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a)\(\left(x-5\right)\left(x+5\right)=\left(x-2\right)\)
\(x^2-25-x+2=0\)
\(x^2-23-x=0\)
\(x.\left(x-1\right)=23\)
Bài này vô lý quá
b)\(\left(3-2x\right)^2-\left(x-5\right)\left(4x+3\right)=2\left(x+5\right)\)
\(9-12x+4x^2-4x^2-3x+20x+15=2x+10\)
\(5x+24=2x+10\)
\(5x+24-2x-10=0\)
\(3x-14=0\)
\(3x=14\)
\(x=\frac{14}{3}\)
Vậy \(x=\frac{14}{3}\)
c)\(\left(7-x\right)\left(2x-5\right)-\left(7-x\right)2x=3\left(-5+x\right)\)
\(\left(7-x\right)\left[\left(2x-5\right)-2x\right]=\left(-15\right)+3x\)
\(5x-35=\left(-15\right)+3x\)
\(5x-35+15+3x=0\)
\(8x-20=0\)
\(8x=20\)
\(x=\frac{5}{2}\)
Vậy \(x=\frac{5}{2}\)
a: \(\dfrac{1}{x-2}+3=\dfrac{3-x}{x-2}\)
=>1+3x-6=3-x
=>3x-5=3-x
=>4x=8
hay x=2(loại)
b: \(\Leftrightarrow8-x-8\left(x-7\right)=-26\)
=>8-x-8x+56=-26
=>-9x+64=-26
=>-9x=-90
hay x=10(nhận)
c: \(\dfrac{1}{x-2}+\dfrac{1}{x-3}=\dfrac{2}{x-1}\)
\(\Leftrightarrow\dfrac{x-3+x-2}{\left(x-2\right)\left(x-3\right)}=\dfrac{2}{x-1}\)
\(\Leftrightarrow\left(x-1\right)\left(2x-5\right)=2\left(x^2-5x+6\right)\)
\(\Leftrightarrow2x^2-5x-2x+5=2x^2-10x+12\)
=>-7x+10x=12-5
=>3x=7
hay x=7/3(nhận)
1/ 3(x - 4) - (8 - x) = 12 => 3x - 12 - 8 + x = 12 => 4x = 32 => x = 8
2/ 4(x - 5) - 3(x - 7) = -9 => 4x - 20 - 3x + 21 = -9 => x = -10
3/ 7(x - 3) -5(3 - x) = 11x - 5 => 7x - 21 - 15 + 5x = 11x - 5 => x = 31
4/ -5(2 - x) + 4(x - 3) = 10x => -10 + 5x + 4x - 12 = 10x => x = -22
1) 3.(x-4)-(8-x) = 12
=> 3x-12-8+x = 12
=> 4x - 20 = 12
=> 4x = 12 +20 = 32
=> x = 32: 4 = 8
2) 4.(x-5)-3(x-7) = -9
=> 4x-20-3x+21 = -9
=>x +1 = -9
=>x = -9-1= -10
3) 7.(x-3)-5(3-x) = 11x-5
=> 7x-21-15+5x = 11x -5
=> 12x - 36 = 11x -5
=> 12x-11x = -5+36
hay x = 31
4) -5.(2-x)+4.(x-3) = 10x
=> -10+5x+4x-12 = 10x
=> -22 + 9x = 10x
=> -22 = 10x -9x
hay x = -22
XONG
Câu 1 :
a, \(\frac{3\left(2x+1\right)}{4}-\frac{5x+3}{6}=\frac{2x-1}{3}-\frac{3-x}{4}\)
\(\Leftrightarrow\frac{6x+3}{4}+\frac{3-x}{4}=\frac{2x-1}{3}+\frac{5x+3}{6}\)
\(\Leftrightarrow\frac{5x+6}{4}=\frac{9x+1}{6}\Leftrightarrow\frac{30x+36}{24}=\frac{36x+4}{24}\)
