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(X + 1) + (X + 2) + (X + 3) + ..... + (X + 10) = 165
( X x 10 ) + ( 1 + 2 + 4 + ... + 10 ) = 165
( X x 10 ) + 45 = 165
X x 10 = 165 - 45
X x 10 = 120
X = 120 : 10
X = 12
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a ) ( 165 + 99 + 165 x 1 ) - ( 163 x 101 - 163 x 1 )
= ( 165 x ( 99 + 1 ) ) - ( 163 x ( 101 - 1 ) )
= 165 x 100 - 163 x 100
= 16500 - 16300
= 200
b ) 24 x 62 + 24 x 2 x 19
= 24 x 62 + 24 x 38
= 24 x ( 62 + 38 )
= 24 x 100
= 2400
=
a) ( 165 x 99 + 165 x 1 ) - ( 163 x 101 - 163 x 1 )
= 165 x ( 99 + 1 ) - 163 x ( 101 - 1 )
= 165 x 100 - 163 x 100
= 100 x ( 165 - 163 )
= 100 x 2
= 200
b) 24 x 62 + 24 x 2 x 19
= 24 x 62 + 24 x 38
= 24 x ( 62 + 38 )
= 24 x 100
= 2400
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a)\(3:\left(2x+1\right)=72-69\)
\(3:\left(2x+1\right)=3\)
\(2x+1=3:3\)
\(2x+1=1\)
\(2x=1-1\)
\(2x=0\)
\(x=0:2\)
\(x=0\)
các bài còn lại giống như câu a nha nếu ko biết thì comment lại minhf sẽ giải cho . Nhớ k cho mình nha
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a,\(\Rightarrow x:3=1,56+7,2\)
\(\Rightarrow x:3=8,76\)
\(\Rightarrow x=8,76\cdot3\)
\(\Rightarrow x=26,28\)
b,\(\Rightarrow x:6=1,248:4\)
\(\Rightarrow x:6=0,312\)
\(\Rightarrow x=0,312\cdot6\)
\(\Rightarrow x=1,872\)
c,(x+x+x+x+...+x)+(2+5+8+....+29)=165
10 số hạng 10 số hạng
\(\Rightarrow\)10x+(29+2)*10:2=165
\(\Rightarrow\)10x+155=165
\(\Rightarrow10x=165-155\)
\(\Rightarrow10x=10\)
\(\Rightarrow x=10:10\)
\(\Rightarrow x=1\)
Tìm x :
(x - 21*13) : 11 = 30
(627 - 56,5) : (x: 2) = 163
2/3 + 1/3 : x = 1
165 - (35 : x + 3) * 15 = 15
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a, ( x - 21 . 13 ) : 11 = 30
x - 273 = 30 . 11
x - 273 = 330
x = 330 + 273
x = 603
b, ( 627 - 56,5 ) : ( x : 2 ) = 163
570,5 : ( x : 2 ) = 163
x : 2 = 570,5 : 163
x : 2 = 3,5
x = 3,5 . 2
x = 7
c, 2/3 + 1/3 : x = 1
1/3 : x = 1 - 2/3
1/3 : x = 1/3
x = 1/3 : 1/3
x = 1
d, 165 - ( 35 : x + 3 ) . 15 = 15
165 - ( 35 : x + 3 ) = 15 : 15
165 - ( 35 : x + 3 ) = 1
35 : x + 3 = 165 - 1
35 : x + 3 = 164
35 : x = 164 - 3
35 : x = 161
x = 35 : 161
x = 5/23
Mk tính nhẩm nên chắc có chỗ sai nên bn cứ kiểm tra lại nha
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a)2012(x-9)=1-1
2012(x-9)=0
x-9=0:2012
x-9=0
x=0+9
x=9
b)15(3x+5)=165-45
15(3x+5)=120
3x+5=120:15
3x+5=8
3x=8-5
3x=3
x=3:3
x=1
1) 2012.[ x - 9 ] + 1 = 1
<=> 2012.[ x - 9 ] = <=> x - 9 = 0 : 2012 <=> x - 9 = 0 => x = 9
2) 165 - 15[ 3x + 5 ] = 5.9
<=>165 - 15[ 3x + 5 ] = 45 <=> 15[ 3x + 5 ] = 120 <=> 3x + 5 = 8 <=> 3x = 3 => x = 1
( x + 1 ) + ( x + 2 ) + ... + ( x + 10 ) = 165
10 * x + 55 = 165
10 * x = 165 - 55
10 * x = 110
=> x = 110 : 10
=> x = 11
Vậy x = 11
( x +1 ) + ( x + 2) +...+ (x +10) = 165
=> 10x + (1 + 2 + 3 + ... + 10) = 165
=> 10x + 55 = 165
=> 10x = 110
=> x = 11