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a) (x.7 +8):5=10
x.7 +8= 10.5=50
x.7= 50-8=42
x= 42:7=6
b) 280: (7+3.x)=4
7+3.x= 4.280= 1120
3.x= 1120-7 =1113
x= 1113: 3= 371
c) (x.5) .19:13= 57
(x.5). 19= 57.13= 741
x.5= 741: 19= 39
x= 39:5 =7,8
d) 6.(28-8).x = 72
20.x= 72:6= 12
x= 12: 20= 0,6
e) 4. (36-4.x)= 3,2
36-4.x= 32:4= 0,8
-4.x= 0,8- 36= -35,2
x= -35,2 : -4 = 8,8
f) (x-15).3 :12= 6
(x-15).3 = 6. 12= 72
x-15= 72: 3= 24
x= 24+ 15= 39
g) (x:4+ 6) . 7 = 70
x:4+6= 70:7= 10
x:4= 10-6= 4
x= 4.4 = 16
h) (x:2+50) :5= 12
x:2+ 50= 12.5= 60
x:2= 60-50= 10
x= 10.2=20
l) 5.(7+3.x)= 140
7+3.x= 140:5 = 28
3.x= 28-7 =21
x= 21: 3= 7
k cho mình nhe
\(\left[12\cdot15-x\right]\cdot\frac{1}{4}=120\cdot\frac{1}{4}\)
\(\Leftrightarrow\left[180-x\right]\cdot\frac{1}{4}=30\)
\(\Leftrightarrow180-x=30:\frac{1}{4}\)
\(\Leftrightarrow180-x=120\)
\(\Leftrightarrow x=60\)
( x - 25) x 17 = 34
=> x - 25 = 34 : 17
x - 25 = 2
=> x = 2 + 25
x = 27
145 + (150 - x) = 250
=> 150 - x = 250 - 145
150 - x = 105
=> x = 150 - 105
x = 45
(2x - 7) x 81 = 0
=> 2x - 7 = 0 : 81
2x - 7 = 0
=> 2x = 7
=> x = 7 : 2 = 3,5
x - 90 : 15 = 32
=> x - 6 = 32
=> x = 32 + 6
x = 38
520 - (x - 5) = 250 : 5
=> 520 - (x - 5) = 50
=> x - 5 = 520 - 50
x - 5 = 470
=> x = 470 + 5
x = 475
t i c k nhé!! 346457567684786896789
a ) \(\left(x-5\right).17=34\)
=> \(x-5=2\)
=> \(x=7\)
b ) \(145+\left(150-x\right)=250\)
=> \(150-x=105\)
=> \(x=150-105\)
=> \(x=45\)
c ) \(\left(2.x-7\right).81=0\)
=> \(2x-7=0\)
=> \(2x=7\)
=> \(x=\frac{7}{2}\)
d ) \(x-90:15=32\)
=> \(x-6=32\)
=> \(x=38\)
Mấy cái dấu chấm đó là nhân đó nhé
\(x:3\times48+x:4\times36=1500\)
\(x\times\frac{1}{3}\times48+x\times\frac{1}{4}\times36=1500\)
\(x\times16+x\times9=1500\)
\(x\times\left(16+9\right)=1500\)
\(x\times25=1500\)
\(x=1500:25\)
\(x=60\)
X + X x 2 + X x 3 + X x 4 = 20,06
X x 1 + X x 2 + X x 3 + X x 4 = 20,06
X x ( 1 + 2 + 3 + 4 ) = 20,06
X x 10 = 20,06
X = 20,06 : 10
X = 2,006
bạn tk mik nha
\(x\cdot5+\frac{3}{4}\cdot x=87,4\)
\(x\cdot\left[5+0,75\right]=87,4\)
\(x\cdot5,75=87,4\)
\(x=87,4:5,75\)
\(x=1,52\)
\(x.\dfrac{3}{4}=\dfrac{1}{5}.\dfrac{9}{8}\)
\(x.\dfrac{3}{4}=\dfrac{9}{40}\)
\(x=\dfrac{9}{40}:\dfrac{3}{4}\)
\(x=\dfrac{3}{10}\)
Vậy \(x=\dfrac{3}{10}\)
\(x\div3\times4,5+x\div4\times34=1500\)
\(x\div13,5+x\div136=1500\)
\(x\div\left(13,5+0,1\right)+x\div136=1500\)
\(x\div13,6+x\div136=1500\)
\(x\div\left(136\div13,6\right)=1500\)
\(x\div10=1500\)
\(\Rightarrow x=1500\div10=150\)
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