`Answer:`

\(222^{333}=\left(222^3\right)^{111}=[\left(2.111\right)^3]^{111}=\left(8.111^3\right)^{111}=\left(888.111^2\right)^{111}\)

\(333^{222}=\left(333^2\right)^{111}=[\left(3.111\right)^2]^{111}=\left(9.111^2\right)^{111}\)

Mà \(\left(888.111^2\right)>\left(9.111^2\right)^{111}\Rightarrow222^{333}>333^{222}\)

MÌNH TÌM ĐƯỢC ĐÓ LÀ

3;13 THÔI À

\(B=\dfrac{1}{7}\left(\dfrac{1}{2}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{16}+...+\dfrac{1}{107}-\dfrac{1}{114}\right)\)

\(=\dfrac{1}{7}\left(\dfrac{1}{2}-\dfrac{1}{114}\right)=\dfrac{4}{57}\)

a, đk : x khác 10 \(\Rightarrow x-10=26\Leftrightarrow x=36\left(tm\right)\)

b, đk : x khác 2 

\(\left(x-2\right)^2=100\Leftrightarrow\left[{}\begin{matrix}x-2=10\\x-2=-10\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-8\end{matrix}\right.\left(tm\right)\)

\(\dfrac{2x+4}{2x+1}=\dfrac{2x+1+3}{2x+1}=1+\dfrac{3}{2x+1}\Rightarrow2x+1\inƯ\left(3\right)=\left\{\pm1;\pm3\right\}\)

Nguyễn Huy Tú biến đổi sai

\(\frac{x+2}{2x+1}=\frac{2.\left(x+2\right)}{2.\left(2x+1\right)}=\frac{2x+4}{4x+2}\)Chứ

là so sánh hay nhân hay chia thế bạn ?