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1 tháng 5 2019

\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{50}\right)\)

\(=\left(\frac{2}{2}-\frac{1}{2}\right)\left(\frac{3}{3}-\frac{1}{3}\right)\left(\frac{4}{4}-\frac{1}{4}\right)...\left(\frac{50}{50}-\frac{1}{50}\right)\)

\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}...\frac{49}{50}\)

\(=\frac{1}{50}\)

1 tháng 5 2019

\(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right).....\left(1-\frac{1}{50}\right)\)

\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.....\frac{49}{50}\)

\(=\frac{1}{50}\)

29 tháng 3 2023

\(S=\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{49.50}\)

\(S=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{49}-\dfrac{1}{50}\)

\(S=1-\dfrac{1}{50}\)

\(S=\dfrac{49}{50}\)

\(=\dfrac{1}{3}+\dfrac{1}{6}+...+\dfrac{1}{50\cdot\dfrac{49}{2}}\)

\(=\dfrac{1}{2\cdot\dfrac{3}{2}}+\dfrac{1}{3\cdot\dfrac{4}{2}}+...+\dfrac{1}{50\cdot\dfrac{49}{2}}\)

\(=\dfrac{2}{2\cdot3}+\dfrac{2}{3\cdot4}+...+\dfrac{2}{49\cdot50}\)

\(=2\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{49}-\dfrac{1}{50}\right)\)

=2*24/50=48/50=24/25

29 tháng 7 2015

Ax2=1x2/1x2x3+1x2/2x3x4+...+1x2/48x49x50

Ax2=1/1x2-1/2x3+1/2x3-1/3x4+...+1/48x49-1/49x50

Ax2=1/1x2-1/49x50

Ax2=1/2-1/2450

Ax2=1225/2450-1/2450

Ax2=1224/2450

A=1224/2450:2

A=1224/2450X1/2

A=1224/4900

A=306/1225

29 tháng 6 2017

Còn câu trả lời nào khác ko zậy !?!

   .....

13 tháng 4 2022

E=-1/3+1/3^2-1/3^3+1/3^4-...+1/3^50-1/3^51

3E=-1+1^2-1^3+1^4-1^5+...+1^50-1^51

3E=-1+1-1+1-1+...+1-1

3E=0

13 tháng 4 2022

mình thiếu

bổ sung:

E=0:3

E=0

12 tháng 7 2016

\(\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+4+...+50}\)

\(=\frac{1}{\left(1+2\right).2:2}+\frac{1}{\left(1+3\right).3:2}+\frac{1}{\left(1+4\right).4:2}+...+\frac{1}{\left(1+50\right).50:2}\)

\(=\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+...+\frac{2}{50.51}\)

\(=2.\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{50.51}\right)\)

\(=2.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{50}-\frac{1}{51}\right)\)

\(=2.\left(\frac{1}{2}-\frac{1}{51}\right)\)

\(=2.\frac{49}{102}=\frac{49}{51}\)

Ủng hộ mk nha ^_-