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a (-7)^6
b (-4).(-4).(-4).(-5).(-5).(-5)
=[(-4).(-5)].[(-4).(-5)].[(-4).(-5)]
=20 .20 .20 =20^3
a) \(\left(-7\right).\left(-7\right).\left(-7\right).\left(-7\right).\left(-7\right).\left(-7\right)=\left(-7\right)^6\)
b) \(\left(-4\right).\left(-4\right).\left(-4\right).\left(-5\right).\left(-5\right).\left(-5\right)\\ =\left[\left(-4\right).\left(-5\right)\right].\left[\left(-4\right).\left(-5\right)\right].\left[\left(-4\right).\left(-5\right)\right]\\ =20.20.20=20^3\)
a: \(=\dfrac{3^3\cdot2^6}{3^{-4}\cdot2^6}=3^7\)
b: \(=\left(\dfrac{3}{7}\right)^5\cdot\left(\dfrac{3}{7}\right)\cdot\dfrac{5^6}{3^6}:\left(\dfrac{625}{343}\right)^2\)
\(=\dfrac{3^6}{7^6}\cdot\dfrac{5^6}{3^6}:\dfrac{5^8}{7^6}\)
\(=\dfrac{1}{5^2}\)
c: \(=5^{4+3}\cdot\left(\dfrac{5}{2}\right)^{-5}\cdot\dfrac{1}{25}\)
\(=5^5\cdot\left(\dfrac{2}{5}\right)^5=2^5\)
a) \(\left(-8\right).\left(-3\right)^3.\left(+125\right)\\ =\left(-2\right)^3.\left(-3\right)^3.\left(+5\right)^3\\ =\left[\left(-2\right).\left(-3\right).\left(+5\right)\right]^3\\ =30^3\)
b) \(27.\left(-2\right)^3.\left(-7\right).\left(+49\right)\\ =3^3.\left(-2\right)^3.\left(-7\right).\left(-7\right)^2\\ =\left[3.\left(-2\right)\right]^3.\left[\left(-7\right).\left(-7\right)^2\right]\\ =\left(-6\right)^3.\left(-7\right)^3\\ =\left[\left(-6\right).\left(-7\right)\right]^3\\ =42^3\)
1: \(\left(3x-\dfrac{1}{5}\right)^2=\left(-\dfrac{3}{25}\right)^2\)
=>3x-1/5=3/25 hoặc 3x-1/5=-3/25
=>3x=8/25 hoặc 3x=2/25
=>x=8/75 hoặc x=2/75
2: \(\left(2x-\dfrac{1}{3}\right)^2=\left(-\dfrac{2}{9}\right)^2\)
=>2x-1/3=2/9 hoặc 2x-1/3=-2/9
=>2x=5/9 hoặc 2x=1/9
=>x=5/18 hoặc x=1/18
\(a,\) \(\left(3^2\right)^3\) = \(3^{2.3}\) = \(3^6\)
\(\left(3^3\right)^2\) = \(3^{3.2}=3^6\)
\(\left(3^2\right)^5\) = \(3^{2.5}=3^{10}\)
\(9^8=\left(3^2\right)^8=3^{2.8}=3^{16}\)
b, \(\left(5^3\right)^2=5^{3.2}=5^6\)
\(\left(5^4\right)^3=5^{4.3}=5^{12}\)
\(\left(5^2\right)^4\) = \(5^{2.4}=5^8\)
\(25^5=\left(5^2\right)^5=5^{2.5}=5^{10}\)
1. A = (-2)(-3) - 5.|-5| + 125.\(\left(-\dfrac{1}{5}\right)^2\)
= 6 - 25 + 125.\(\dfrac{1}{25}\)
= -19 + 5
= -14
@Shine Anna
a: \(\left(\dfrac{4}{9}+\dfrac{1}{3}\right)^2=\dfrac{49}{81}\)
b: \(\left(\dfrac{1}{2}-\dfrac{3}{5}\right)^3=-\dfrac{1}{1000}\)
c: \(\left(-\dfrac{10}{3}\right)^5\cdot\left(-\dfrac{6}{4}\right)^4=-\dfrac{6250}{3}\)
d: \(\left(\dfrac{3}{4}\right)^3:\left(\dfrac{3}{4}\right)^2:\left(-\dfrac{3}{2}\right)^3=-\dfrac{2}{9}\)
a) Ta thấy: có 5 thừa số (-5) nên tích mang dấu "-" nên:
(-5).(-5).(-5).(-5).(-5) = -55
b) (-2).(-2).(-2).(-3).(-3).(-3)
= (-2).(-3).(-2).(-3).(-2).(-3)
=6.6.6 = 63
hoặc: ta thấy tích có 6 thừa số nguyên âm nên tích mang dấu "+"
(-2).(-2).(-2).(-3).(-3).(-3)
= 23.33