a) ( 7/9+3/7 ) + 2/9 =
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\(4,7\div0,25+5,3\times4+120\%\times4\)
\(=4,7\times4+5,3\times4+1,2\times4\)
\(=4\times\left(4,7+5,3+1,2\right)\)
\(=4\times11,2\)
\(=44,8\)
Số kg gạo đã chuyển:
11150 × 3 = 33450 (kg)
Số kg gạo còn lại trong kho:
54357 - 33450 = 20907 (kg)
3 lần chuyển số kg gạo là
\(11150\times3=33450\) (kg)
Sau 3 lần chuyển, trong kho còn lại số kg gạo là
\(54357-33450=20907\) (kg)
\(\dfrac{x-1}{13}-\dfrac{2x-13}{15}=\dfrac{3x-15}{27}-\dfrac{4x-27}{29}\)
=>\(\left(\dfrac{x-1}{13}-1\right)-\left(\dfrac{2x-13}{15}-1\right)=\left(\dfrac{3x-15}{27}-1\right)-\left(\dfrac{4x-27}{29}-1\right)\)
=>\(\dfrac{x-14}{13}-\dfrac{2x-28}{15}-\dfrac{3x-42}{27}+\dfrac{4x-56}{29}=0\)
=>\(\left(x-14\right)\left(\dfrac{1}{13}-\dfrac{2}{15}-\dfrac{3}{27}+\dfrac{4}{29}\right)=0\)
=>x-14=0
=>x=14
\(A=\dfrac{1}{4}+\dfrac{1}{16}+\dfrac{1}{36}+\dfrac{1}{64}+...+\dfrac{1}{256}+\dfrac{1}{324}\)
\(A=\dfrac{1}{2\times2}+\dfrac{1}{4\times4}+\dfrac{1}{6\times6}+....+\dfrac{1}{16\times16}+\dfrac{1}{18\times18}\)
\(2A=\dfrac{2}{2\times2}+\dfrac{2}{4\times4}+\dfrac{2}{6\times6}+....+\dfrac{2}{16\times16}+\dfrac{2}{18\times18}\)
\(2A< \dfrac{1}{2}+\dfrac{2}{2\times4}+\dfrac{2}{4\times6}+\dfrac{2}{6\times8}+....+\dfrac{2}{14\times16}+\dfrac{2}{16\times18}\)
\(2A< \dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{6}+....+\dfrac{1}{14}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{18}\)
\(2A< 1-\dfrac{1}{18}< 1\)
\(A< \dfrac{1}{2}< 1\)
\(\left(\dfrac{7}{9}+\dfrac{3}{7}\right)+\dfrac{2}{9}=\dfrac{7}{9}+\dfrac{3}{7}+\dfrac{2}{9}=\left(\dfrac{7}{9}+\dfrac{2}{9}\right)+\dfrac{3}{7}\)
\(=1+\dfrac{3}{7}\)
\(=\dfrac{10}{7}\)
$(\frac79+\frac37)+\frac29$
$=(\frac79+\frac29)+\frac37$
$=1+\frac37$
$=\frac{10}{7}$