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a: \(=23\cdot100+300=2600\)
b: \(=300:\left(4+6\right)-25=30-25=5\)
\(\left(-67\right)+125+\left(-33\right)+75\)
\(=\left[\left(-67\right)+\left(-33\right)\right]+\left(125+75\right)\)
\(=100+200=300\)
_______
\(86.\left(-108\right)+86.9-86\)
\(=86.\left[\left(-108\right)+9-1\right]\)
\(=86.\left(-100\right)=-8600\)
_______
\(23.\left(-16\right)-23.84+300\)
\(=23.\left[\left(-16\right)-84\right]+300\)
\(=23.\left(-100\right)+300\)
\(=-2300+300\)
\(=-2000\)
______
\(235-5\left[\left(5^3-3^3\right):14\right]\)
\(=235-5\left[\left(125-27\right):14\right]\)
\(=235-5\left[98:14\right]\)
\(=235-5.7\)
\(=235-35\)
\(=200\)
_______
\(95-\left(129-74\right):5+2022^0\)
\(=95-55:5+1\)
\(=95-11+1\)
\(=84+1=85\)
\(#NqHahh\)
a: \(=27+5^2-1=27+25-1=52-1=51\)
b: \(=320:\left\{180-36+8\cdot16+4\cdot12\right\}=320:320=1\)
a: \(=168:\left[180-\left(36+2^3\cdot8\right)\right]=168:80=\dfrac{21}{10}\)
b: =62-81-12+59-9
=50+50-81
=100-81
=19
c: \(=298\cdot198-298\cdot127+198\cdot127-198\cdot298\)
=127x(-100)=-12700
a) 3.5.15.9 = 3.5.5.3.3.3 = 34.52
b) 10.100.1000 = 10.10.10.10.10.10 = 106
c) 2.x.2.x.2.x = 23.x3
d) a3.a6.a9 = a3+6+9 = a18
e) x2.x.x5.x7.x8 = x2+1+5+7+8 = x23
f) 34.44 = (3.4)4 = 124
g) 23.84 = 23 . (23)4 = 23.212 = 215
b) \(|-2|^{300}=2^{300}=\left(2^3\right)^{100}=8^{100}\)
\(|-3|^{200}=3^{200}=\left(3^2\right)^{100}=9^{100}\)
Thấy 8<9 => \(8^{100}< 9^{100}\)=> \(|-2|^{300}< |-3|^{200}\)
a) TA CÓ
|-2|300=2300=22*150=(22)150=4150
mà |-4|150=4150
=>bằng nhau
b)TA CÓ
|-2|300=2300=23*100=(23)100=8100
mà |-3|200=3200=32*100=(32)100=9100
=>bé hơn
a/ \(2^{300}=\left(2^3\right)^{100}=8^{100}\)
\(3^{200}=\left(3^2\right)^{100}=9^{100}\)
Vì \(8^{100}< 9^{100}\Leftrightarrow2^{300}< ^{200}\)
b/ \(3^{450}=\left(3^3\right)^{150}=27^{150}\)
\(5^{300}=\left(5^2\right)^{300}=25^{150}\)
Vì \(27^{150}>25^{100}\Leftrightarrow3^{450}>5^{300}\)
a) ta có:
\(2^{300}=\left(2^3\right)^{100}=8^{100}\\ 3^{200}=\left(3^2\right)^{100}=9^{100}\)
ta thấy: \(9^{100}>8^{100}\) nên \(2^{300}< 3^{200}\)
vậy \(2^{300}< 3^{200}\)
b) ta có:
\(3^{450}=\left(3^3\right)^{150}=27^{150}\\ 5^{300}=\left(5^2\right)^{150}=25^{150}\)
\(27^{150}>25^{150}\Rightarrow3^{450}>5^{300}\)
vậy \(3^{450}>5^{300}\)
23.16 + 23.84 - 300
= 23.(16+ 84) - 300
= 23. 100 - 3 x 100
= 100 x (23 - 3)
= 100 x 20
= 2000
23.16+23.84-300
=23.(16+84)-300
=23.100-300
=2300-300
=2000