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Mình đang gõ câu hỏi thì đứa em lớp 1 bấm linh tinh. Sorry nhiều, mình đã sửa rồi
Mình muốn hỏi cách làm, còn kết quả thì bấm máy tính cũng ra
ta có: \(1-\frac{5}{6}+\frac{7}{12}-\frac{9}{20}+\frac{11}{30}-\frac{13}{42}+\frac{15}{56}-\frac{17}{72}+\frac{19}{90}\)
\(=1-\frac{5}{2.3}+\frac{7}{3.4}-\frac{9}{4.5}+\frac{11}{5.6}-\frac{13}{6.7}+\frac{15}{7.8}-\frac{17}{8.9}+\frac{19}{9.10}\)
\(=1-\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{4}+\frac{1}{5}-\frac{1}{5}+\frac{1}{6}-\frac{1}{6}+\frac{1}{7}-\frac{1}{7}+\frac{1}{8}-\frac{1}{8}+\frac{1}{9}-\frac{1}{9}+\frac{1}{10}\)
\(=1-\frac{1}{2}+\frac{1}{10}=\frac{3}{5}\)
Nếu biết cách đăng hình vào câu trả lời thì mk sẽ đăng cách giải và đáp số, chứ mk ngại viết lắm
A = 1 - \(\dfrac{5}{6}\)+\(\dfrac{7}{12}\)-\(\dfrac{9}{20}\)+\(\dfrac{11}{30}\)-\(\dfrac{13}{42}\)+\(\dfrac{15}{56}\) - \(\dfrac{17}{72}\)+\(\dfrac{19}{90}\)+\(\dfrac{23}{132}\)-\(\dfrac{25}{156}\)
A = 1 - \(\dfrac{5}{2.3}\)+\(\dfrac{7}{3.4}\)-\(\dfrac{9}{4.5}\)+\(\dfrac{11}{5.6}\)-\(\dfrac{13}{6.7}\)+\(\dfrac{15}{7.8}\)-\(\dfrac{17}{8.9}\)+\(\dfrac{19}{9.10}\)+\(\dfrac{23}{11.12}\)-\(\dfrac{25}{12.13}\)
A = 1 - \(\dfrac{1}{2}-\dfrac{1}{3}\)+\(\dfrac{1}{3}+\dfrac{1}{4}\)-\(\dfrac{1}{4}-\dfrac{1}{5}\)+...+\(\dfrac{1}{11}+\dfrac{1}{12}\)- \(\dfrac{1}{12}-\dfrac{1}{13}\)
A = 1 - \(\dfrac{1}{2}\) - \(\dfrac{1}{13}\)
A = \(\dfrac{1}{2}\) - \(\dfrac{1}{13}\)
A = \(\dfrac{11}{26}\)
\(1-\dfrac{5}{6}+\dfrac{7}{12}-\dfrac{9}{20}+\dfrac{11}{30}-\dfrac{13}{42}+\dfrac{15}{56}-\dfrac{17}{72}+\dfrac{19}{90}\\ =1-\dfrac{5}{2\cdot3}+\dfrac{7}{3\cdot4}-\dfrac{9}{4\cdot5}+\dfrac{11}{5\cdot6}-\dfrac{13}{6\cdot7}+\dfrac{15}{7\cdot8}-\dfrac{17}{8\cdot9}+\dfrac{19}{9\cdot10}\\ =1-\left(\dfrac{5}{2}-\dfrac{5}{3}\right)+\left(\dfrac{7}{3}-\dfrac{7}{4}\right)-\left(\dfrac{9}{4}-\dfrac{9}{5}\right)+\left(\dfrac{11}{5}-\dfrac{11}{6}\right)-\left(\dfrac{13}{6}-\dfrac{13}{7}\right)+\left(\dfrac{15}{7}-\dfrac{15}{8}\right)-\left(\dfrac{17}{8}-\dfrac{17}{9}\right)+\left(\dfrac{19}{9}-\dfrac{19}{10}\right)\\ =1-\dfrac{5}{2}+\dfrac{5}{3}+\dfrac{7}{3}-\dfrac{7}{4}-\dfrac{9}{4}+\dfrac{9}{5}+\dfrac{11}{5}-\dfrac{11}{6}-\dfrac{13}{6}+\dfrac{13}{7}+\dfrac{15}{7}-\dfrac{15}{8}-\dfrac{17}{8}+\dfrac{17}{9}+\dfrac{19}{9}-\dfrac{19}{10}\\ =1-\dfrac{5}{2}+4-4+4-4+4-4+4-\dfrac{19}{10}\\ =1-\dfrac{5}{2}+4-\dfrac{19}{10}=\dfrac{3}{5}\)
Giải thích các bước giải:
1−56+712−920+1130−1342+1556−1772+1990−21110+231321-56+712-920+1130-1342+1556-1772+1990-21110+23132
=16+215+235+263+299+2313216+215+235+263+299+23132
=310+445+796310+445+796
=710+796710+796
=0,58(3)