 0,3 (mol)

Khối lượng C₂H₄Br₂ thu được : 

\(m=n.M=0,3.188=56,4\left(g\right)\)

\(3x^2-5x+3=0\)

\(\Delta=b^2-4ac\)

   \(=\left(-5\right)^2-4.3.3\)

   \(=-11< 0\)

=> phương trình vô nghiệm