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\(-8.4+19=-32+19=-13\)
\(-11.3-28=-33-28=-61\)
\(4.\left(-15\right)-18=-60-18=-78\)
\(19-4.\left(-12\right)=19+48=67\)
\(-25.\left(-3\right)-54=75-54=21\)
\(-16-7.\left(-4\right)+24\div\left(-8\right)=-16+28-3=9\)
\(15\div\left(-3\right)+30-7.\left(-3\right)=-5+30+21=46\)
\(-48\div\left(-4\right)+15.\left(-5\right)=12-75=-63\)
\(-29+65\div\left(-5\right)+23=-29-13+23=-19\)
\(15\div\left(-5\right)-17-12.\left(-5\right)=-3-17+60=40\)
\(28.\left(-4\right)-17=-112-17=-129\)
\(-19-7.4=-19-28=-47\)
\(-14.\left(-2\right)-16=28-16=12\)
\(13.\left(-3\right)-65-4.\left(-6\right)=-39-65+24=-80\)
\(-24-8.\left(-6\right)+28=-24+48+28=52\)
Chúc bạn hok tốt!!! tỷ tỷ
a thì đặt 4 ra ngoài sau đó tự tính theo cách đã học
câu b tương tự
-8.4+19= -13
-11.3-28=-61
4.(-15)-18=-78
19-4.(-12)=67
-25.(-3)-54=21
-8.4+19=-32+19=-13
-11.3-28=-33-28=-61
4.(-15)-18=-60-18=-78
19-4.(-12)=19-(-48)=67
-25.(-3)-54=75-54=21
-16-7.(-4)+24:(-8)=-16+28-3=12-3=9
15:(-3)+30-7.(-3)=-5+30+21=25+21=46
-48:(-4)+12.(-5)=12-60=-48
-29+65:(-5)+23=-29-13+23=-19
15:(-5)-17-12.(-5)=-3-7+60=-10+60=50
28.(-4)-17=-112-17=-129
-19-7.4=-19-28=-47
-14.(-2)-16=28-16=12
13.(-3)-65-4.(-6)=-39-65+24=-104+24=-80
-24-8.(-6)+28=-24+48+28=24+28=52
\(\dfrac{7.4^5.3^{11}+2^{13}.9^5}{6^{10}+2^{12}.3^{10}}\) \(=\dfrac{7.\left(2^2\right)^5+2^{13}.\left(3^3\right)^5}{\left(2.3\right)^{10}+2^{12}.3^{10}}\) \(=\dfrac{7.2^{10}.3^{11}+2^{13}.3^{15}}{2^{10}.3^{10}+2^{12}.3^{10}}\)
\(=\dfrac{7.2^{10}.3^{10}.3+2^{10}.2^3.3^{10}.3^5}{2^{10}.3^{10}+2^{10}.2^2.3^{10}}\) \(=\dfrac{2^{10}.3^{10}\left(7.3+2^3.3^5\right)}{2^{10}.3^{10}\left(1+2^2\right)}\)
\(=\dfrac{7.3+2^3.3^5}{1+2^2}\) \(=\dfrac{21+8.243}{5}\) \(=\dfrac{1965}{5}=393\)
\(\dfrac{7.4^5.3^{11}+2^{13}.9^5}{6^{11}+2^{12}.3^{10}}\)=\(\dfrac{7.\left(2^2\right)^5.3^{11}+2^{13}.\left(3^2\right)^5}{\left(2.3\right)^{11}+2^{12}.3^{11}}\)=\(\dfrac{7.2^{10}.3^{11}+2^{13}.3^{10}}{2^{11}.3^{11}+2^{12}.3^{11}}\)
= \(\dfrac{3^{10}.\left(7.3.2^{10}+2^{13}\right)}{3^{11}.\left(2^{11}+2^{12}\right)}\)=\(\dfrac{3^{10}.\left(21.2^{10}+2^{13}\right)}{3^{11}.\left(2^{11}+2^{12}\right)}\)=\(\dfrac{21.2^{10}+2^{13}}{3.\left(2^{11}+2^{12}\right)}\)
\(\frac{7.4^5.3^{11}+2^{13}.9^5}{6^{10}+2^{12}.3^{10}}=\frac{7.\left(2^2\right)^5.3^{11}+2^{13}.\left(3^2\right)^5}{\left(2.3\right)^{10}+2^{12}.3^{10}}=\frac{7.2^{10}.3^{11}+2^{13}.3^{10}}{2^{10}.3^{10}+2^{12}.3^{10}}\)
\(=\frac{2^{10}.3^{10}.\left(7.3+2^3\right)}{2^{10}.3^{10}.\left(1+2^2\right)}=\frac{7.3+2^3}{1+2^2}=\frac{29}{5}\)
\(\Leftrightarrow x-12=7\cdot4=28\)
hay x=40