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a)2.16.8.4.32
=2^1.2^4.2^3.2^2.2^5
=2^15
b)9.27.81.729
=3^2.3^3.3^4.3^6
=3^15
c)3^3.225.45
=3^3.45.5.45
=3^3.45^2.5
d)36.30.125
=6^2.6.5.5^3
=6^3.5^4
a. 2. 16 . 8 . 4 . 32
= 2 .2 .8 .8 .4 . 4 .8
= \(^{2^2}\). \(8^3\). \(^{4^2}\)
\(a,2.2^2.2^4.2^3=2^{10}\)
\(b,3^3.3^2.5^2.3^2.5=3^7.5^3\)
\(c,3^2.3^3.3^4=3^9\)
\(d,3^2.2^2.2.3.5.5^3=2^3.3^3.5^4\)
a)
2 . 4. 16.8
= 2 . 4 .4 . 4 . 2 . 4
= 22 . 44
b) 33 . 225 . 45
= 33 . 45 . 5 . 45
= 33. 452. 5
Ps :Mấy câu sao giống zậy!
^^ Cbht!!!
\(3^3.225.45=3^3.25.9.5.9=3^3.5^2.3^2.5.3^2=3^7.5^3\)
\(36.30.125=6^2.5.6.5^3=6^3.5^4\)
\(a.a^5:a^2=a^6:a^2=a^4\)
\(a^8:a^6.a^2=a^2.a^2=a^4\)
\(a^2+a^4:a^2=a^2+a^2=2.a^2\)
\(C=\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+...+\dfrac{1}{2^{2020}}\\ 2C=1+\dfrac{1}{2}+\dfrac{1}{2^2}+...+\dfrac{1}{2^{2019}}\\ 2C-C=\left(1+\dfrac{1}{2}+\dfrac{1}{2^2}+...+\dfrac{1}{2^{2019}}\right)-\left(\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+...+\dfrac{1}{2^{2020}}\right)\\ C=1-\dfrac{1}{2^{2020}}=\dfrac{2^{2020}-1}{2^{2020}}\)
Giải:
C=1/2 + 1/2^2 + 1/2^3 + ... + 1/2^2020
2C=1 + 1/2 + 1/2^2 + ... +1/2^2019
2C-C=(1+1/2+1/2^2+...+1/2^2019)-(1/2+1/2^2+1/2^3+...+1/2^2020)
C=1-1/2^2020
Chúc bạn học tốt!
`a) (243756000)/(-487512000)=243756000/(-2.243756000)=1/(-2)=(-1)/2`
`b) (3.16-3.14)/(-12)=(3.2)/(3.(-4))=2/(-4)=(-1)/2`
`c) (-8.4+8.3)/(8.6-8.4)=(-8)/(8.2)=(-1.8)/(2.8)=(-1)/2`
`d) (-15)/(-90)=(-15.1)/(-15.6)=1/6`
A = -(x - y - z) + (-z + y + x) - (x + y)
= -x + y + z - z + y + x - x - y
= (-x + x - x) + (y + y - y) + (z - z)
= -x + y
B = -(-a + b + c) + (b + c - 1)
= a - b - c + b + c - 1
= a + (-b + b) + (-c + c) - 1
= a - 1
A= -(x-y-z) + (- z + y + x) - (x + y)
A= -x + y - z - z + y + x - x- y
A= (-x + x - x) + (y - y + y) + (-z - z)
A= (-x) + y - 2z
B= -(- a + b + c) + (b+c-1)
B= a - b - c + b + c -1
B= a + (-b + b) + (-c + c) - 1
B= a -1.
a) `(-63)/72 = (-63:9)/(72:9)=(-7)/8`
b) `20/(-140) = (20:20)/(-140:20) = 1/(-7)=(-1)/7`
c) `(3.10)/(5.24) =(3.2.5)/(5.2 .3.4)=1/4`
d) `(6.5-6.2)/(6+3)=18/9=2`
a)2x2x2x2x2x2x2x2x2x2=2\(^{10}\)
b)
c) 3x3x3x3x3x3x3x3x3=3\(^9\)
d)