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tổng 2 số:
40 x 2 = 80
số thứ nhất:
80 : ( 2 + 3 ) x 2 = 32
số thứ hai:
80 - 32 = 48
* tự viết sơ đồ nhé *
nhầm là tổng của hai số bằng trung bình cộng của hai số .trung bình cộng của hai số là 40 tỉ số là 2 phần 3 tìm hai số đó
Ỏ chỗ nếu gấp số thứ hai lên 2 lần thì trung bình cộng hai số là 24 hình như phải là trung bình cộng của 3 số đúng không bạn? Bạn kiểm tra lại giúp mk xem đề bài có đúng ko nhé!
Gọi 3 số cần tìm lần lượt là a, b, c
Có trung bình cộng của 3 số là 18 => \(\dfrac{a+b+c}{3}=18\)
=> a + b + c = 18x3 = 54 (1)
Nếu gấp số thứ nhất lên 2 lần thì trung bình cộng ba số là 22
=> \(\dfrac{2xa+b+c}{3}=22\)
=> 2xa + b + c = 22x3 = 66 (2)
Lấy (2) - (1), ta được:
(2xa + b + c) - (a + b + c) = 66 - 54 = 12
=> a = 12
Nếu gấp số thứ hai lên 2 lần thì trung bình cộng ba số là 24
=> \(\dfrac{a+2xb+c}{3}=24\)
=> a + 2xb + c = 24x3 = 72 (3)
Lấy (3) - (1), ta được
(a + 2xb + c) - (a + b + c) = 72 - 54 = 16
=> b = 18
Có a + b + c = 54, a = 12; b = 18
=> 12 + 18 + c = 54
=> c = 54 - 12 - 18 = 24
Vậy 3 số cần tìm lần lượt là 12; 18; 24
Chúc bạn học tốt!!!
trung bình cộng của hai số là 61,hiệu của hai số là 12, tìm hai só đó .giúp mình bài này với các bạn
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Ba lần trung bình cộng của bốn số là:
\(106+54+14=174\)
Trung bình cộng của bốn số là:
\(174\div3=58\)
Số thứ tư là:
\(58+14=72\)
Lời giải:
Tổng hai số: $1000\times 2=2000$ (tấn)
Số lớn gấp 4 lần số bé. Tổng số phần bằng nhau:
$1+4=5$ (phần)
Số bé là: $2000:5\times 1=400$
Số lớn là: $2000-400=1600$
Tổng của hai số đó là : 45 x 2 = 90
Số bé là : 90 : ( 2 + 3 ) x 2 =36
Số lớn là : 90 - 36 = 54
Tổng của hai số là: 45 : 2 = 22,5
Tổng số phần bằng nhau là: 2 + 3 = 5 (phần)
Số lớn: (22,5 + 3) : 5 = 5,1
Số bé: 22,5 - 5,1 = 17,4
ĐS:..
Dạng toán tổng tỉ nhé.
Tick nha!! Tks
HT