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Lớp 6 rồi mà gà quá :v
Ta có:
10+20+30=(120:(x-6)+24)
=>(120:(x-6)+24)=60
=> 120:(x-6)=36
=> x-6=10/3
=> x=28/3
Ta có :
10 + 20 = 30 = [ 120 : ( x - 6 ) + 24 ]
Suy ra [ 120 : ( x - 6 ) + 24 ] = 60
Suy ra 120 : ( x - 6 ) = 36
Suy ra x - 6 = 10/3
Suy ra x = 28/3
\(\frac{4}{1.3}+\frac{16}{3.5}+\frac{36}{5.7}+...+\frac{324}{17.19}\)
\(=\frac{2^2}{1.3}+\frac{4^2}{3.5}+\frac{6^2}{5.7}+...+\frac{18^2}{17.19}\)
\(=2\left(\frac{2.1^2}{1.3}+\frac{2.2^2}{3.5}+\frac{2.3^2}{5.7}+...+\frac{2.9^2}{17.19}\right)\)
\(=2\left(\frac{1}{1}-\frac{1}{3}+\frac{2^2}{3}-\frac{2^2}{5}+\frac{3^2}{5}-\frac{3^2}{7}+...+\frac{9^2}{17}-\frac{9^2}{19}\right)\)
\(=2\left[1+\frac{2^2-1}{3}+\frac{3^2-2^2}{5}+...+\frac{9^2-8^2}{17}-\frac{9^2}{19}\right]\)
\(=2\left(1+1+1....+1-\frac{81}{19}\right)=2\left(9-\frac{81}{19}\right)=\frac{180}{19}\)
\(a.x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\)
\(\left(x+x+x+...+x\right)+\left(1+2+...+30\right)=1240\)
\(31x+465=1240\)
\(31x=775\)
\(x=25\)
\(b.\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=6550\)
\(\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=6550\)
\(100x+5050=6550\)
\(100x=1500\)
\(x=15\)
x+(x+1)+(x+2)+....+(x+30)=1240
<=> (x+x+x+....+x)+(1+2+3+...+30)=1240
<=> 31x+\(\frac{\left(30+1\right)\cdot30}{2}\)=1240
<=> 31x+465=1240
<=> 31x=775
<=> x=25
Vậy x=25
8)4(x-2)-2(x-1)=12
4x-8-(2x-2)=12
4x-8-2x+2=12
2x-8+2=12
2x=12-2+8
2x=18
x=18/2=9
9)6x-13-2-(x×5)=7
6x-5x=7+13+2
x=22
10)7(x-5)-3(x+5)=30
7x-35-(3x+15)=30
7x-35-3x-15=30
4x=30+35+15
4x=80
x=20
8)4(x-2)-2(x-1)=12
\(\Rightarrow4x-8-2x+2=12\)
\(\Rightarrow2x=18\)
\(=>x=9\)
9)6x-13-2-(x×5)=7
\(\Rightarrow6x-15-\left(x+5\right)=7\)
\(\Rightarrow6x-15-x-5=7\)
\(\Rightarrow5x=27\)
\(\Rightarrow x=\frac{27}{5}\)
10)7(x-5)-3(x+5)=30
\(\Rightarrow7x-35-3x-15=30\)
\(\Rightarrow4x=80\)
\(\Rightarrow x=20\)
x+30%x=-1,3
=> x.(30%+1)=-1,3
=> x.1,3 =-1,3
=> x =-1,3:1,3
=> x =-1
Chúc bạn học tốt :)) !!!!!!!!!!!!
\(x+30\%=-1,3\)
=>\(x+\frac{3}{10}=-1,3\)
=>\(x=-1,3-\frac{3}{10}=\frac{-13}{10}-\frac{3}{10}=\frac{-16}{10}=-1,6\)
Vậy x=-1,6