\(E=\frac{1}{10}+\frac{1}{40}+\frac{1}{88}+\frac{1}{1...">
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20 tháng 1 2019

E = 1/2*5 + 1/5*8 + 1/8*11 + ....... + 1/29*32

E = 1/2 - 1/5 +1/5 - 1/8 + 1/8 - 1/11 + ........+1/29 - 1/32

E = 1/2 - 1/32

E = 15/32

nếu đúng thì k mik với nha

\(1+\frac{1}{1+2}+\frac{1}{1+2+3}+....+\frac{1}{1+2+3+...+2015}\)

\(=\frac{2}{1.2}+\frac{1}{\frac{\left(1+2\right).2}{2}}+\frac{1}{\frac{\left(1+2+3\right).3}{2}}+.....+\frac{1}{\frac{\left(2015+1\right).2015}{2}}\)

\(=\frac{2}{1.2}+\frac{2}{2.3}+....+\frac{2}{2015.2016}\)

8 tháng 2 2020

dễ vãi cả đạn

8 tháng 8 2018

\(\frac{1}{3.8}+\frac{1}{8.13}+...+\frac{1}{2018.2023}\)

Ta có : \(\frac{1}{3.8}+\frac{1}{8.13}+...+\frac{1}{2018.2023}\)

         \(=\frac{1}{5}.\left(\frac{5}{3.8}+\frac{5}{8.13}+...+\frac{5}{2018.2023}\right)\)

         \(=\frac{1}{5}.\left(\frac{1}{3}-\frac{1}{8}+\frac{1}{8}-\frac{1}{13}+...+\frac{1}{2018}-\frac{1}{2023}\right)\)

         \(=\frac{1}{5}.\left(\frac{1}{3}-\frac{1}{2023}\right)\)

          \(=\frac{1}{5}.\frac{2020}{6069}=\frac{404}{6069}\)

8 tháng 8 2018

Tính : 

a) 1/3.8 + 1/8.13 + ... + 1/2018 . 2023 

= 1/5 . ( 5/3.8 + 5/8.13 + ... + 5/2018 . 2023 ) 

= 1/5 . ( 1/3 - 1/8 + 1/8 - 1/13 + ... + 1/2018 - 1/2023 ) 

= 1/5 . ( 1/3 - 1/2023 ) 

= 1/5 . ( 2023/6069 - 3/6069 ) 

= 1/5 . 2020/6069

= 404/6069

4 tháng 8 2018

a,427-98

=(427+2)-(98+2)

=429-100

=329

4 tháng 8 2018

\(a)\) \(427-98=329\)

\(b)\) \(2\cdot19\cdot15+3\cdot43\cdot10+62\cdot80\)

\(=\left(2\cdot15\right)\cdot19+\left(3\cdot10\right)\cdot43+62\cdot80\)

\(=30\cdot19+30\cdot43+62\cdot80\)

\(=30\cdot\left(19+43\right)+62\cdot80\)

\(=30\cdot62+62\cdot80\)

\(=62\cdot\left(30+80\right)\)

\(=62\cdot110=6820\)

\(c)\)  Đặt \(M=\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{243}+\frac{1}{729}\)

\(=\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+\frac{1}{3^5}+\frac{1}{3^6}\)

\(\Rightarrow3M=1+\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+\frac{1}{3^5}\)

\(\Rightarrow3M-M=\left(1+\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+\frac{1}{3^5}\right)-\left(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+\frac{1}{3^5}+\frac{1}{3^6}\right)\)

\(\Rightarrow2M=1-\frac{1}{3^6}\)

\(\Rightarrow M=\frac{728}{2\cdot729}=\frac{364}{729}\)

Vậy \(M=\frac{364}{729}\)

12 tháng 5 2018

(1/12+3 1/6-30,75).x -8 = (3/5+0,415+1/200):0,01

(1/12+19/6-123/4).x-8=(3/5+83/200+1/200):1/100

-55/2.x-8=51/50:1/100

-55/2.x-8=102

-55/2.x=102+8=110

x=110:-55/2=-4

13 tháng 5 2018

Bạn không làm được bài 2 phần A à?

27 tháng 5 2019

\(a,A=\frac{1}{25\cdot27}+\frac{1}{27\cdot29}+...+\frac{1}{73\cdot75}\)

\(A=\frac{1}{2}\left[\frac{2}{25\cdot27}+\frac{2}{27\cdot29}+...+\frac{2}{73\cdot75}\right]\)

\(A=\frac{1}{2}\left[\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+...+\frac{1}{73}-\frac{1}{75}\right]\)

\(A=\frac{1}{2}\left[\frac{1}{25}-\frac{1}{75}\right]=\frac{1}{2}\cdot\frac{2}{75}=\frac{1}{75}\)

\(b,B=\frac{1}{8\cdot11}+\frac{1}{11\cdot14}+\frac{1}{14\cdot17}+...+\frac{1}{197\cdot200}\)

\(3B=\frac{3}{8\cdot11}+\frac{3}{11\cdot14}+\frac{3}{14\cdot17}+...+\frac{3}{197\cdot200}\)

\(3B=\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+...+\frac{1}{197}-\frac{1}{200}\)

\(3B=\frac{1}{8}-\frac{1}{200}\)

\(3B=\frac{3}{25}\)

\(B=\frac{3}{25}:3=\frac{1}{25}\)

27 tháng 5 2019

#)Giải :

a, \(A=\frac{1}{25.27}+\frac{1}{27.29}+...+\frac{1}{73.75}\)

\(A=\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+...+\frac{1}{73}-\frac{1}{75}\)

\(A=\frac{1}{25}-\frac{1}{75}\)

\(A=\frac{2}{75}\)

b, \(B=\frac{1}{8.11}+\frac{1}{11.14}+\frac{1}{14.17}+...+\frac{1}{197.200}\)

\(B=\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{17}+...+\frac{1}{197}-\frac{1}{200}\)

\(B=\frac{1}{8}-\frac{1}{200}\)

\(B=\frac{3}{25}\)

            #~Will~be~Pens~#