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a, 3/4 và 4/5
\(\frac{3}{4}< \frac{4}{5}vì3.5< 4.4\)
b,2000/1000 và 2/5
ta có \(\frac{2000}{1000}=\frac{2}{1}>1\)và 2/5 < 1
Suy ra \(\frac{2000}{1000}>1>\frac{2}{5}\)
Vậy \(\frac{2000}{1000}>\frac{2}{5}\)
c,7/5 và 9/7
ta có \(\frac{7}{5}>\frac{9}{7}\)vì 7.7 > 5.9
a) 3/4 và 4/5
1 - 3/4 = 1/4
1 - 4/5 = 1/5
Vì 1/4 > 1/5 nên 3/4 < 4/5
b) 2000/1000 và 2/5
2000/1000 > 1
2/5 < 1
2000/1000 > 1 > 2/5 nên 2000/1000 > 2/5
c) 7/5 và 9/7
7/5 - 1 = 2/5
9/7 - 1 = 2/7
Vì 2/5 > 2/7 nên 7/5 > 9/7
Chúc bạn học tốt.
bạn lấy chín chừ bốn nhân hai tương tự tám trừ năm bằng ba ra kết quả thì so sánh 2 số số giư nào to hơn số đó bé hơn
So sánh bằng phân số trung gian em nhé!
a; \(\dfrac{9}{4}\) > \(\dfrac{9}{5}\) > \(\dfrac{8}{5}\)
Vậy \(\dfrac{9}{4}\) > \(\dfrac{8}{5}\)
b; \(\dfrac{10}{3}\) > \(\dfrac{10}{7}\) > \(\dfrac{9}{7}\)
Vậy \(\dfrac{10}{3}\) > \(\dfrac{9}{7}\)
a; Cách một:
\(\dfrac{2}{9}\) = \(\dfrac{2\times2}{9\times2}\) = \(\dfrac{4}{18}\) < \(\dfrac{4}{10}\) Vậy \(\dfrac{2}{9}\) < \(\dfrac{4}{10}\)
\(\dfrac{4}{9}\) = \(\dfrac{4\times3}{9\times3}\) = \(\dfrac{12}{27}\); \(\dfrac{6}{10}\) = \(\dfrac{6\times2}{10\times2}\) = \(\dfrac{12}{20}\)
Vì \(\dfrac{12}{27}\) < \(\dfrac{12}{20}\) vậy \(\dfrac{4}{9}\) < \(\dfrac{12}{20}\)
\(\dfrac{3}{8}\) = \(\dfrac{3\times4}{8\times4}\) = \(\dfrac{12}{24}\); \(\dfrac{4}{7}\) = \(\dfrac{4\times3}{7\times3}\) = \(\dfrac{12}{21}\)
Vậy \(\dfrac{3}{8}\) < \(\dfrac{4}{7}\)
\(\dfrac{5}{9}\) = \(\dfrac{5\times7}{9\times7}\) = \(\dfrac{35}{63}\); \(\dfrac{7}{10}\) = \(\dfrac{7\times5}{10\times5}\) = \(\dfrac{35}{50}\)
Vì \(\dfrac{35}{63}\) < \(\dfrac{35}{50}\) vậy \(\dfrac{5}{9}\) < \(\dfrac{7}{10}\)
Cách hai:
a; \(\dfrac{2}{9}\) = \(\dfrac{2\times10}{9\times10}\) = \(\dfrac{20}{90}\); \(\dfrac{4}{10}\) = \(\dfrac{4\times9}{10\times9}\) = \(\dfrac{36}{90}\)
Vì \(\dfrac{20}{90}\) < \(\dfrac{36}{90}\) vậy \(\dfrac{2}{9}\) < \(\dfrac{4}{10}\)
b; \(\dfrac{4}{9}\) = \(\dfrac{4\times10}{9\times10}\) = \(\dfrac{40}{90}\); \(\dfrac{6}{10}\) = \(\dfrac{6\times9}{10\times9}\) = \(\dfrac{54}{90}\)
Vì \(\dfrac{40}{90}\) < \(\dfrac{54}{90}\) vậy \(\dfrac{4}{9}\) < \(\dfrac{6}{10}\)
c; \(\dfrac{3}{8}\) = \(\dfrac{3\times7}{8\times7}\) = \(\dfrac{21}{56}\); \(\dfrac{4}{7}\) = \(\dfrac{4\times8}{7\times8}\) = \(\dfrac{32}{56}\)
Vì \(\dfrac{21}{56}\) < \(\dfrac{32}{56}\) vậy \(\dfrac{3}{8}\) < \(\dfrac{4}{7}\)
d; \(\dfrac{5}{9}\) = \(\dfrac{5\times10}{9\times10}\) = \(\dfrac{50}{90}\); \(\dfrac{7}{10}\) = \(\dfrac{7\times9}{10\times9}\) = \(\dfrac{63}{90}\)
Vì \(\dfrac{50}{90}\) < \(\dfrac{63}{90}\) vậy \(\dfrac{5}{9}\) < \(\dfrac{7}{10}\)
a) \(\frac{7}{9}\)và \(\frac{11}{13}\)
Ta có : \(1-\frac{7}{9}=\frac{2}{9};1-\frac{11}{13}=\frac{2}{13}\)
Vì \(\frac{2}{9}>\frac{2}{13}\)nên \(\frac{7}{9}< \frac{11}{13}\).
