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125x . 5x+1 = 6252 . 5
125x . 5x . 5 = ( 54 )2 . 5
625x . 5 = 59
625x = 59 : 5
625x = 58
54x = 58
4x = 8
x = 2
49x+1 . 73 = 3432 . 49
( 72 )x+1 . 73 = ( 73 )2 . 72
72x+5 = 78
2x + 5 = 8
2x = 3
x = 3/2
\(\left(\frac{3}{7}+\frac{1}{2}\right)^2=\left(\frac{13}{14}\right)^2=\frac{169}{196}\)
\(\frac{5^4\cdot20^4}{25^5\cdot4^5}=\frac{5^4\cdot4^4\cdot5^4}{5^5\cdot5^5.4^5}=\frac{1}{100}\)
\(\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6=\left(\frac{3}{7}\right)^{21}:\left[\left(\frac{3}{7}\right)^2\right]^6=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{12}=\left(\frac{3}{7}\right)^9\)
\(3-\left(-\frac{6}{7}\right)^0+\left(\frac{1}{2}\right)^2:2\)
\(=3-1+\frac{1}{4}:2=3-1+\frac{1}{8}=\frac{17}{8}\)
Ta có : B = 550 - 549 + 548 - 547 + .... + 52 - 5 + 1
=> 5B = 551 - 550 + 549 - 548 + ... + 53 - 52 + 5
Khi đó 5B + B = (551 - 550 + 549 - 548 + ... + 53 - 52 + 5) + (550 - 549 + 548 - 547 + .... + 52 - 5 + 1)
=> 6B = 551 + 1
=> B = \(\frac{5^{51}+1}{6}\)
Vậy \(B=\frac{5^{51}+1}{6}\)
<=> 5B = 551 - 550 + 549 - ...... - 52 + 5
<=> 5B + B = 551 - 550 + 550 - 549 + 549 - ... + 5 - 5 + 1
<=> 6B = 551 + 1
<=> B = (551 + 1)/6
a.17 . 85 + 25 . 17 + 1200
=17.(85+25)+1200
=17.110+1200
=1870+1200
=3070
b.62 : 4 . 3 + 2 . 52
=36:4.3+2.25
=27+50
=77
c.5 . 42 - 18 : 32
=5.16-18:9
=80-2
=78
d.3 . 52 - 16 : 23 + 34 : 33
=3.25-16:8+3
=75-2+3
=76
e.220 - [ 32 . 33 - ( 12 - 70 ) 2]
=220-35+112
=220-243+121
=98
j. 49 . 73 + 49 . 51 - 49 . 24
=49.(73+51-24)
=49.100
=4900
Con bấm mỏi suốt đấy mấy má
nhầm
a) 17 . 85 + 25 . 17 + 1200
=(17.85+25.17)+1200
=17(85+25)+1200
=17.110+1200
=1870+1200
=3070
b) 62 : 4 . 3 + 2 . 52
=36:4.3+2.25
=9.3+50
=27+50
=77
c) 5 . 42 - 18 : 32
=5.16-18:9
=80-2
=78
d) 3 . 52 - 16 : 23 + 34 : 33
=3.25-24:23+3(4-3)
=75-2(4-3)+31
=75-21+3
=75-2+3
=76
e) 220 - [ 32 . 33 - ( 12 - 70 ) 2 ]
=220-[3(2+3)-(12-1)2]
=220-(35-112)
=220-(243-121)
=220-122
=98
j) 49 . 73 + 49 . 51 - 49 . 24
=49(73+51-24)
=49.100
=4900