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a) \(\frac{-2}{3}x+\frac{1}{5}=\frac{1}{10}\)
\(\Leftrightarrow\frac{-2}{3}x=\frac{1}{10}-\frac{1}{5}\)
\(\Leftrightarrow\frac{-2}{3}x=\frac{-1}{10}\)
\(\Leftrightarrow x=\frac{-1}{10}\div\frac{-2}{3}\)
\(\Leftrightarrow x=\frac{3}{20}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1) \(2x\cdot\left(x-3\right)-5=3x\left(2x-5\right)-4x^2+40\)
\(\Leftrightarrow2x^2-6x-5=6x^2-15x-4x^2+40\)
\(\Leftrightarrow2x^2-6x-5=2x^2-15x+40\)
\(\Leftrightarrow2x^2-6x-5-2x^2+15x-40=0\)
\(\Leftrightarrow9x-45=0\)
<=> x=5
2) x(2x-1)-5(-7)2=2x2-2x+5
<=> 2x2-x-5.49=2x2-2x+5
<=> 2x2-x-245-2x2+2x-5=0
<=> x-250=0
<=> x=250
3) |a-2|=10
\(\Leftrightarrow\orbr{\begin{cases}x-2=10\\x-2=-10\end{cases}\Leftrightarrow\orbr{\begin{cases}x=12\\x=-8\end{cases}}}\)
4) |x|=-5
=> Không tồn tại giá trị của x thỏa mãn vì |x| >=0 với mọi x thuộc Z
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1) -3-(-x) =5
=> -3 + x = 5
=> x = 5 - (-3)
=> x = 8
2)-9-(x-3)=12
=> x- 3 = (-9) - 12
=> x-3 =-21
=> x = (-21)+3
=> x = -18
3)-10-(x-5)=-5
x-5 = (-10) -(-5)
x-5 = -5
x = -5 +5
x = 0
4)210-(10-x) =110
10-x = 210 -110
10-x = 100
x = 10 -100
x = -90
5)4x-(2x-5)=21
=> 4x-2x + 5 =21
=> x(4-2) + 5 = 21
=> x.2 =21 - 5
=> x.2 = 16
=> x = 16:2
=> x = 8
6)14x-5=8x+10
7)15+5x =3x+30
8)2x-5=15-3x
9)2(3x+5)+3(x+1)=x+220
10)4.(x-2+5(x-3)=18
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\(5\left(7+48:x\right)=45\)
\(\Leftrightarrow\left(7+48x\right)=9\)
\(\Leftrightarrow4x=2\)
\(\Leftrightarrow x=2\)
________________
\(5^2x-3.2.5^2=5^2.3\)
\(\Leftrightarrow5x^2-3-2.5^2=75\)
\(\Leftrightarrow5x^2-3-50=75\)
\(\Leftrightarrow5x^2-3=125\)
\(\Leftrightarrow5x^2=128\)
\(\Leftrightarrow x^2=\frac{128}{5}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{128}{5}\\x=-\frac{128}{5}\end{cases}}\)
___________________
\(2+x:5=0\)
\(\Leftrightarrow x:5=-2\)
\(\Leftrightarrow x=-10\)
\(10+2x=16\)
\(\Leftrightarrow2x=6\)
\(\Leftrightarrow x=3\)
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|2x-1|=|x+3|
=> 2x-1=x+3 =>x=4
Hoặc 2x-1=-x-3 => x=-2/3
Vậy x thuộc { 4; -2/3}
A) \(\left|2x-1\right|=\left|x+3\right|\)
\(\Rightarrow\left[{}\begin{matrix}2x-1=x+3\\1-2x=x+3\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}2x-x=3+1\\-2x-x=3-1\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=4\\-3x=2\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=4\\x=-\dfrac{2}{3}\end{matrix}\right.\)
Vậy \(\left[{}\begin{matrix}x=4\\x=-\dfrac{2}{3}\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
-3x+(-9)+5x-5=-10
(-3x+5x)+(-9-5)=-10
-2x+(-14)=-10
-2x=-10-(-14)
-2x=24
x=24:(-2)
x=-12. chúc bạn học tối nha
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a: \(\Leftrightarrow x^{10}=1\)
=>x=1 hoặc x=-1
b: \(\Leftrightarrow x^{10}-x=0\)
\(\Leftrightarrow x\left(x^9-1\right)=0\)
=>x=0 hoặc x=1
c: \(\Leftrightarrow\left(2x-15\right)^3\cdot\left(2x-14\right)\left(2x-16\right)=0\)
hay \(x\in\left\{\dfrac{15}{2};7;8\right\}\)