Khử mẫu : \(30x+36=36x+4\Leftrightarrow-6x=-32\Leftrightarrow x=\frac{32}{6}=\frac{16}{3}\)
tương tự
\(\frac{19}{4}-\frac{2\left(3x-5\right)}{5}=\frac{3-2x}{10}-\frac{3x-1}{4}\)
\(< =>\frac{19.5}{20}-\frac{8\left(3x-5\right)}{20}=\frac{2\left(3-2x\right)}{20}-\frac{5\left(3x-1\right)}{20}\)
\(< =>95-24x+40=6-4x-15x+5\)
\(< =>-24x+135=-19x+11\)
\(< =>5x=135-11=124\)
\(< =>x=\frac{124}{5}\)
Bài 1
1.(x-3)(x+2)-x(x-7)=15
\(\Leftrightarrow x^2+2x-3x-6-x^2+7x=15\)
\(\Leftrightarrow-6+6x=15\)
\(\Leftrightarrow6x=15+6\) =21
\(\Rightarrow x=\dfrac{21}{6}=3,5\)
2.(x-5)(x+5)+x(3-x)=20
\(\Leftrightarrow x^2-25+3x-x^2=20\)
\(\Leftrightarrow-25+3x=20\)
\(\Leftrightarrow3x=20+25=45\)
\(\Rightarrow x=\dfrac{45}{3}=15\)
3.(x-7)2-x(2+x)=-7
\(\Leftrightarrow x^2-14x+49-2x-x^2=-7\)
\(\Leftrightarrow-16x+49=-7\)
\(\Leftrightarrow-16x=-7-49=-56\)
\(\Rightarrow x=\dfrac{-56}{-16}=\dfrac{7}{2}=3,5\)
Tiếp bài 1
4.(x-4)2-(x+4)(x-4)=-16
\(\Leftrightarrow x^2-8x+16-x^2-16=-16\)
\(\Leftrightarrow-8x=-16\)
\(\Rightarrow x=\dfrac{-16}{-8}=2\)
5.(x-5)(x+5)-x(2-3x)=4x2-7
\(\Leftrightarrow x^2-25-2x+3x^2=4x^2-7\)
\(\Leftrightarrow4x^2-25-2x+3x^2=4x^2-7\)
\(\Leftrightarrow4x^2-4x^2-2x=-7+25\)
\(\Leftrightarrow-2x=18\)
\(\Rightarrow x=\dfrac{18}{-2}=-9\)
một đòn bẫy dài một mét .đặt ở đâu để có thể dùng 3600n có thể nâng tảng đá nặng 120kg?
a, \(-\left(x+3\right)\left(x-4\right)+\left(x+1\right)\left(x-1\right)=10\)
\(\Rightarrow-\left(x^2-4x+3x-12\right)+x^2-1=10\)
\(\Rightarrow-x^2+x+12+x^2-1=10\)
\(\Rightarrow x=10+1-12\Rightarrow x=-1\)
b, \(\left(2x-1\right)\left(x-2\right)-\left(x+3\right)\left(2x-7\right)=3\)
\(\Rightarrow2x^2-4x-x+2-\left(2x^2-7x+6x-21\right)=3\)
\(\Rightarrow2x^2-5x+2-2x^2+x+21=3\)
\(\Rightarrow-4x=3-21-2\Rightarrow-4x=-20\)
\(\Rightarrow x=5\)
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(x-5)(x+7)-7x(x+3)
= x2x2 +2x-35 - 7x2x2 -21x
= -6x2x2 +-19x-35
2.
(x+5)(x-7)-(x-4)(x+3)
= x2x2 -2x -35 -(x2x2-x-12)
=-x-23
(x + 5)(x - 7) - (x - 5)(x + 3)
= (x^2 - 7x + 5x - 35)-(x^2 + 3x - 5x - 15)
= x^2 -2x - 35 - x^2 + 2x + 15
= - 20