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a.384:25:4=384:[25x4]=384:100=3.84
380:[38x2]=[380:38]x2=20
a)=384:(25*4)=384:100=3,84.
b)37/25:5/4:74/25=37/25*4/5*25/74=37*4*25/5*25*74=2/5.
c)380:(38*2)=(380:38):2=10:2=5.
d)6/11:4/3:5/11:4/3=6/11*3/4*11/5*3/4=6*3*11*3/11*4*5*4=27/40.
k nha
a)
4 x 64,3 x 2,5 = 64,3 x (2,5 x 4) = 64,3 x 10 = 643
b)
18,7 x 4,3 + 18,7 x 5,7 = 18,7(4,3 + 5,7) = 18,7 x 10 = 187
c)
25/141 x 17/11 - 25/141 x 6/11 = 25/141 x (17/11 - 6/11) = 25/141 x 11/11 = 25/141 x 1 = 25/141
d)
số số hạng trong dãy : 2006-1+1 =2006(số)
1+2+3+4+...+2006 = (2006+1)+(2005+2)+(2004+3)+....+(1003+1004)
số cặp có tổng bằng 2007 là : 2006 : 2 = 1003(cặp)
Vậy 1+2+3+4+.....+2006 = 1003 x 2007 = 2013021
\(\left(1-\frac{1}{4}\right)\left(1-\frac{1}{9}\right)\left(1-\frac{1}{16}\right)\left(1-\frac{1}{25}\right)...\left(1-\frac{1}{10000}\right)\)
\(=\frac{3}{4}\cdot\frac{8}{9}\cdot\frac{15}{16}\cdot\frac{24}{25}\cdot...\cdot\frac{9999}{10000}\)
\(=\frac{\left(1\cdot3\right)\left(2\cdot4\right)\left(3\cdot5\right)\left(4\cdot6\right)...\left(99\cdot101\right)}{\left(2\cdot2\right)\left(3\cdot3\right)\left(4\cdot4\right)\left(5\cdot5\right)...\left(100\cdot100\right)}\)
\(=\frac{\left(1\cdot2\cdot3\cdot4\cdot...\cdot99\right)\left(3\cdot4\cdot5\cdot6\cdot...\cdot101\right)}{\left(2\cdot3\cdot4\cdot5\cdot...\cdot100\right)\left(2\cdot3\cdot4\cdot5\cdot...\cdot100\right)}\)
\(=\frac{1\cdot101}{100\cdot2}\)
\(=\frac{101}{200}\)
a) \(\frac{37}{25}+\frac{11}{21}-\frac{12}{25}+\frac{10}{21}\)
= \(\left(\frac{37}{25}-\frac{12}{25}\right)+\left(\frac{11}{21}+\frac{10}{21}\right)\)
= 1 + 1
= 2
\(\frac{37}{25}+\frac{11}{21}-\frac{12}{25}+\frac{10}{21}\)
=\(\left(\frac{37}{25}-\frac{12}{25}\right)+\left(\frac{11}{21}+\frac{11}{21}\right)\)
= 1 + 1 = 2 .
167 : 25 : 4
= 6,68 : 4
= 1,67