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\(\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\)
\(=\frac{1}{2}+\frac{1}{8}+\frac{1}{32}\)
\(=\frac{5}{8}+\frac{1}{32}\)
\(=\frac{21}{32}\)
A=1/2+1/6+1/12+1/24+…+1/192+1/384
Giải
Ta có:
A x 2 =(1/2+1/6+1/12+1/24+…+1/192+1/384) x 2
A x 2 = 1 + 2/6 + 2/12 + 2/24 + ... + 2/192 + 2/384
Rút gọn ta được:
A x 2 = 1 + 1/3 + 1/6 + 1/12 + ... + 1/96 + 1/192
A x 2 - A = 1 + 1/3 + 1/6 + 1/12 + ... + 1/96 + 1/192 - (1/2+1/6+1/12+1/24+…+1/192+1/384)
A = 1 + 1/3 - 1/2 - 1/384
A = 5/6 - 1/384
A = 319/384
ĐS: 319/384
Đặt A=\(1-\frac{1}{3}-\frac{1}{6}-\frac{1}{12}-\frac{1}{24}\)
3A=\(3-1-\frac{1}{3}-\frac{1}{6}-\frac{1}{12}\)
3A+A=\(3-\frac{1}{24}\)
4A=\(\frac{71}{24}\)
A=\(\frac{71}{24}:4\)
A=\(\frac{71}{96}\)
= \(\frac{3}{8}\).
Đúng 100% luôn!
Ai tk cho mình mình tk lại.
\(\dfrac{3}{9}+\dfrac{9}{15}+\dfrac{16}{24}=\dfrac{1}{3}+\dfrac{9}{15}+\dfrac{2}{3}=\dfrac{5}{15}+\dfrac{9}{15}+\dfrac{10}{15}=\dfrac{24}{15}=\dfrac{8}{5}\)
\(\dfrac{4}{10}+\dfrac{12}{32}+\dfrac{9}{15}=\dfrac{2}{5}+\dfrac{3}{8}+\dfrac{3}{5}=\dfrac{2}{5}+\dfrac{3}{5}+\dfrac{3}{8}=\dfrac{5}{5}+\dfrac{3}{8}=1+\dfrac{3}{8}=1\dfrac{3}{8}=\dfrac{11}{8}\)
\(\dfrac{1}{6}+\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{18}=\dfrac{3}{18}+\dfrac{9}{18}+\dfrac{6}{18}+\dfrac{1}{18}=\dfrac{19}{18}\)
=3/8 nha bạn