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\(\left[5^3.\left(3x+2\right)\right]:13=5^5:\left(13^5:13^4\right)\)
\(\left[5^3\left(3x+2\right)\right]:13=5^5:13\)
\(\left[5^3\left(3x+2\right)\right]:13=\frac{3125}{13}\)
\(\left[5^3\left(3x+2\right)\right]=3125\)
\(3x+2=3125:5^3\)
\(3x+2=25\)
\(3x=25-2\)
\(3x=23\)
\(x=\frac{23}{3}\)
\(5^3.\left(3x+2\right):13=5^5:\left(13^5:13^4\right)\)
\(5^3.\left(3x+2\right):13=3125:13\)
\(5^3.\left(3x+2\right):13=\frac{3125}{13}\)
125 . ( 3x + 2 ) : 13 =\(\frac{3125}{13}\)
125 . ( 3x + 2 ) =\(\frac{3125}{13}.\frac{13}{1}=3125\)
3x + 2 = 3125 : 125
3x + 2 = 25
3x = 25 -2
3x = 23
x = 23 : 3
x = \(\frac{23}{3}\)
\(\left[5^3\left(3x+2\right)\right]:13=5^5:\left(13^5:13^4\right)\)
\(\left[5^3\left(3x+2\right)\right]:13=5^5:13\)
\(5^3\left(3x+2\right)=5^5:13.13\)
\(5^3\left(3x+2\right)=5^5\)
\(3x+2=5^5:5^3\)
\(3x+2=25\)
\(3x=25-2\)
\(3x=23\)
\(\Rightarrow x=\frac{23}{3}\)
ta có \(\frac{\frac{4}{5}-\frac{4}{11}+\frac{4}{13}}{\frac{9}{5}-\frac{9}{11}+\frac{9}{13}}+\frac{\frac{5}{7}+\frac{5}{11}-\frac{5}{13}}{\frac{9}{7}+\frac{9}{11}-\frac{9}{13}}\)
\(=\frac{4\left(\frac{1}{5}-\frac{1}{11}+\frac{1}{13}\right)}{9\left(\frac{1}{5}-\frac{1}{11}+\frac{1}{13}\right)}+\frac{5\left(\frac{1}{7}+\frac{1}{11}-\frac{1}{13}\right)}{9\left(\frac{1}{7}+\frac{1}{11}-\frac{1}{13}\right)}\)
\(=\frac{4}{9}+\frac{5}{9}=\frac{9}{9}=1\)
\(\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)
\(=\frac{5}{9}.\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)\)
\(=\frac{5}{9}.\frac{13}{13}=\frac{5}{9}.1=\frac{5}{9}\)
_Vi hạ_
\(\dfrac{5}{9}\times\dfrac{-7}{13}+\dfrac{5}{9}\times\dfrac{-9}{13}+\dfrac{5}{9}-\dfrac{3}{13}=-\dfrac{29}{39}\)
a: =-5/11-6/11+1=-11/11+1=0
b: =-13/17-13/21-4/17=-1-13/21=-34/21
b: \(=-\dfrac{5}{12}\cdot\dfrac{9}{20}\cdot\dfrac{7}{17}=\dfrac{-21}{272}\)
d: \(=\dfrac{13}{17}\left(-\dfrac{4}{5}-\dfrac{3}{4}\right)=\dfrac{13}{17}\cdot\dfrac{-31}{20}=\dfrac{-403}{340}\)
\(-13-5+5\)
\(=-13+\left(-5+5\right)\)
\(=-13\)
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