Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
(Vẫn rút gọn hở ?)
4. \(\frac{64^3.36^2}{16^4.18^5}=\frac{\left(2^6\right)^3.\left(2^2.3^2\right)^2}{\left(2^4\right)^4.\left(2.3^2\right)^5}=\frac{2^{18}.\left(2^2\right)^2.\left(3^2\right)^2}{2^{16}.2^5.\left(3^2\right)^5}\)
\(=\frac{2^{18}.2^4.3^4}{2^{16}.2^5.3^{10}}=\frac{2^{22}.3^4}{2^{21}.3^{10}}=\frac{2}{3^6}\)
5. \(\frac{34^{18}.68^{24}}{17^{30}.2^{16}}=\frac{\left(2.17\right)^{18}.\left(2^2.17\right)^{24}}{17^{30}.2^{16}}=\frac{2^{18}.17^{18}.\left(2^2\right)^{24}.17^{24}}{17^{30}.2^{16}}\)
\(=\frac{2^{18}.17^{18}.2^{48}.17^{24}}{17^{30}.2^{16}}=\) \(\frac{2^{66}.17^{42}}{17^{30}.2^{16}}=2^{50}.17^{12}\)
\(A=\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}+\frac{1}{256}+\frac{1}{512}\)
\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+....+\frac{1}{256}-\frac{1}{512}\)
\(=\frac{1}{2}-\frac{1}{512}\)
\(=\frac{255}{512}\)
Vậy \(A=\frac{255}{512}\)
A=14 +18 +116 +132 +164 +1128 +1256 +1512
=12 −14 +14 −18 +....+1256 −1512
=12 −1512
=255512
Vậy A=255512
Phạm Long Khánh
a)1.2.3.4...9-1.2.3.4...8-1.2.3.4...8.8
=1.2.3.4...8(9-1-8)
=1.2.3.4...8.0
=0
b)(3.4.216)2/11.123.411-169=(3.22.216)2/11.213.222-236=32.24.232/11.235-236=32.226/235.(11-2)
=32.236/235.9=32.236/235.32=2
c)70.(131313/565656+131313/727272+131313/909090
=70.(13/56+13/72+13/90)
=70.39/70=39
d)1/4.9+1/9.14+1/14.19+...+1/64.69
=4/4.9.4+4/9.4.14+4/14.19.4+...+4/64.69.4.
=1/4.(4/4.9+4/9.14+4/14.19+...+4/64.69)
=1/4.(1/4-1/9+1/9-1/14+1/14-1/19+...+1/64-1/69)
=1/4.(1/4-1/69)
=1/4.65/276=65/1104
~~~~~~~~Chúc bạn học giỏi nhé !~~~~~~~~
\(\frac{\frac{1}{3}+\frac{1}{7}-\frac{1}{13}}{\frac{2}{3}+\frac{4}{14}-\frac{2}{13}}\times\frac{\frac{3}{4}-\frac{3}{16}+\frac{3}{64}-\frac{3}{256}}{1-\frac{1}{4}+\frac{1}{16}-\frac{1}{64}}+\frac{5}{8}\)
\(=\frac{\frac{2}{6}+\frac{2}{14}-\frac{2}{26}}{\frac{4}{6}+\frac{4}{14}-\frac{4}{26}}\times\frac{\frac{3}{4}-\frac{3}{16}+\frac{3}{64}-\frac{3}{356}}{\frac{4}{4}-\frac{4}{16}+\frac{4}{64}-\frac{4}{256}}+\frac{5}{8}\)
\(=\frac{2\left(\frac{1}{6}+\frac{1}{14}-\frac{1}{26}\right)}{4\left(\frac{1}{6}+\frac{1}{14}-\frac{1}{26}\right)}\times\frac{3\left(\frac{1}{4}-\frac{1}{16}+\frac{1}{64}-\frac{1}{356}\right)}{4\left(\frac{1}{4}-\frac{1}{16}+\frac{1}{64}-\frac{1}{256}\right)}+\frac{5}{8}\)
\(=\frac{2}{4}\times\frac{3}{4}+\frac{5}{8}\)
\(=\frac{1}{2}\times\frac{3}{4}+\frac{5}{8}\)
\(=\frac{3}{8}+\frac{5}{8}\)
\(=\frac{8}{8}=1\)
\(\frac{\frac{109}{3.7.13}}{\frac{361}{3.14.13}}\)\(\frac{\frac{153}{256}}{\frac{51}{64}}\)+5/8
=\(\frac{327}{722}\)+5/8
=\(\frac{3113}{2888}\)
a)\(\frac{32}{64}-\frac{16}{64}+\frac{8}{64}-\frac{4}{64}+\frac{2}{64}-\frac{1}{64}\le\frac{1}{3}\)
\(\Rightarrow\frac{32-16+8-4+2-1}{64}=\frac{23}{64}\)\
\(\Rightarrow\frac{23}{64}=0,359375;\frac{1}{3}=0,33333...\)
đề sao lạ vậy
Gọi \(A=\frac{1}{2}-\frac{1}{4}+\frac{1}{8}-\frac{1}{16}+\frac{1}{32}-\frac{1}{64}\)
\(\Rightarrow2A=1-\frac{1}{2}+\frac{1}{4}-\frac{1}{8}+\frac{1}{16}-\frac{1}{32}\)
=> 2A - A = \(1-\frac{1}{2}+\frac{1}{4}-\frac{1}{8}+\frac{1}{16}-\frac{1}{32}-\frac{1}{2}+\frac{1}{4}-\frac{1}{8}+\frac{1}{16}-\frac{1}{32}+\frac{1}{64}\)
\(\Rightarrow A=1+\frac{1}{64}=\frac{65}{64}\)
Đặt \(A=4+16+...+1048576\)
=>\(A=4+4^2+...+4^{10}\)
=>\(4A=4^2+4^3+...+4^{11}\)
=>\(4A-A=4^2+4^3+...+4^{11}-4-4^2-...-4^{10}\)
=>\(3A=4^{11}-4\)
=>\(A=\dfrac{4^{11}-4}{3}\)
\(A=4+16+64+...+1048576\)
vì số trước gấp 4 lần số sau nên:
\(A=4+4\cdot4+4\cdot4\cdot4+...+4\cdot4\cdot4\cdot4\cdot4\cdot4\cdot4\cdot4\cdot4\cdot4\)
cái đoạn này hơi dài dòng nên mk làm kiểu cấp 2 nha
\(4A=4^2+4^3+4^4+...+4^{11}\)
\(4A-A=4^2+4^3+4^4+...+4^{11}-4+4^2+4^3+...+4^{10}\)
\(3A=4^{11}-4\)
\(A=\dfrac{4^{11}-4}{3}\)
\(A=\dfrac{1048576\cdot2-4}{3}\)
\(A=\dfrac{4194300}{3}\)
\(A=1398100\)