b) \(\frac{125}{121}\)và \(\frac{413}{409}\)
Ta có : \(\frac{125}{121}-1=\frac{4}{121};\frac{413}{409}-1=\frac{4}{409}\)
Vì \(\frac{4}{121}>\frac{4}{409}\)nên \(\frac{125}{121}>\frac{413}{409}\)
c) \(\frac{8}{7}\)và \(\frac{4}{5}\)
Vì \(\frac{8}{7}>1;1>\frac{4}{5}\)nên \(\frac{8}{7}>\frac{4}{5}\)
d) \(\frac{46}{35}\)và \(\frac{41}{38}\)
Chon phân số trung gian là : \(\frac{46}{38}\)
Vì \(\frac{46}{35}>\frac{46}{38};\frac{46}{38}>\frac{41}{38}\)nên \(\frac{46}{35}>\frac{41}{38}\)
a; Cách một:
\(\dfrac{2}{9}\) = \(\dfrac{2\times2}{9\times2}\) = \(\dfrac{4}{18}\) < \(\dfrac{4}{10}\) Vậy \(\dfrac{2}{9}\) < \(\dfrac{4}{10}\)
\(\dfrac{4}{9}\) = \(\dfrac{4\times3}{9\times3}\) = \(\dfrac{12}{27}\); \(\dfrac{6}{10}\) = \(\dfrac{6\times2}{10\times2}\) = \(\dfrac{12}{20}\)
Vì \(\dfrac{12}{27}\) < \(\dfrac{12}{20}\) vậy \(\dfrac{4}{9}\) < \(\dfrac{12}{20}\)
\(\dfrac{3}{8}\) = \(\dfrac{3\times4}{8\times4}\) = \(\dfrac{12}{24}\); \(\dfrac{4}{7}\) = \(\dfrac{4\times3}{7\times3}\) = \(\dfrac{12}{21}\)
Vậy \(\dfrac{3}{8}\) < \(\dfrac{4}{7}\)
\(\dfrac{5}{9}\) = \(\dfrac{5\times7}{9\times7}\) = \(\dfrac{35}{63}\); \(\dfrac{7}{10}\) = \(\dfrac{7\times5}{10\times5}\) = \(\dfrac{35}{50}\)
Vì \(\dfrac{35}{63}\) < \(\dfrac{35}{50}\) vậy \(\dfrac{5}{9}\) < \(\dfrac{7}{10}\)
Cách hai:
a; \(\dfrac{2}{9}\) = \(\dfrac{2\times10}{9\times10}\) = \(\dfrac{20}{90}\); \(\dfrac{4}{10}\) = \(\dfrac{4\times9}{10\times9}\) = \(\dfrac{36}{90}\)
Vì \(\dfrac{20}{90}\) < \(\dfrac{36}{90}\) vậy \(\dfrac{2}{9}\) < \(\dfrac{4}{10}\)
b; \(\dfrac{4}{9}\) = \(\dfrac{4\times10}{9\times10}\) = \(\dfrac{40}{90}\); \(\dfrac{6}{10}\) = \(\dfrac{6\times9}{10\times9}\) = \(\dfrac{54}{90}\)
Vì \(\dfrac{40}{90}\) < \(\dfrac{54}{90}\) vậy \(\dfrac{4}{9}\) < \(\dfrac{6}{10}\)
c; \(\dfrac{3}{8}\) = \(\dfrac{3\times7}{8\times7}\) = \(\dfrac{21}{56}\); \(\dfrac{4}{7}\) = \(\dfrac{4\times8}{7\times8}\) = \(\dfrac{32}{56}\)
Vì \(\dfrac{21}{56}\) < \(\dfrac{32}{56}\) vậy \(\dfrac{3}{8}\) < \(\dfrac{4}{7}\)
d; \(\dfrac{5}{9}\) = \(\dfrac{5\times10}{9\times10}\) = \(\dfrac{50}{90}\); \(\dfrac{7}{10}\) = \(\dfrac{7\times9}{10\times9}\) = \(\dfrac{63}{90}\)
Vì \(\dfrac{50}{90}\) < \(\dfrac{63}{90}\) vậy \(\dfrac{5}{9}\) < \(\dfrac{7}{10}\)
ta thấy 7/10 có mẫu số hơn tử số nhiều hơn số đó là bé nhất. còn 3/4 và 5/6 thì số 3/4 lớn hơn. cứ vẽ sơ đồ hiểu liền
a)>
b)>
So sánh bằng phân số trung gian em nhé!
a; \(\dfrac{9}{4}\) > \(\dfrac{9}{5}\) > \(\dfrac{8}{5}\)
Vậy \(\dfrac{9}{4}\) > \(\dfrac{8}{5}\)
b; \(\dfrac{10}{3}\) > \(\dfrac{10}{7}\) > \(\dfrac{9}{7}\)
Vậy \(\dfrac{10}{3}\) > \(\dfrac{9}{7}\)