Question

[Phạm Thu Huyền]

Tính tổng

a) \(\dfrac{2}{1.3}\)+ \(\dfrac{2}{3.5}\)+ \(\dfrac{2}{5.7}\)+......+\(\dfrac{2}{99.101}\)

b) \(\dfrac{2}{1.3}\)+ \(\dfrac{5}{3.5}\)+ \(\dfrac{5}{5.7}\)+.......+ \(\dfrac{5}{99.101}\)

Answer 1

[no no]

Trả lời

a)\(\dfrac{2}{1.3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+...\dfrac{2}{99.101}\)

=\(2.\left(\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+...+\dfrac{1}{99.101}\right)\)

=\(2.\left(\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{99}-\dfrac{1}{101}\right)\)

= \(2.\left(\dfrac{1}{1}-\dfrac{1}{101}\right)\)

=\(2.\dfrac{100}{101}\)

=\(\dfrac{200}{101}\)

Answer 2

[no no]

Hình như phần b bạn chép đề sai hay sao đấy