
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


\(\frac{\frac{125}{8}+\frac{125}{97}+\frac{125}{576}+\frac{250}{991}}{\frac{25}{8}+\frac{25}{97}+\frac{25}{576}+\frac{50}{991}}\)=\(\frac{250.\left(\frac{1}{8}+\frac{1}{97}+\frac{1}{576}+\frac{1}{991}\right)}{50.\left(\frac{1}{8}+\frac{1}{97}+\frac{1}{576}+\frac{1}{991}\right)}\)=\(\frac{250}{50}\)=5

Vì \(-3⋮\left(x-2\right)\)
\(\Rightarrow x-2\inƯ\left(3\right)\)
Vậy các \(Ư\left(3\right)\)là \(3;1;-1;-3\)
Vậy \(x-2\in\left\{3,1;-1;-3\right\}\)
Ta có
1) \(x-2=3\)
\(x=5\)
2) \(x-2=1\)
\(x=3\)
3) \(x-2=-1\)
\(x=1\)
4) \(x-2=-3\)
\(x=-5\)
Vậy \(x\in\left\{-5;3;5;1\right\}\)

\(12x-250=-3+125\)
\(12x-250=122\)
\(12x=372\)
\(x=31\)
Vậy \(x=31.\)
12 . x - 250 = -3 + 125
12 . x - 250 = 122
12 . x = 122 + 250
12 . x = 372
x = 372 : 12
x = 31
vậy x = 31
bn k ch mk nha

\(E=250:\left\{175-\left[50+3.5^2\left(2014+2015^{40}\right)^0\right]\right\}\)
\(E=250:\left\{175-\left[50+3.5^2.1\right]\right\}\)
\(E=250:\left\{175-\left[50+75\right]\right\}\)
\(E=250:\left\{175-50-75\right\}\)
\(E=250:50=5\)( mk đổi dấu ngoặc xíu nha tại cho nó đỡ bị nhầm )
\(F=\left(6^{27}:6^{25}\right):\left\{780:\left[5.89-\left(125+5.7^2\right)+5.11\right]\right\}\)
\(F=6^2:\left\{780:\left[5.89-370+5.11\right]\right\}\)
\(F=6^2:\left\{780:\left[5.\left(89+11\right)-370\right]\right\}\)
\(F=36:\left\{780:\left[5.100-370\right]\right\}\)
\(F=36:\left\{780:\left[500-370\right]\right\}\)
\(F=36:\left\{780:130\right\}=36:6=6\)
cậu có thể tham khảo bài làm trên đây ạ, chúc cậu học tốt ^^

Bài 1:
\(a.\left(-356+57\right)-\left(27-356\right)=-356+57-27+356=\left(-356+356\right)+\left(57-27\right)=30\) \(b.125.\left(-24+24.225\right)=125.\left(-24+5400\right)=125.\left(-24\right)+125.5400=-3000+675000=672000\)
\(c.26.\left(-125\right)-125.\left(-36\right)=-125.\left(26-36\right)=-125.\left(-10\right)=1250\)
Bài 2:
\(a.\left(2x-4\right)^2=0\)
\(\Rightarrow2x-4=0\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
\(b.\frac{x+5}{x+3}=\frac{x+3+2}{x+3}=\frac{x+3}{x+3}+\frac{2}{x+3}=1+\frac{2}{x+3}\)
Để (x+5) chia hết cho (x+3) thì 2 phải chia hết cho (x+3)
\(\Rightarrow x+3\inƯ\left(2\right)=\left\{\pm1;\pm2\right\}\)
\(x+3=1\Rightarrow x=-2\)
\(x+3=-1\Rightarrow x=-4\)
\(x+3=2\Rightarrow x=-1\)
\(x+3=-2\Rightarrow x=-5\)
Vậy \(x\in\left\{-2;-4;-1;-5\right\}\)
Bài 2:
a)\(\left(2x-4\right)^2=0\)
\(\Leftrightarrow2x-4=0\)
\(\Leftrightarrow2x=4\Leftrightarrow x=2\)
b)\(\frac{x+5}{x+3}=\frac{x+3+2}{x+3}=\frac{x+3}{x+3}+\frac{2}{x+3}=1+\frac{2}{x+3}\in Z\)
Suy ra \(2⋮x+3\Rightarrow x+3\inƯ\left(2\right)=\left\{1;-1;2;-2\right\}\)
\(\Rightarrow x\in\left\{-2;-4;-1;-5\right\}\)

a) \(125\cdot\left(-24\right)+24\cdot225\)
\(=\left(225-125\right)\cdot24\)
\(=100\cdot24\)
\(=2400\)
b) \(26\cdot\left(-125\right)-125\cdot\left(-36\right)\)
\(=\left(36-26\right)\cdot125\)
\(=10\cdot125\)
\(=1250\)

`250 - 125 : x = 125`
`125 : x = 250 - 125`
`125 : x = 125`
`x = 125 : 125`
`x = 1`
Vậy ...
125
𝑥
=
125
x
125
=125
Nhân hai vế với
𝑥
x:
125
=
125
𝑥
125=125x
Chia hai vế cho 125:
𝑥
=
1
x=1
👉 Đáp án:
𝑥
=
1
x=1 ✅