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10 tháng 8 2016
\(\left[5^3.\left(3x+2\right)\right]:13=5^5:\left(13^5:13^4\right)\)
\(\left[5^3\left(3x+2\right)\right]:13=5^5:13\)
\(\left[5^3\left(3x+2\right)\right]:13=\frac{3125}{13}\)
\(\left[5^3\left(3x+2\right)\right]=3125\)
\(3x+2=3125:5^3\)
\(3x+2=25\)
\(3x=25-2\)
\(3x=23\)
\(x=\frac{23}{3}\)
10 tháng 8 2016
\(5^3.\left(3x+2\right):13=5^5:\left(13^5:13^4\right)\)
\(5^3.\left(3x+2\right):13=3125:13\)
\(5^3.\left(3x+2\right):13=\frac{3125}{13}\)
125 . ( 3x + 2 ) : 13 =\(\frac{3125}{13}\)
125 . ( 3x + 2 ) =\(\frac{3125}{13}.\frac{13}{1}=3125\)
3x + 2 = 3125 : 125
3x + 2 = 25
3x = 25 -2
3x = 23
x = 23 : 3
x = \(\frac{23}{3}\)
HT
2
8 tháng 8 2016
\(\left[5^3\left(3x+2\right)\right]:13=5^5:\left(13^5:13^4\right)\)
\(\left[5^3\left(3x+2\right)\right]:13=5^5:13\)
\(5^3\left(3x+2\right)=5^5:13.13\)
\(5^3\left(3x+2\right)=5^5\)
\(3x+2=5^5:5^3\)
\(3x+2=25\)
\(3x=25-2\)
\(3x=23\)
\(\Rightarrow x=\frac{23}{3}\)
11 tháng 7 2019
\(\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)
\(=\frac{5}{9}.\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)\)
\(=\frac{5}{9}.\frac{13}{13}=\frac{5}{9}.1=\frac{5}{9}\)
_Vi hạ_
15 tháng 5 2015
ta có \(\frac{\frac{4}{5}-\frac{4}{11}+\frac{4}{13}}{\frac{9}{5}-\frac{9}{11}+\frac{9}{13}}+\frac{\frac{5}{7}+\frac{5}{11}-\frac{5}{13}}{\frac{9}{7}+\frac{9}{11}-\frac{9}{13}}\)
\(=\frac{4\left(\frac{1}{5}-\frac{1}{11}+\frac{1}{13}\right)}{9\left(\frac{1}{5}-\frac{1}{11}+\frac{1}{13}\right)}+\frac{5\left(\frac{1}{7}+\frac{1}{11}-\frac{1}{13}\right)}{9\left(\frac{1}{7}+\frac{1}{11}-\frac{1}{13}\right)}\)
\(=\frac{4}{9}+\frac{5}{9}=\frac{9}{9}=1\)
2 tháng 1 2017
Chọn câu D
-(-7) = 7
-|-5| = -5
Ta có : A. 7 ; -5 ; 4 ; 0 ; -13 ( loại )
B. -13 ; 0 ; 4 ; -5 ; 7 ( loại )
C. -13 ; -5 ; 0 ; 4 ; 7 ( loại )
D. 7 ; 4 ; 0 ; -5 ; -13 ( chọn )
7 tháng 8 2020
\(a,\frac{-1}{9}.\frac{15}{22}.\frac{-9}{25}\)
\(=\frac{-1.15.\left(-9\right)}{9.22.25}\)
\(=\frac{3}{110}\)
\(b,\frac{-2}{7}.\left(\frac{5}{13}-\frac{9}{15}\right)-\frac{2}{7}.\frac{8}{13}\)
\(=\frac{-2}{7}.\left(\frac{5}{13}+\frac{8}{13}-\frac{3}{5}\right)\)
\(=\frac{-2}{7}.\left(1-\frac{3}{5}\right)\)
\(=\frac{-2}{7}.\frac{2}{5}\)
\(=\frac{-4}{35}\)
\(c,\frac{3}{10}.\left(\frac{-4}{9}+\frac{2}{5}\right)-\frac{3}{10}.\left(\frac{5}{9}-\frac{3}{5}\right)\)
\(=\frac{3}{10}.\left[\left(\frac{-4}{9}+\frac{2}{5}\right)-\left(\frac{5}{9}-\frac{3}{5}\right)\right]\)
\(=\frac{3}{10}.\left(\frac{-4}{9}+\frac{2}{5}-\frac{5}{9}+\frac{3}{5}\right)\)
\(=\frac{3}{10}.\left[\left(\frac{-4}{9}-\frac{5}{9}\right)+\left(\frac{2}{5}+\frac{3}{5}\right)\right]\)
\(=\frac{3}{10}.\left(-1+1\right)\)
\(=\frac{3}{10}.0\)
\(=0\)
\(d,\frac{4}{11}-\frac{5}{13}+\frac{7}{11}-\frac{8}{13}\)
\(=\left(\frac{4}{11}+\frac{7}{11}\right)+\left(\frac{-5}{13}-\frac{8}{13}\right)\)
\(=1-1\)
\(=0\)
Học tốt
LK
2
HD
8 tháng 8 2017
\(a)\dfrac{5}{12}+\dfrac{5}{3}+\dfrac{2}{12}+\dfrac{2}{3}\)
\(=\left(\dfrac{5}{12}+\dfrac{2}{12}\right)+\left(\dfrac{5}{3}+\dfrac{2}{3}\right)\)
\(=\dfrac{7}{12}+\dfrac{7}{3}\)
\(=\dfrac{7}{12}+\dfrac{28}{12}\)
\(=\dfrac{35}{12}\)
\(b)\dfrac{5}{9}.\dfrac{7}{13}+\dfrac{5}{9}-\dfrac{5}{9}.\dfrac{3}{13}\)
\(=\dfrac{5}{9}.1.\dfrac{7}{13}+\dfrac{5}{9}-\dfrac{5}{9}.\dfrac{3}{13}\)
\(=\dfrac{5}{9}.\left(1+\dfrac{7}{13}-\dfrac{3}{13}\right)\)
\(=\dfrac{5}{9}.\dfrac{17}{13}\)
\(=\dfrac{85}{117}\)
\(-13-5+5\)
\(=-13+\left(-5+5\right)\)
\(=-13\)
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