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\(25x^2y^4+30xy^2z+9z^2=\left(5xy^2\right)^2+2.5xy^2.3z+\left(3z\right)^2=\left(5xy^2+3z\right)^2\)
\(\frac{16}{9}x^2+4xyz^2+\frac{9}{4}y^2z^4=\left(\frac{4}{3}x\right)^2+2.\frac{4}{3}x.\frac{3}{2}yz^2+\left(\frac{3}{2}yz^2\right)^2=\left(\frac{4}{3}x+\frac{3}{2}yz^2\right)^2\)
\(\frac{9}{25}x^2+\frac{12}{35}xy+\frac{4}{49}y^2=\left(\frac{3}{5}x\right)^2+2.\frac{3}{5}x.\frac{2}{7}y+\left(\frac{2}{7}y\right)^2=\left(\frac{3}{5}x+\frac{2}{7}y\right)^2\)( tự thay vào tính nhé )
\(\frac{25}{16}u^4y^2+\frac{1}{5}u^2+y^3+\frac{4}{625}y^4=\left(\frac{5}{4}u^2y\right)^2+2.\frac{5}{4}u^2y.\frac{2}{25}.y^2+\left(\frac{2}{25}y^2\right)^2=\left(\frac{5}{4}u^2y+\frac{2}{25}y^2\right)^2\)( tự thay vào tính nhé )
Tham khảo nhé~
a: \(9x^2+30x+25=\left(3x+5\right)^2\)
b: \(\dfrac{4}{9}x^4-16x^2=x^2\left(\dfrac{4}{9}x^2-16\right)=x^2\left(\dfrac{2}{3}x-4\right)\left(\dfrac{2}{3}x+4\right)\)
c: \(\dfrac{12}{5}x^2y^2-9x^4-\dfrac{4}{25}y^4\)
\(=-\left(9x^4-\dfrac{12}{5}x^2y^2+\dfrac{4}{25}y^4\right)\)
\(=-\left(3x^2-\dfrac{2}{5}y^2\right)^2\)
\(\frac{12}{5}x^2y^2-9x^4-\frac{4}{25}y^4\)
\(=-\left(\frac{4}{25}y^4-\frac{12}{5}x^2y^2+9x^4\right)\)
\(=-\left[\left(\frac{2}{5}y^2\right)^2-2\cdot\frac{2}{5}y^2\cdot3x^2+\left(3x^2\right)^2\right]\)
\(=-\left(\frac{2}{5}y^2-3x^2\right)^2\)
\(\frac{12}{5}x^2y^2-9x^4-\frac{4}{25}y^4\)
\(=-\left(9x^4-\frac{12}{5}x^2y^2+\frac{4}{25}y^4\right)\)
\(=-\left[\left(3x\right)^2-2.3x^2.\frac{2}{5}y^2+\left(\frac{2}{5}y^2\right)^2\right]\)
\(=-\left(3x^2+\frac{2}{5}y^2\right)\)
a) 9x2+30x+25=32x2+2.3.5x+52=(3x+5)2
b)12/5x2y2-9x4-4/25y4=-(9x4-12/5x2y2+4/25y4)=-(3x-2/5y)2
c)a2y2+b2x22axby=(ax-by)2
d)64x2-(8a+b)2=(8x-8a-b)(8x+8a+b)
a) \(9x^2+6x+1=\left(3x+1\right)^2\)
b)\(x^2-x+\frac{1}{4}=\left(x-\frac{1}{2}\right)^2\)
c)\(x^2y^4-2xy^2+1=\left(xy^2-1\right)^2\)
d) \(x^2+\frac{2}{3}x+\frac{1}{9}=\left(x+\frac{1}{3}\right)^2\)
a) 9x2 + 6x + 1 = ( 3x + 1 )2
b) x2 - x + 1/4 = ( x - 1/2)2
c) x2 . y4 - 2xy2 + 1 = ( xy2 - 1 ) 2
d) x2 + 2/3x + 1/9 = (x+1/3)2
\(\left(x+\frac{4}{3}y^2\right)^2=x^2+\frac{8xy^2}{3}+\frac{16y^4}{9}\)
\(\left(2x^2+\frac{5}{3}y\right)^2=4x^4+\frac{20x^2y}{3}+\frac{25y^2}{9}\)
\(\left(x+\frac{4}{3}y^2\right)^2=x^2+2\cdot x\cdot\frac{4}{3}y^2+\left(\frac{4}{3}y^2\right)^2=x^2+\frac{8}{3}xy^2+\frac{16}{9}y^4\)
\(\left(2x^2+\frac{5}{3}y\right)^2=\left(2x^2\right)^2+2\cdot2x^2\cdot\frac{5}{3}y+\left(\frac{5}{3}y\right)^2=4x^4+\frac{20}{3}x^2y+\frac{25}{9}y^2\)
a) \(\left(5xy^3\right)^2-2.5xy^3.6yz^2+\left(6yz^2\right)^2\)=\(\left(5xy^3-6yz^2\right)^2\)
b) \(\left(\frac{1}{3}u^2v^3\right)^2-2.\frac{1}{3}u^2v^3.\frac{1}{2}u^3v+\left(\frac{1}{2}u^3v\right)^2\)=\(\left(\frac{1}{3}u^2v^3-\frac{1}{2}u^3v\right)^2\)
a) \(9x^2+6x+1=\left(3x\right)^2+2.3x.1+1^2=\left(3x+1\right)^2\)
b) \(x^2-x+\dfrac{1}{4}=x^2-2.\dfrac{1}{2}x+\left(\dfrac{1}{2}\right)^2=\left(x-0,5\right)^2\)
c) \(x^2y^4-2xy^2+1=\left(xy^2\right)^2-2.xy^2.1+1^2=\left(xy^2-1\right)^2\)
d) \(x^2+\dfrac{2}{3}x+\dfrac{1}{9}=x^2+2.x.\dfrac{1}{3}+\left(\dfrac{1}{3}\right)^2=\left(x+\dfrac{1}{3}\right)^2\)
a) \(9x^2+6x+1\)
\(=\left(3x\right)^2+2.3x.1+1^2\)
\(=\left(3x+1\right)^2\)
\(\frac{12}{5}x^2y^2-9x^4-\frac{4}{25}y^4\)
\(=-\left(9x^4-\frac{12}{5}x^2y^2+\frac{4}{25}y^4\right)\)
\(=-\left[\left(3x^2\right)^2-2.3x^2.\frac{2}{5}y^2+\left(\frac{2}{5}y^2\right)^2\right]\)
\(=-\left(3x^2-\frac{2}{5}y^2\right)^2.\)
Chúc bạn học tốt!