Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) \(x:\frac{1}{2}+\frac{3}{4}=1\frac{19}{20}\)
\(x:\frac{1}{2}+\frac{3}{4}=\frac{39}{20}\)
\(x:\frac{1}{2}=\frac{39}{20}-\frac{3}{4}\)
\(x:\frac{1}{2}=\frac{39}{20}-\frac{15}{20}\)
\(x:\frac{1}{2}=\frac{24}{20}\)
\(x=\frac{24}{20}.\frac{1}{2}\)
\(x=\frac{3}{5}\)
\(x:\frac{1}{2}+\frac{3}{4}=1\frac{19}{20}\)
\(x:\frac{1}{2}=1\frac{19}{20}-\frac{3}{4}\)
\(x:\frac{1}{2}=\frac{39}{20}-\frac{3}{4}\)
\(x:\frac{1}{2}=\frac{39}{20}-\frac{15}{20}\)
\(x:\frac{1}{2}=\frac{24}{20}\)
\(x=\frac{24}{20}\times\frac{1}{2}\)
\(x=\frac{24}{40}\)
\(x=\frac{3}{5}\)
a, x + \(\frac{1}{4}=\frac{5}{8}\)
x = \(\frac{5}{8}-\frac{1}{4}\)
x = \(\frac{5}{8}-\frac{2}{8}\)
x = \(\frac{3}{8}\)
b, x - \(\frac{1}{3}=\frac{1}{6}\)
x = \(\frac{1}{6}+\frac{1}{3}\)
x = \(\frac{1}{6}+\frac{2}{6}\)
x = \(\frac{3}{6}\)
x = \(\frac{1}{2}\)
c, \(Xx\frac{3}{5}=\frac{9}{10}\)
\(X=\frac{9}{10}:\frac{3}{5}\)
\(X=\frac{9}{10}x\frac{5}{3}\)
\(X=\frac{45}{30}\)
\(X=\frac{3}{2}\)
d, \(X:\frac{1}{6}=18\)
\(X=18x\frac{1}{6}\)
\(X=3\)
\(x+x.\frac{1}{3}+\frac{5}{18}=\frac{7}{6}\)
\(\Rightarrow x.\left(1+\frac{1}{3}\right)=\frac{7}{6}-\frac{5}{18}\)
\(\Rightarrow x.\frac{4}{3}=\frac{21-5}{18}=\frac{16}{18}=\frac{8}{9}\)
\(\Rightarrow x=\frac{8}{9}:\frac{4}{3}=\frac{2}{3}\)
Ủng hộ mk nha,chúc các bn học tốt!!!
a) 4 × (5 - x) = x
20 - 4x = x
x + 4x = 20
5x = 20
x = 20 : 5
x = 4
b) 1/2 (x - 14) = 2
x - 14 = 2 : 1/2
x - 14 = 4
x = 4 +14
x = 18
c) 18/13 + 3 × x = 3
3x = 3 - 18/13
3x = 21/13
x = 21/13 : 3
x = 7/13
d) đề khó hiểu
X + X x \(\dfrac{1}{3}\) + \(\dfrac{5}{18}\) = \(\dfrac{7}{6}\)
X x \(\dfrac{4}{3}\) = \(\dfrac{7}{6}-\dfrac{5}{18}\)
X x \(\dfrac{4}{3}\) = \(\dfrac{8}{9}\)
X = \(\dfrac{8}{9}:\dfrac{4}{3}=\dfrac{2}{3}\)
\(x\cdot\left(\dfrac{1}{3}+1\right)=\dfrac{21}{18}-\dfrac{5}{18}=\dfrac{16}{18}=\dfrac{8}{9}\)
\(x=\dfrac{8}{9}:\dfrac{4}{3}=\dfrac{8}{9}\cdot\dfrac{3}{4}=\dfrac{4\cdot2\cdot3}{3\cdot3\cdot4}=\dfrac{2}{3}\)
\(4,7\div0,25+5,3\times4\)
\(=18,8+21,2\)
\(=40\)
\(3\times\left(a-2\right)+150=240\)
\(3\times\left(a-2\right)=90\)
\(a-2=30\)
\(a=32\)
\(\dfrac{1}{9}+a+\dfrac{7}{12}=\dfrac{17}{18}\)
\(\dfrac{1}{9}+a=\dfrac{13}{36}\)
\(a=\dfrac{1}{4}\)
\(\left(\dfrac{1}{2}\times\dfrac{1}{3}+\dfrac{1}{3}\times\dfrac{1}{4}+\dfrac{1}{4}\times\dfrac{1}{5}+\dfrac{1}{5}\times\dfrac{1}{6}+\dfrac{1}{6}\times\dfrac{1}{7}+\dfrac{1}{7}\times\dfrac{1}{8}\right)\times a=\dfrac{9}{16}\)
\(\left(\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+\dfrac{1}{4\times5}+\dfrac{1}{5\times6}+\dfrac{1}{6\times7}+\dfrac{1}{7\times8}\right)\times a=\dfrac{9}{16}\)
\(\left(\dfrac{1}{2}-\dfrac{1}{8}\right)\times a=\dfrac{9}{16}\)
\(\dfrac{3}{8}\times a=\dfrac{9}{16}\)
\(a=\dfrac{3}{2}\)
\(x+x\times\frac{1}{3}+\frac{5}{18}=1\frac{1}{6}\)
\(x+x\times\frac{1}{3}+\frac{5}{18}=\frac{7}{6}\)
\(x+x\times\frac{1}{3}=\frac{7}{6}-\frac{5}{18}\)
\(x+x\times\frac{1}{3}=\frac{8}{9}\)
\(x\times1+x\times\frac{1}{3}=\frac{8}{9}\)
\(x\times\left(1+\frac{1}{3}\right)=\frac{8}{9}\)
\(x\times\frac{4}{3}=\frac{8}{9}\)
\(x=\frac{8}{9}:\frac{4}{3}\)
\(x=\frac{2}{3}\)
Vậy \(x=\frac{2}{3}\)
#Y/n
\(x+x\times\frac{1}{3}+\frac{5}{18}=1\frac{1}{6}\)
\(x+x\times\frac{1}{3}+\frac{5}{18}=\frac{7}{6}\)
\(x+x\times\frac{1}{3}=\frac{7}{6}-\frac{5}{18}\)
\(x+x\times\frac{1}{3}=\frac{21}{18}-\frac{5}{18}\)
\(x\left(1+\frac{1}{3}\right)=\frac{16}{18}\)
\(x\left(\frac{3}{3}+\frac{1}{3}\right)=\frac{8}{9}\)
\(\frac{4}{3}x=\frac{8}{9}\)
\(x=\frac{8}{9}\times\frac{3}{4}\)
\(x=\frac{2}{3}\)