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a: =>x+1/5-27/10=11/2
=>x-5/2=11/2
hay x=8
b: =>11/4+x-7/8=6
=>15/8+x=6
hay x=33/8

a, \(x-\frac{1}{5}-\frac{2}{7}=4\frac{1}{2}\)
\(\Leftrightarrow x-\frac{17}{35}=\frac{9}{2}\)
\(\Leftrightarrow x=\frac{9}{2}+\frac{17}{35}\)
\(\Leftrightarrow x=\frac{349}{70}\)
b, \(1\frac{3}{4}+x-\frac{7}{8}=5\)
\(\Leftrightarrow\frac{7}{4}+x-\frac{7}{8}=5\)
\(\Leftrightarrow\frac{7}{8}+x=5\)
\(\Leftrightarrow x=5-\frac{7}{8}\)
\(\Leftrightarrow x=\frac{33}{8}\)

1. a) = 0,08 _ b) = 9 giờ 39 phút
2. a) (19+35+46):3 = 30 _ b) (2,4+2,7+3,8):3=2.966

a) \(x+\frac{1}{5}-\frac{2}{7}=4\frac{1}{2}\)
=> \(x+\frac{1}{5}-\frac{2}{7}=\frac{9}{2}\)
=> \(x=\frac{9}{2}+\frac{2}{7}-\frac{1}{5}=\frac{321}{70}\)
b) \(1\frac{3}{4}+x-\frac{7}{8}=5\)
=> \(\frac{7}{4}+x-\frac{7}{8}=5\)
=> \(\frac{7}{4}+x=\frac{47}{8}\)
=> \(x=\frac{33}{8}\)
c) \(\frac{1}{2}-\frac{1}{3}\cdot x=\frac{3}{4}\)
=> \(\frac{1}{3}\cdot x=\frac{1}{2}-\frac{3}{4}=-\frac{1}{4}\)
=> \(x=\left(-\frac{1}{4}\right):\frac{1}{3}=\left(-\frac{1}{4}\right)\cdot3=-\frac{3}{4}\)

a) X x 3 và 1/3 = 3 và 1/3 :4 và 1/4
=> X x 10/3 = 10/3 : 17/4
=> X = 10/3 : 17/4 : 10/3
=> X = ( 10/3 : 10/3 ) ; 17/4
=> X = 1 : 17/4 = 4/17
Vậy X = 4/17
b) 5 và 2/3 : X = 3 và 2/3 - 2 và 1/2
=> 17/3 : X = 11/3 - 5/2
=> 17/3 : X = 7/6
=> X = 17/3 : 7/6 = 34/7
Vậy x = 34/7
c) X x 3,9 + X x 0.1 = 2,7
=> X x ( 3,9 + 0,1 ) = 2,7
=> X x 4 = 2,7
=> X = 2,7 : 4
=> X = 0,675
Vậy x = 0,675

X + 1/2 = 4 1/2 + 2,7 1 3/4 + X = 5 + 7/8
X + 1/2 = 7,2 1 3/4 + X = 5,875
X = 7,2 + 1/2 X = 5,875 - 1 3/4
X = 7,7 X = 4,125

\(x.2+x.\frac{1}{5}=1\frac{3}{5}\)
\(x=1\frac{3}{5}:\left(2+\frac{1}{5}\right)\)
\(x=\frac{8}{11}\)
Sai thì bỏ qua

\((2,5\cdot x+2017)\cdot2018=(7,5+2017)\cdot2018\)
\(\Rightarrow(2,5\cdot x+2017)\cdot2018=4085441\)
\(\Rightarrow2,5\cdot x+2017=2024,5\)
\(\Rightarrow2,5x=7,5\)
\(\Rightarrow x=7,5:2,5=3\)
\(3\frac{1}{5}+\frac{2}{5}\left[x+\frac{1}{3}\right]=\frac{21}{5}\)
\(\Rightarrow\frac{16}{5}+\frac{2}{5}\left[x+\frac{1}{3}\right]=\frac{21}{5}\)
\(\Rightarrow\frac{2}{5}\left[x+\frac{1}{3}\right]=\frac{21}{5}-\frac{16}{5}\)
\(\Rightarrow\frac{2}{5}\left[x+\frac{1}{3}\right]=1\)
\(\Rightarrow x+\frac{1}{3}=\frac{5}{2}\)
\(\Rightarrow x=\frac{13}{6}\)