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a)\(\left(\frac{3}{5}\right)^5.x=\left(\frac{3}{7}\right)^7\)
\(x=\left(\frac{3}{7}\right)^7\div\left(\frac{3}{7}\right)^5\)
\(x=\left(\frac{3}{7}\right)^2\)
\(x=\frac{9}{49}\)
Vậy...
b)\(\left(-\frac{1}{3}\right)^3.x=\left(\frac{1}{3}\right)^4\)
\(\left(-\frac{1}{3}\right)^3.x=\left(-\frac{1}{3}\right)^4\)
\(x=\left(-\frac{1}{3}\right)^4\div\left(\frac{-1}{3}\right)^3\)
\(x=-\frac{1}{3}\)
Vậy...
c)\(\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)
=>\(x-\frac{1}{2}=\frac{1}{3}\)
\(x=\frac{1}{3}+\frac{1}{2}\)
\(x=\frac{5}{6}\)
Vậy...
d)\(\left(x+\frac{1}{4}\right)^4=\left(\frac{2}{3}\right)^4\)
=>\(x+\frac{1}{4}=\frac{2}{3}\)
\(x=\frac{2}{3}-\frac{1}{4}\)
\(x=\frac{5}{12}\)
Vậy...
Phù, mãi mới xong, tk cho mk nha bn
a)\(\left(\frac{-1}{3}\right)^3\cdot x=\frac{1}{81}\) \(< =>\frac{-1}{27}x=\frac{1}{81}\)\(< =>x=\frac{-1}{3}\)
\(\frac{2^x}{3^x}=\frac{81}{16}\)
\(\left(\frac{2}{3}\right)^x=\frac{81}{16}\)
\(\left(\frac{2}{3}\right)^x=\left(\frac{2}{3}\right)^{-4}\)
\(\Rightarrow x=-4\)
\(\frac{16}{2^x}=2\Rightarrow16:2^x=2\)
\(\Rightarrow2^x=16:2=8\Rightarrow2^x=2^3\Rightarrow x=3\)
\(\frac{\left(-3\right)^x}{81}=-27\Rightarrow\left(-3\right)^x:81=-27\)
\(\Rightarrow\left(-3\right)^x=-27\cdot81=-2187\Rightarrow\left(-3\right)^x=\left(-3\right)^7\Rightarrow x=7\)
mk biết mỗi thế thôi. mong bạn thông cảm.
~CÁC BẠN GIÚP MK LÊN 200 ĐIỂM NHA. BẠN NÀO GIÚP THÌ MK K LẠI NHÉ.~
~THANKS~
\(\left(\frac{2}{3}\right)^x=\frac{16}{81}\)
\(\left(\frac{2}{3}\right)^x=\left(\frac{2}{3}\right)^4\)
\(\Rightarrow x=4\)
= 0,6 : 5/4 + 1/4 + 2/9 : 5/9 - 1/4
= 3/5 . 4/5 + 2/9 . 9/5
= 12/25 + 2/5
= 22/25
\(\left(-\frac{2}{3}\right)^{x-1}=\frac{16}{81}\)
\(\left(-\frac{2}{3}\right)^{x-1}=\frac{\left(-2\right)^4}{3^4}\)
\(\left(-\frac{2}{3}\right)^{x-1}=\left(-\frac{2}{3}\right)^4\)
x - 1 = 4
x = 4 + 1
x = 5
\(\left(x+3\right)^4-\frac{16}{81}=0\)
\(\left(x+3\right)^4=\frac{16}{81}\)
\(\left(x+3\right)^4=\left(\frac{\pm2}{3}\right)^4\)
\(\Rightarrow\orbr{\begin{cases}x+3=\frac{2}{3}\\x+3=\frac{-2}{3}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{-7}{3}\\x=\frac{-11}{3}\end{cases}}\)
Vậy....