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a) 32.x+2=1342176728
32.x=134217728-2
32.x=134217726
x=134217726:32
x=4194303,938
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\(\frac{1}{2}\left(\frac{4}{9}-x\right)-\frac{3}{2}\left(16-x\right)+\frac{1}{2}\left(5x+10\right)=0\)
\(\Leftrightarrow\frac{2}{9}-\frac{1}{2}x-24+\frac{3}{2}x+\frac{5}{2}x+5=0\)
\(\Leftrightarrow-\frac{169}{9}=\frac{7}{2}x\Leftrightarrow x=-\frac{338}{63}\)
Sai thì thông cảm cho mk nha
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\(\left(\dfrac{x-2}{9}\right)^3=\left(\dfrac{2}{3}\right)^6\Rightarrow\left(\dfrac{x-2}{9}\right)^3=\left(\dfrac{2}{3}\right)^{2^3}\Rightarrow\left(\dfrac{x-2}{9}\right)^3=\left(\dfrac{4}{9}\right)^3\Rightarrow\dfrac{x-2}{9}=\dfrac{4}{9}\Rightarrow x-2=4\Rightarrow x=6\)
\(\left(\dfrac{x-2}{9}\right)^3=\left(\dfrac{2}{3}\right)^6\)
\(\Rightarrow\dfrac{\left(x-2\right)^3}{9^3}=\dfrac{2^6}{3^6}\)
\(\Rightarrow\dfrac{\left(x-2\right)^3}{9^3}=\dfrac{\left(2^2\right)^3}{\left(3^2\right)^3}\)
\(\Rightarrow\dfrac{x-2}{9}=\dfrac{2^2}{3^2}\)
\(\Rightarrow\dfrac{x-2}{9}=\dfrac{4}{9}\)
\(\Rightarrow x-2=4\)
\(x=4+2\)
\(x=6\)
Vậy:\(x=6\)
ý bn là:
\(\left(x\cdot\dfrac{2}{9}\right)=\dfrac{2}{3}\cdot6\) đúng ko ạ?
\(x\cdot\dfrac{2}{9}=\dfrac{2}{3}\cdot6\)
\(\Rightarrow x\cdot\dfrac{2}{9}=4\)
\(\Rightarrow x=4:\dfrac{2}{9}\)
\(\Rightarrow x=\dfrac{8}{9}\)
Vậy \(x=\dfrac{8}{9}\)