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Câu a : - 891 / 100 = - 8 , 91
Câu b : - 21 / 4 = - 5 , 25
Câu c : 5 / 2 = 2 , 5
Câu d : 4096 / 387 = 11 ( đã làm tròn )
Câu e : - 3 / 2 = - 1 , 5
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Bài 1:
a, Ta có: \(\dfrac{27}{23}+\dfrac{5}{21}-\dfrac{4}{23}+\dfrac{16}{21}+\dfrac{1}{2}\)
= \(\left(\dfrac{27}{23}-\dfrac{4}{23}\right)+\left(\dfrac{5}{21}+\dfrac{16}{21}\right)+\dfrac{1}{2}\)
=\(\dfrac{23}{23}+\dfrac{21}{21}+\dfrac{1}{2}\) = \(1+1+\dfrac{1}{2}\)
= \(2\dfrac{1}{2}\)
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E = \(\left(\frac{1}{57}-\frac{1}{5757}+\frac{1}{23}\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
E = \(\left(\frac{1}{57}-\frac{1}{5757}+\frac{1}{23}\right).0\)
E = 0
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a) A = 3² . 1/243 . 81² . 1/3²
= 3² . 1/3⁵ . (3⁴)² . 1/3²
= 3² . 1/3⁷ . 3⁸
= 3¹⁰ . 1/3⁷
= 3³
= 27
b) B = (4.2⁵) : (2³ . 1/6)
= (4.32) : (8 . 1/6)
= 128 : 4/3
= 96
c) C = (-1/3)³.(-1/3)².(-1/3)
= (-1/3)³⁺²⁺¹
= (-1/3)⁶
= 1/729
d) D = (-1/3)⁻¹ - (-6/7)⁰ + (1/2)² : 2
= -3 - 1 + 1/4 : 2
= -4 + 1/8
= -31/8
\(\dfrac{1}{2}-\left(-\dfrac{1}{3}\right)+\dfrac{1}{23}+\dfrac{1}{6}=\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{23}+\dfrac{1}{6}=\dfrac{5}{6}+\dfrac{1}{6}+\dfrac{1}{23}=1+\dfrac{1}{23}=\dfrac{24}{23}\)
\(\dfrac{1}{2}-\left(\dfrac{-1}{3}\right)+\dfrac{1}{23}+\dfrac{1}{6}\\ =\dfrac{3}{6}+\dfrac{2}{6}+\dfrac{1}{6}+\dfrac{1}{23}\\ =\left(\dfrac{3}{6}+\dfrac{2}{6}+\dfrac{1}{6}\right)+\dfrac{1}{23}\\ =1+\dfrac{1}{23}\\ =\dfrac{24}{23}\)