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a ) - 24 + 13 + 6 +24
= [(-24) + 24 ] + 13 + 6
= 0 + 13 + 6
= 19
b) 28 + (-6) - 50 + 6
= 22 - 56
= - 34
c) - 27 + ( -789 ) + ( -73 ) +789
= [ (-789) + 789 ] + [ ( - 27 ) + ( -73) ]
= 0 + (-100)
= -100
d) (-23) + ( - 17 ) + 50 +(-10)
= [ ( -23 ) + ( -17 ) + ( -10) ] + 50
= ( -50 ) + 50
= 0
e) 1998+ (-72) + ( -1998 ) + 72
= [ 1998 + ( -1998 ) ] + [ (-72) + 72 ]
= 0 + 0
= 0
1) $(-35)\cdot18+28\cdot35$
$=35\cdot(-18)+28\cdot35$
$=35\cdot(-18+28)$
$=35\cdot10$
$=350$
2) $53\cdot29-47\cdot(-29)$
$=53\cdot29-47\cdot(-1)\cdot29$
$=53\cdot29+47\cdot29$
$=29\cdot(53+47)$
$=29\cdot100$
$=2900$
3) $125\cdot(-24)+24\cdot225$
$=(-125)\cdot24+24\cdot225$
$=24\cdot(-125+225)$
$=24\cdot100$
$=2400$
4) $26\cdot(-121)-121\cdot(-36)$
$=-121\cdot[26+(-36)]$
$=-121\cdot(26-36)$
$=-121\cdot(-10)$
$=121\cdot10$
$=1210$
5) $65\cdot(-25)+25\cdot(-23)$
$=-65\cdot25+25\cdot(-23)$
$=25\cdot(-65-23)$
$=25\cdot(-88)$
$=-2200$
6) $237\cdot(-26)+26\cdot137$
$=-237\cdot26+26\cdot137$
$=26\cdot(-237+137)$
$=26\cdot(-100)$
$=-2600$
7) $30\cdot(-125)+25\cdot30$
$=30\cdot(-125+25)$
$=30\cdot(-100)$
$=-3000$
8) $(-37)\cdot69+(-31)\cdot37$
$=37\cdot(-69)+37\cdot(-31)$
$=37\cdot(-69-31)$
$=37\cdot(-100)$
$=-3700$
9) $31\cdot72-31\cdot70-31\cdot2$
$=31\cdot(72-70-2)$
$=31\cdot(2-2)$
$=31\cdot0$
$=0$
10) $(-12)\cdot47+(-12)\cdot52+(-12)$
$=-12\cdot(47+52+1)$
$=-12\cdot100$
$=-1200$
$\text{#}Toru$
Lời giải:
a)
\(2006.2005^{2003}> 2005.2005^{2003}=2005^{1+2003}=2005^{2004}\)
Vậy \(2006.2005^{2003}> 2005^{2004}\)
b)
\(2005^{2004}+2005^{2003}=2005^{2003}(2005+1)=2005^{2003}.2006< 2006^{2003}.2006\)
hay \(2005^{2004}+2005^{2003}< 2006^{2004}\)
c) Thiếu đề
d)
\(72^{27}-72^{26}=72^{26}(72-1)=71.72^{26}\)
\(72^{28}-72^{27}=72^{27}(72-1)=71.72^{27}> 71.72^{26}\)
\(\Rightarrow 72^{28}-72^{27}> 72^{27}-72^{26}\)
45-58+(-45)+(+58)-3=45-58-45+58-3=(45-45)+(58-58)-3=-3
(-57)-(-12)+3-(-57)=-57+12+3+57=(-57+57)+12+3=15
-(-24)-(-30)+(-24)-30+8=24+30-24-30+8=(24-24)+(30-30)+8=8
-(-12)+(+19)-(+12)+8-19=12+19-12+8-19=(12-12)+(19-19)+8=8
47-(-53)+(-47)-(+53)=47+53-47-53=(47-47)+(53-53)=0
-(+28)+32-(-28)+(-34)=-28+32+28-34=(-28+28)-(34-32)=-2
15-(+72)+(-15)+(+72)=15-72-15+72=(15-15)+(72-72)=0
20-(+46)+(-25)-(-46)=20-46-25+46=(20-25)+(46-46)=-5
28-(-32)+(-28)-32+5=28+32-28-32+5=(28-28)+(32-32)+5=5
-75+(-49)+(+75)+49-12=-75-49+75+49-12=(-75+75)+(49-49)-12=-12
\(...=45-58-45+58-3=-3\)
\(...=-57+12+3+57=15\)
\(...=24+30-24-30+8=8\)
\(...=12+19-12+8-19=8\)
\(...=47+53-47-53=0\)
\(...=-28+32+28-34=-2\)
\(...=15-72-15+72=0\)
\(...=20-46-25+46=-5\)
\(=...28+32-28-32+5=5\)
\(...=-75-49+75+49-12=-12\)
a)=-50
b)=-33
c)=13
d)=46
e)=-33
f)=-54
g)=29
h)=-11
i)=-120
k)=-196
l)=-108
m)=100
a)=-50
b)=-33
c)=13
d)=46
e)=-33
f)=-54
g)=29
h)=-11
i)=-120
k)=-196
l)=-108
m)=100
a) \(96-7\left(x+1\right)=14^4:14^3\)
\(\Rightarrow96-7\left(x+1\right)=14^{4-3}\)
\(\Rightarrow96-7\left(x+1\right)=14\)
\(\Rightarrow7\left(x+1\right)=96-14\)
\(\Rightarrow7\left(x+1\right)=82\)
\(\Rightarrow x+1=\dfrac{82}{7}\)
\(\Rightarrow x=\dfrac{82}{7}-1\)
\(\Rightarrow x=\dfrac{75}{7}\)
b) \(\left(5x+3^4\right)\cdot2^4=2^6\cdot7^2\)
\(\Rightarrow5x\cdot2^4+3^4\cdot2^4=2^6\cdot7^2\)
\(\Rightarrow5x\cdot2^4+6^4=\left(2^3\cdot7\right)^2\)
\(\Rightarrow80x+1296=3136\)
\(\Rightarrow80x=1840\)
\(\Rightarrow x=\dfrac{1840}{80}\)
\(\Rightarrow x=23\)
a: =>96-7(x+1)=14
=>7(x+1)=82
=>x+1=82/7
=>x=75/7
b =>5x+81=2^2*7^2=196
=>5x=115
=>x=23
Bài 1:
\(\dfrac{-5}{18}=\dfrac{-20}{72};\dfrac{7}{-24}=\dfrac{-21}{72}.\)
\(\dfrac{-15}{-40}=\dfrac{3}{8}=\dfrac{9}{24};\dfrac{24}{-72}=\dfrac{-1}{3}=\dfrac{-8}{24}.\)
Bài 3:
a) \(\dfrac{2}{3}h=\dfrac{8}{12}h;\dfrac{3}{4}h=\dfrac{9}{12}h.\Rightarrow\dfrac{2}{3}h< \dfrac{3}{4}h.\)
b) \(\dfrac{4}{5}km/h=\dfrac{8}{10}km/h;\dfrac{9}{10}km/h.\Rightarrow\dfrac{4}{5}km/h< \dfrac{9}{10}km/h.\)
(-24). 72 - 72 . 26 - 50 .28
= 72. [(-24) - 26] - 50. 28
= 72. (-50) - 50. 28
= 72. (-50) + (-50). 28
= (-50). ( 72 + 28 )
= (-50). 100
= -5000
Chi tiết giúp mình nhé.Cảm ơn ạ