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#include <bits/stdc++.h>
using namespace std;
long long x,n,i,t,dem;
int main()
{
cin>>n;
dem=0;
t=0;
for (i=1; i<=n; i++)
{
cin>>x;
if (x%2==0 && x>10) t+=x;
if (x%2!=0 || x<100) dem++;
}
cout<<t<<" "<<dem;
return 0;
}
1:
uses crt;
const fi='ketqua.txt';
var f1:text;
st:string;
i,d:integer;
begin
clrscr;
assign(f1,fi); rewrite(f1);
write('Nhap xau:'); readln(st);
d:=length(st);
for i:=1 to d do
if st[i]=#32 then delete(st,i,1);
writeln(f1,st);
close(f1);
end.
2:
uses crt;
var a,b,c,d:integer;
{----------chuong-trinh-con-----------------------}
function min(x,y:integer):integer;
begin
if x<y then min:=x
else min:=y;
end;
{---------------chuong-trinh-chinh--------------------}
begin
clrscr;
write('a='); readln(a);
write('b='); readln(b);
write('c='); readln(c);
write('d='); readln(d);
writeln(min(a,min(b,min(c,d))));
readln;
end.
Tham khảo nhen
Program Tin_hoc;
var a: integer;
begin
write('Nhap a: '); readln(a);
if a=0 then write('a la so 0') else
if a mod 2=0 then write(a,' la so chan') else write(a,' la so le');
readln
end.
Tham khảo
Program Tin_hoc;
var a: integer;
begin
write('Nhap a: '); readln(a);
if a=0 then write('a la so 0') else
if a mod 2=0 then write(a,' la so chan') else write(a,' la so le');
readln
end.
Program HOC24;
var m,n,i: integer;
t1,t2: longint;
begin
write('Nhap m;n: '); readln(m,n);
t1:=1; t2:=1;
for i:=1 to n do t1:=t1*i;
for i:=m to n do t2:=t2*i;
writeln('T1=',t1);
write('T2=',t2);
readln
end.
Mình dùng C++ nên div = /; mod = % nha bn!
#include <bits/stdc++.h>
using namespace std;
int main() {
int a, S;
cin >> a;
S=0;
while(a>0)
{
S+=a%10, a=a/10;
}
cout << S << endl;
return 0;
}
Chúc bn học tốt!
uses crt;
var a:array[1..100]of integer;
n,i,k,dem,dem1:integer;
begin
clrscr;
write('Nhap n='); readln(n);
for i:=1 to n do
begin
write('A[',i,']='); readln(a[i]);
end;
write('Nhap k='); readln(k);
dem:=0;
dem1:=0;
for i:=1 to n do
begin
if a[i] mod 2=0 then inc(dem);
if a[i] mod k=0 then inc(dem1);
end;
writeln('So phan tu chan la: ',dem);
writeln('So phan tu chia het cho ',k,' la: ',dem1);
readln;
end.